A.200 ạ                                                      

Trả lời:   Câu A.200

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#Tử Thần

 tl 200 nha bạn

a) A = m x 2 + p x 2

= 50 x 2 + 20 x 2

= 100 + 40

= 140

B = ( m + n + p ) x 2

= ( 50 + 30 + 20 ) x 2

= 100 x 2

= 200

b) M = a - ( b + c ) 

= 2000 - ( 500 + 200 )

= 2000 - 700

= 1300

N = a - b - c

= 2000 - 500 - 200

= 1500 - 200

= 1300

a.     2x-3 < 6-x

<=> 2x+x < 6+3

<=>   3x   < 9

<=>    x    < 3

Vậy x thuộc tập hơp {x l x<3}

b. 

              m > n

<=>  (-4).m < (-4).n

<=> 30-4m < 30-4n

a) m x 2 + n x 2 + p x 2

= ( m + b + p ) x 2

= ( 2006 + 2007 + 2008 ) x 2 

= 6021 x 2

= 12042

b) m x 2 + n x 2 + p x 2

= ( m + n + p ) x 2

= 2009 x 2 

= 4018

Đúng 100%

Đúng 100%

Đúng 100%

a/ 

\(m\times2+n\times2+p\times2\)

\(=2006\times2+2007\times2+2008\times2\)

\(=2\left(2006+2007+2008\right)\)

\(=2\times6021\)

\(=12042\)

b/ 

\(m\times2+n\times2+p\times2\)

\(=2\left(m+n+p\right)\)

\(=2\times2009\)

\(=4018\)

ket qua la 4018

ai tot bung kl cho minh nhe

m x 2 + n x 2 + p x 2 biết:

a) m = 2006, n = 2007, p = 2008

2006 x 2 + 2007 x 2 + 2008 x 2

= (2006 + 2007 + 2008) x 2

=6021 x 2 = 12042

b) m + n + p = 2009

ta có: 

m x 2 + n x 2 + p x 2

= ( m + n + p) x 2

mà m + n + p = 2009

suy ra : 

m x 2 + n x 2 + p x 2 

= 2009 x 2 =4018

Bài 1 :

\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)

\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)

\(\Rightarrow M< N\)

Bài 3 :

a) \(t^2+5t-8\) khi \(t=2\)

\(=5^2+2.5-8\)

\(=25+10-8\)

\(=27\)

b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)

\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)

\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)

c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)

\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)

\(\left(1\right)=1^3=1\)

Bài 2 :

a) \(...=2^3\left(19-14\right)+1=8.5+1=41\)

b) \(...=100-\left[60:\left(5^2-15\right)\right]=100-\left[60:10\right]=100-6=94\)

c) \(...=160:\left[17+\left(9.5-\left(14+2^3\right)\right)\right]=160:\left[17+\left(45-22\right)\right]=160:\left[17+23\right]=160:40=4\)

d) \(...=798+100\left[16-2\left(25-22\right)\right]=798+100\left[16-2.3\right]=798+100.10=798+1000=1798\)

a) m x 2 + n x 2 + p x 2
 = (m + n + p) x 2
 = (2006 + 2007 + 2008) x 2
 = 6021 x 2
 = 12042
b) m x 2 + n x 2 + p x 2
 = (m + n + p) x 2
 = 2009 x 2
 = 4018

a)m x 2 + n x 2 + p x 2 = 2006 x2 +2007 x 2 +2008 x2 = 12042

b)m x 2 + nx2 + px2 = (m+n+p) x2 = 2009x2 = 4018

a=12042

b=4018

\(35\times m+35\times n+35\times p\)

\(=35\times\left(m+n+p\right)\)

Thay \(m=3;n=2;p=5\) vào biểu thức trên ta có:

\(35\times\left(3+2+5\right)=35\times10=350\)

35 x m + 35 x p + 35 x n

Thay số: ⇒ 35 x 3 + 35 x 5 + 35 x 2

= 35 x (3 + 5 + 2)

= 35 x 10

= 350