tim x, biet
a/ (72 -x)/7 = (x-70) /9
b/ (x-1)/(x+2) = (x-2)/(x+3)
Tim so nguyen x,y biet
a) (x+5) mu 2 + (2y - 8 ) mu 2 = 0
b)(x + 3).(2y - 1 ) = 5
a: \(\left(x+5\right)^2>=0\forall x\)
\(\left(2y-8\right)^2>=0\forall y\)
Do đó: \(\left(x+5\right)^2+\left(2y-8\right)^2>=0\forall x,y\)
Dấu '=' xảy ra khi \(\left\{{}\begin{matrix}x+5=0\\2y-8=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=-5\\y=4\end{matrix}\right.\)
b: \(\left(x+3\right)\left(2y-1\right)=5\)
=>\(\left(x+3\right)\left(2y-1\right)=1\cdot5=5\cdot1=\left(-1\right)\cdot\left(-5\right)=\left(-5\right)\cdot\left(-1\right)\)
=>\(\left(x+3;2y-1\right)\in\left\{\left(1;5\right);\left(5;1\right);\left(-1;-5\right);\left(-5;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(-2;3\right);\left(2;1\right);\left(-4;-2\right);\left(-8;0\right)\right\}\)
tim x biet 72-x/7=x-70/9
x*3/5+x*2/7=31/70
x*x-1/6=5/18
tim x
Tìm x biết :
a. x :0.16=9:x
b/ (72-x):7=(x-70):9
c. (X^2-1^2)+(x-y+3)^2=0
Bai 1 tim x
2/3 x -3/2 x=5/12
72-3/x+1/=9
7/9 : (2+3/4 x)+5/9=23/27
bài 1 tính
a, 24 x 66 - 24 + 36 x 24
b, 29 x 173 - 29 x 72 -29
c, 1+5+10+15+...+55+60
d, 1x2+2x3+3x4 +...+18x19+19x20
bài 2 tìm x
a,106- ( x+ 7) =9
b, 2 x ( x+ 4) + 5 =65
c, (16x x -32) x 45=0
d, x+4 x x = 100 : 5
bài 2 tìm x
a,106- ( x+ 7) =9
x+7 = 106 - 9
x+7 = 107
x= 107 - 7
x=100
b, 2 x ( x+ 4) + 5 =65
2 x (x+4) = 65 - 5
2 x (x+4) = 60
x+4 = 60:2
x+4= 30
x= 30 - 4
x=26
c, (16x x -32) x 45=0
16 x X - 32 = 0: 45
16 x X - 32 =0
16 x X = 0 + 32
16 x X = 32
X= 32:16
X=2
d, x+4 x x = 100 : 5
X + 4 x X = 20
(1+4) x X = 20
5 x X = 20
X= 20:5
X=4
Bài 1:
a, 24 x 66 - 24 + 36 x 24
= 24 x (66-1+36)
= 24 x 101
= 24 x 100 + 24
= 2400+24
=2424
b, 29 x 173 - 29 x 72 - 29
= 29 x (173 - 72 -1)
= 29 x 100
= 2900
c, 1+5+10+15+...+55+60
= (5+60) x 6 + 1 (có 6 cặp)
= 65 x 6 + 1
= 390 +1 =391
d, D= 1 x 2 + 2 x 3 + 3 x 4 +...+18 x 19 + 19 x 20
3D= 1 x 2 x 3+ 2 x 3 x (4-1) + 3 x 4 x (5-2) +...+ 18 x 19 x (20 - 17) + 19 x 20 x (21-18)
3D= 1 x 2 x 3 - 1 x 2 x 3 + 2 x 3 x 4 - 2 x 3 x 4 +.... + 19 x 20 x 21 - 18 x 19 x 20
3D= 19 x 20 x 21 =7980
=> D= 7980:3=2660
Tìm x biết :
a/ x:0,16=9:x
b/ (72-x) :7=(x-70):9
c/ (x2-1)2 + ( x-y+3)2 =0
a: =>x^2=1,44
=>x=1,2 hoặc x=-1,2
b: =>648-9x=7x-490
=>-16x=-1138
=>x=569/8
c: =>x^2-1=0 và x-y+3=0
=>x^2=1 và x-y=-3
=>(x,y)=(1;4) hoặc (x,y)=(-1;2)
1) tìm x
a) 2/5 . x + 1/3 = 1/5
b) 1/5 + 5/3 : x = 1/2
c) 4/9 - 5/3 . x = - 2
d) 5/7 : x - 3 = -2/7
2) Thực hiện các phép tính bằng hai cách ( mấy cái cách ở dưới là hỗn số)
a) 17 2/9 + 6 1/9
b) 34 15/37 + 3 12/37
c) 12 2/7 + 35 3/14
d) 28 9/5 + 22 7/10
e) 74 2/8 - 17 1/8
f) 36 7/4 - 16 1/2
g) 64 2/15 - 36 5/3
h) 75 1/8 - 29 5/16
3) Thực hiện các phép tính sau ( mấy cái cách ở dưới là hỗn số)
a) 2 3/4 . 3 6/5
b) 4 3/8 . 2 4/7
c) 4 3/8 . ( - 2 4/7 )
d) 6 7/8 : ( - 2 8/9 )
e) ( - 6 1/2 ) . ( -3 1/5 )
f) ( - 4 2/9 ) . ( - 5 1/2 )
g) 7 1/3 . 2
h) 3 6/5 : 2
1) tìm x
a) 2/5 . x + 1/3 = 1/5
b) 1/5 + 5/3 : x = 1/2
c) 4/9 - 5/3 . x = - 2
d) 5/7 : x - 3 = -2/7
2) Thực hiện các phép tính bằng hai cách ( mấy cái cách ở dưới là hỗn số)
a) 17 2/9 + 6 1/9
b) 34 15/37 + 3 12/37
c) 12 2/7 + 35 3/14
d) 28 9/5 + 22 7/10
e) 74 2/8 - 17 1/8
f) 36 7/4 - 16 1/2
g) 64 2/15 - 36 5/3
h) 75 1/8 - 29 5/16
3) Thực hiện các phép tính sau ( mấy cái cách ở dưới là hỗn số)
a) 2 3/4 . 3 6/5
b) 4 3/8 . 2 4/7
c) 4 3/8 . ( - 2 4/7 )
d) 6 7/8 : ( - 2 8/9 )
e) ( - 6 1/2 ) . ( -3 1/5 )
f) ( - 4 2/9 ) . ( - 5 1/2 )
g) 7 1/3 . 2
h) 3 6/5 : 2
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)