a) \(55-4x-4\left(-x+3\right)=6-2\left(-8-3x\right)\)

\(55-4x+4x-12=6+16+6x\)

\(43-6-16=6x\)

\(6x=21\)

\(x=3,5\)

b) \(-5\left(-2x-6\right)-9\left(4-7x\right)=51-3x+6\left(x-9\right)\)

\(10x+30-36+63x=51-3x+6x-54\)

\(73x-6=-3+3x\)

\(73x-3x=-3+6\)

\(70x=3\)

\(x=\frac{3}{70}\)

c) \(93+\left|6-3x\right|-39=231\)

\(\left|6-3x\right|+54=231\)

\(\left|6-3x\right|=177\)

\(\Rightarrow\orbr{\begin{cases}6-3x=177\\6-3x=-177\end{cases}}\Rightarrow\orbr{\begin{cases}3x=6-177\\3x=6+177\end{cases}}\Rightarrow\orbr{\begin{cases}3x=-171\\3x=183\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-57\\x=61\end{cases}}\)

a)       \(55-4x-4\left(-x+3\right)=6-2\left(-8-3x\right)\)

\(\Leftrightarrow\)\(55-4x+4x-12=6+16+6x\)

\(\Leftrightarrow\)\(6x+22=43\)

\(\Leftrightarrow\)\(6x=43-22=21\)

\(\Leftrightarrow\)\(x=21:6=3.5\)

Vậy...

b)pt\(\Leftrightarrow10x+30-36+63x=51-3x+6x-54\)

tự tiếp

a) |2x - 1| - 3 = 5 

=> |2x - 1| = 8

Có 2 TH xảy ra:

TH1 : 2x - 1 = 8 => 2x = 9 => x = 9/2 (ko thỏa mãn x thuộc Z)

TH2 : -(2x - 1) = 8 => -2x + 1 = 8 => -2x = 9 => x = -9/2 (ko thỏa mãn x thuộc Z)

b) |3x - 5| = 4

Có 2 TH xảy ra :

TH1 : 3x - 5 = 4 => 3x = 9 => x = 3

TH2 : -(3x - 5) = 4 => -3x + 5 = 4 => -3x = -1 => x = 1/3 (ko thỏa mãn x thuộc Z)

c) |5x - 1| = |-3 - 3x| 

Có 2 TH xảy ra :

TH1 : 5x - 1 = -3 - 3x => 5x + 3x = -3 + 1 => 8x = -2 => x = -1/4 (ko thỏa mãn x thuộc Z)

TH2 : 5x - 1 = -(-3 - 3x) => 5x - 1 = 3 + 3x => 5x - 3x = 3 +1 => 2x = 4 => x = 2

d) |4x - 8| = |x + 1|

Có 2 TH xảy ra :

TH1 : 4x - 8 = x + 1 => 4x - x = 1 + 8 => 3x = 9 => x = 3

TH2 : 4x - 8 = -(x + 10) => 4x - 8 = -x - 10 => 4x + x = -10 + 8 => 5x = -2 => x = -2/5 (ko thỏa mãn x thuộc Z)

e) |3x - 5| - |4x + 9| = 0

=> |3x - 5| = |4x + 9|

Có 2 TH xảy ra :

TH1 : 3x - 5 = 4x + 9 => 3x - 4x = 9 + 5 => -x = 14 => x = -14

TH2 : 3x - 5 = -(4x + 9) => 3x - 5 = -4x - 9 => 3x + 4x = -9 + 5 => 7x = -4 => x = -4/7 (ko thỏa mãn x thuộc Z)

a: =>2x+5=4

=>2x=-1

hay x=-1/2

b: \(\Leftrightarrow\left(3x-4\right)^2\cdot\left[\left(3x-4\right)^2-1\right]=0\)

=>(3x-4)(3x-5)(3x-3)=0

hay \(x\in\left\{1;\dfrac{4}{3};\dfrac{5}{3}\right\}\)

c: \(\Leftrightarrow3^{x+1}=3^{2x}\)

=>2x=x+1

=>x=1

d: \(\Leftrightarrow2^{2x+3}=2^{2x-10}\)

=>2x+3=2x-10

=>0x=-13(vô lý)

k mk đi

ai k mk 

mk k lại

thanks

không ai trả lời 

a,\(2\left(3x-1\right)-5\left(x-3\right)-9\left(2x-4\right)=24\)

\(< =>6x-2-5x+15-18x+36=24\)

\(< =>-29x+49=24< =>29x=25< =>x=\frac{25}{29}\)

b,\(2x^2+4\left(x^2-1\right)=2x\left(3x+1\right)\)

\(< =>2x^2+4x^2-4=6x^2+2x\)

\(< =>2x=-4< =>x=-\frac{4}{2}=-2\)

c, \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=4\)

\(< =>10x-6x^2+6x^2-10x-3x+21=4\)

\(< =>-3x=4-21=-17< =>x=\frac{17}{3}\)

d, \(5x\left(x+1\right)-4x\left(x+2\right)=1-x\)

\(< =>5x^2+5x-4x^2-8x=1-x\)

\(< =>x^2-3x+x-1=0\)

\(< =>x^2-2x-1=0\)

\(< =>\left(x-1\right)^2=2\)

\(< =>\orbr{\begin{cases}x-1=\sqrt{2}\\x-1=-\sqrt{2}\end{cases}}\)

\(< =>\orbr{\begin{cases}x=1+\sqrt{2}\\x=1-\sqrt{2}\end{cases}}\)

Sai rồi bn:)

a, \(2\left(3x-1\right)-5\left(x-3\right)-9\left(2x-4\right)=24\)

\(\Leftrightarrow6x-2-5x+15-18x+36=24\)

\(\Leftrightarrow-17x+25=0\Leftrightarrow x=\frac{25}{17}\)

b, \(2x^2+4\left(x^2-1\right)=2x\left(3x+1\right)\)

\(\Leftrightarrow2x^2+4x^2-4=6x^2+2x\)

\(\Leftrightarrow-4-2x=0\Leftrightarrow x=-2\)

c, \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=4\)

\(\Leftrightarrow10x-6x^2+6x^2-10x-3x+21=4\)

\(\Leftrightarrow-3x+17=0\Leftrightarrow x=\frac{17}{3}\)

d, \(5x\left(x+1\right)-4x\left(x+2\right)=1-x\)

\(\Leftrightarrow5x^2+5x-4x^2-8x=1-x\)

\(\Leftrightarrow x^2-3x-1+x=0\Leftrightarrow x^2-2x-1=0\)

\(\Leftrightarrow x^2-2x+1-2=0\Leftrightarrow\left(x-1\right)^2=2\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=\sqrt{2}\\x-1=-\sqrt{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{2}+1\\x=-\sqrt{2}+1\end{cases}}}\)

b, \(\left(x-5\right)\left(x-4\right)-\left(x+1\right)\left(x-2\right)=7\)

\(\Rightarrow x^2-9x+20-x^2+x+2=7\)

\(\Rightarrow-8x+22=7\)

\(\Rightarrow-8x=-15\)

\(\Rightarrow x=\frac{15}{8}\)

c, \(\left(3x-4\right)\left(x-2\right)=3x\left(x-9\right)-3\)

\(\Rightarrow3x^2-10x+8=3x^2-27x-3\)

\(\Rightarrow3x^2-10x-3x^2+27x=\left(-3\right)+\left(-8\right)\)

\(\Rightarrow17x=-11\)

\(\Rightarrow x=-\frac{11}{17}\)

d, \(\left(x-3\right)\left(x^2+3x+9\right)+x\left(5-x^2\right)=6x\)

\(\Rightarrow x^3+3x^2+9x-3x^2-9x-27+5x-x^3=6x\)

\(\Rightarrow6x=-27\)

\(\Rightarrow x=-\frac{27}{6}\)

\(\Rightarrow x=-\frac{9}{2}\)

e, \(\left(3x-5\right)\left(x+1\right)-\left(3x-1\right)\left(x+1\right)=x-4\)

\(\Rightarrow3x^2-2x-5-3x^2-2x+1=x-4\)

\(\Rightarrow-4=x-4\)

\(\Rightarrow x=0\)

b)    (x - 5)(x - 4) - (x + 1)(x - 2) = 7
<=> x² - 9x + 20 - x² + x + 2 - 7 = 0
<=> 8x - 15 = 0 <=> x = 15/8

c)    (3x - 4)(x - 2) = 3x(x - 9) - 3
<=> 3x² - 10x + 8 = 3x² - 27x - 3
<=> 17x = -11 <=> x = -11/17

d)    (x - 3)(x² + 3x + 9) + x(5 - x²) = 6x
<=> x³ - 27 - x³ + 5x - 6x = 0
<=> x = -27

e)    (3x - 5)(x + 1) - (3x - 1)(x + 1) = x - 4
<=> (x + 1)(3x - 5 - 3x + 1) - x + 4 = 0
<=> -4x - 4 - x + 4 = 0 <=> x = 0

a) \(\Rightarrow5x^2-15x=5x^2-x-10x+2-5\)

\(\Rightarrow5x^2-15x-5x^2+x+10x=2-5\)

\(\Rightarrow-4x=-3\)

\(\Rightarrow x=\frac{3}{4}\)

Vậy \(x=\frac{3}{4}\)

b) \(\Rightarrow x^2-4x-5x+20-x^2+2x-x+2=7\)

\(\Rightarrow x^2-4x-5x-x^2+2x-x=7-20-2\)

\(\Rightarrow-8x=-15\)

\(\Rightarrow x=\frac{15}{8}\)

Vậy \(x=\frac{15}{8}\)

c) \(\Rightarrow3x^2-6x-4x+8=3x^2-27x-3\)

\(\Rightarrow3x^2-6x-4x-3x^2+27x=-3-8\)

\(\Rightarrow17x=-11\)

\(\Rightarrow x=\frac{-11}{17}\)

Vậy \(x=\frac{-11}{17}\)

Chúc bạn học tốt.

Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu

a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14) 

=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84

=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84) 

=> 156 -  56x = 24x - 324 

=>  24x + 56x = 324 + 156 

=> 80x = 480 

=> x = 480 : 80 =  6 

Vậy x = 6 

b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1 

=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1 

=> (15x - 8x) + (25 + 12) = 11x + 37 

=> 7x + 37 = 11x + 37 

=> 11x - 7x = 0 

=>  x = 0 

sai đề rồi bạn

đề đúng mà bạn