\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)

\(=\frac{2^8.2^2.81}{2^8.104}\)

\(=\frac{2^8.4.81}{2^8.104}\)

\(=\frac{2^8.324}{2^8.104}\)

\(=\frac{324}{104}\)

\(=\frac{81}{26}\)

\(\frac{2^{10}×13+2^{10}×65}{2^8×104}\)

\(=\frac{2^{10}×\left(13+65\right)}{2^8×104}\)

\(=\frac{2^8×2^2×81}{2^8×104}\)

\(=\frac{2^2×81}{104}\)

\(=\frac{324}{104}\)

\(=\frac{81}{26}\)

Làm cách này nhanh hơn nhé , bạn Xyz

thank bn nhưng 13+65 = 78 mà bn

chịu

Chịu 

Ta có:

65 × 111 - 13 × 15 × 37

= 5 × 13 × 3 × 37 - 13 × 3 × 5 × 37

= 0

Vì 0 nhân với bất kì số nào cũng = 0 nên biểu thức trên = 0

\(\left(1+2+3+...+100\right).\left(1^2+2^2+3^2+...+10^2\right).\left(65.111-13.15.37\right)\)

\(\left(1+2+3+...100\right).\left(1^2+2^2+3^2+...+10^2\right).\left(13.5.111-13.15.37\right)\)

\(\left(1+2+3+...+100\right).\left(1^2+2^2+3^2+...+10^2\right).\left(13.15.37-13.15.37\right)\)

\(=0\)

= 0

mik mới khôi phục đc điểm âm mà giờ lại bị trừ tiếp, các bạn giúp mik nha, mik sẽ giúp lại 100%

cảm mơn các bạn trc

a) \(\dfrac{10^{12}+5^{11}.2^9-5^{13}.2^8}{4.5^5.10^6}\)

\(=\dfrac{2^{12}.5^{12}+5^{11}.2^9-5^{13}.2^8}{2^2.5^5.2^6.5^6}\)

\(=\dfrac{2^{12}.5^{12}+5^{11}.2^9-5^{13}.2^8}{2^8.5^{11}}\)

\(=\dfrac{\left(2^8.5^{11}\right)\left(2^4.5+2-5^2\right)}{2^8.5^{11}}\)

\(=2^4.5+2-5^2\)

\(=57\)

b) \(\dfrac{\left[5\left(x-y\right)^4-3\left(x-y\right)^3+4\left(x-y\right)^2\right]}{\left(y-x\right)^2}\)

\(=\dfrac{\left(x-y\right)^2\left[5\left(x-y\right)^2-3\left(x-y\right)+4\right]}{\left(y-x\right)^2}\)

\(=\dfrac{\left(x^2+y^2-2xy\right)\left[5\left(x-y\right)^2-3\left(x-y\right)+4\right]}{\left(y^2+x^2-2xy\right)}\)

\(=5\left(x-y\right)^2-3\left(x-y\right)+4\)

c) \(\dfrac{\left(x+y\right)^5-2\left(x+y\right)^4+3\left(x+y\right)^3}{-5\left(x+y\right)^3}\)

\(=\dfrac{\left(x+y\right)^3\left[5\left(x+y\right)^2-2\left(x+y\right)+3\right]}{-5\left(x+y\right)^3}\)

\(=\dfrac{5\left(x+y\right)^2-2\left(x+y\right)+3}{-5}\)