Bài 1:
a)S2=10+12+14+...+2010
b)S4=1+4+7+...+79
bài 13 : tính tổng
a) S1= 1+2+3+...+999
b) S2= 10+12+14+...+2010
c) S3= 21+23+25...+1001
d) S4= 24+25+26+...+125+126
e) S5= 1+4+7+...+79
Tính tổng.
S1=10+12+14+....+2010
S2=21+23+25+...+1001
S3=1+4+7+....+79
S4=15+17+19+21+....+151+153+155
S1 = 10 + 12 + 14 + ... + 2010: Có 1001 số hạng
=> (10 + 2010) . 1001 : 2 = 1011010
S2 = 21 + 23 + 25 + ... + 1001: Có 491 số hạng
=> (21 + 1001) . 491 : 2 = 250901
S3 = 1 + 4 + 7 + ... + 79: Có 27 số hạng
=> (1 + 79) . 27 : 2 = 1080
S4 = 15 + 17 + 19 + 21 + ... + 151 + 153 + 155: Có 71 số hạng.
=> (155 + 15) . 71 : 2 = 6035
s2=4250901
s1=1011010
s3=1018
s4=6035
tính tổng: a) S1= 1+2+3+...+999 / b) s2=10+12+14+...+2010 / c0 s3= 21+23+25+...+1001 /d0s5=1+4+7+...+79 / e)=15+17+19+21+...+151+1533+155 / f) s7=15+25+35+...+115 / g) s4= 24+25+26+...+125+126
Tính tổng
a) S1=1+2+3+..........999
b) S2 = 10+12+14+.......2010
c) S3=1+4+7+.........79
a) số số hạng là 999
tổng là \(\dfrac{\left(1+999\right).999}{2}=49950\)
b)sô số hạng là \(\dfrac{2010-10}{2}+1=1001\)
tổng là \(\dfrac{\left(10+2010\right).1001}{2}=1011010\)
c) số số hạng là \(\dfrac{79-1}{3}=26\)
tổng là \(\dfrac{\left(79+1\right).26}{2}=1040\)
Tính tổng
S1 = 1 + 2 + 3 +....+ 999
S2 = 10 + 12 + 14 +....+ 2010
S3 = 21 + 23 + 25 +....+ 1001
S4 = 24 + 25 + 26 +....+ 125 + 126
S5 = 1 + 4 + 7 +.......+ 79
S6 = 15 + 17 + 19 + 21 +....+ 151 + 153 + 155
S7 = 15 + 25 + 35 +....+ 115
Giải cụ thể ra nha!!!!Mình đang cần gấp!!!!
1.Tính tổng:
S1= 1+2+3+.....+999
S2= 10+12+14+.....+2010
S3= 21+23+25+.....+1001
S4= 24+25+26+.....+125+126
S5= 1+4+7+......+79
S6= 15+17+19+21+......+151+153+155
S6= 15+25+35+.......+115
2. Tìm x:
a) 5^2x=625
b) 9^x-1=9
c) 2^x : 2^5=1
2 . tìm x :
a ) 52x = 625
52x = 54
=> 2 . x = 4
x = 4 : 2
x = 2
b ) 9x-1 = 9
9x-1 = 91
=> x - 1 = 1
x = 1 + 1
x = 2
c ) 2x : 25 = 1
2x-5 = 1
=> x = 5 , vì 25-5 = 20 = 1
Tính tổng :
a) S1= 1 + 2 +3 + ..... + 999
b) S2= 10 + 12 + 14 + ..... + 2010
c) S3= 21 + 23 + 25 + ..... + 1001
d) S5=1 + 4 + 7 + ..... +79
e) S7= 15 + 25 + 35 + ..... + 115
a) \(S_1=1+2+3+4+......+999\)
\(\Rightarrow S_1=\dfrac{\left(999+1\right).\left[\left(999-1\right):1+1\right]}{2}\)
\(\Rightarrow S_1=\dfrac{1000.\left(998+1\right)}{2}\)
\(\Rightarrow S_1=\dfrac{1000.999}{2}\)
\(\Rightarrow S_1=\dfrac{999000}{2}\)
\(\Rightarrow S_1=499500\)
b) \(S_2=10+12+14+......+2010\)
\(\Rightarrow S_2=\dfrac{\left(2010+10\right).\left[\left(2010-10\right):2+1\right]}{2}\)
\(\Rightarrow S_2=\dfrac{2020.\left(2000:2+1\right)}{2}\)
\(\Rightarrow S_2=\dfrac{2020.\left(1000+1\right)}{2}\)
\(\Rightarrow S_2=\dfrac{2020.1001}{2}\)
\(\Rightarrow S_2=\dfrac{2022020}{2}\)
\(\Rightarrow S_2=1011010\)
c) \(S_3=21+23+25+.......1001\)
\(\Rightarrow S_3=\dfrac{\left(1001+21\right).\left[\left(1001-21\right):2+1\right]}{2}\)
\(\Rightarrow S_3=\dfrac{1022.\left(980:2+1\right)}{2}\)
\(\Rightarrow S_3=\dfrac{1022.\left(490+1\right)}{2}\)
\(\Rightarrow S_3=\dfrac{1022.491}{2}\)
\(\Rightarrow S_3=\dfrac{501802}{2}\)
\(\Rightarrow S_3=250901\)
d) \(S_5=1+4+7+......+79\)
\(\Rightarrow S_5=\dfrac{\left(79+1\right).\left[\left(79-1\right):3+1\right]}{2}\)
\(\Rightarrow S_5=\dfrac{80.\left(78:3+1\right)}{2}\)
\(\Rightarrow S_5=\dfrac{80.\left(26+1\right)}{2}\)
\(\Rightarrow S_5=\dfrac{80.27}{2}\)
\(\Rightarrow S_5=\dfrac{2160}{2}\)
\(\Rightarrow S_5=1080\)
e) \(S_7=15+25+35+45+......+115\)
\(\Rightarrow S_7=\dfrac{\left(115+15\right).\left[\left(115-15\right):10+1\right]}{2}\)
\(\Rightarrow S_7=\dfrac{130.\left(100:10+1\right)}{2}\)
\(\Rightarrow S_7=\dfrac{130.\left(10+1\right)}{2}\)
\(\Rightarrow S_7=\dfrac{130.11}{2}\)
\(\Rightarrow S_7=\dfrac{1430}{2}\)
\(\Rightarrow S_7=715\)
S1=1+2+3+....+999
S2=10+12+14+......+2010
S3=21+23+25+.....+1001
S7=15+25+35+.....+115
S5=1+4+7+.....+79
Giải hộ mk nha , mk đang vội !!!!!
S1= 1+2+3...+999
S1= (999-1) :1 +1= 999
S1= (999+1) x999 :2=499500
S1= 499500
S2= ( 1010 -10) : 2 +1= 501
S2= (1010+ 10) x 501:2= 255510
S 1=1+2
S2=3+4+5
S4=6+7+8+9
S5=10+11+12+13+14
Tính s100
Ai giải đc bài này thì mình chọn cho