chữ số hàng đơn vị là 0

neu rõ cách tính

\(\left|x-3\right|-7=-4\)

\(\left|x-3\right|=-4+7\)

\(\left|x-3\right|=3\)

\(\Rightarrow\)\(\orbr{\begin{cases}x-3=3\\x-3=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=6\\x=0\end{cases}}}\)

Vậy x=6 hoặc x=0

|x-3|-7=-4

|x-3|   =-4+7

|x-3|=3 

==>\(\orbr{\begin{cases}x-3=3\Rightarrow x=6\\x-3=-3\Rightarrow x=0\end{cases}}\)

                                        Vậy x=6; x=0

|x-3| = (-4)+7

|x-3|=3

=> x-3=-3 hoac x-3=3

*x-3=-3

x=(-3)+3

x=0

*x-3=3

x=3+3

x=6

Vay: x\(\varepsilon\){0;6}

1.4x - 5(-3+x)=7

   4x - 5(x-3)  =7

  4x - 5x + 15=7

     -1x   + 15=7

     -1x         =-8

       =>    x =8

2.5(x-3) - 2(x+6)=9

  5x - 15 -2x -12=9

 5x - 2x -15 - 12=9

             5x - 2x=9 + 12 + 15

             5x - 2x= 36

                3x   = 36

        =>     x   = 12

3.4(x-1) - 3(x-2)=15

  4x - 4 - 3x + 6=15

           4x - 3x =15 - 6 + 4

           4x - 3x = 13

              => x = 13

Nhớ mink nhoa pn

\(6-2\left(x-1\right)=4\)

\(\Rightarrow2\left(x-1\right)=6-4\)

\(\Rightarrow2\left(x-1\right)=2\)

\(\Rightarrow x-1=1\)

\(\Rightarrow x=1+1=2\)

________________

\(2\cdot\left(x-2\right)+1=7\)

\(\Rightarrow2\cdot\left(x-2\right)=7-1\)

\(\Rightarrow2\cdot\left(x-2\right)=6\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=3+2=5\)

_______________

\(\left(2\cdot x-3\right)+4=9\)

\(\Rightarrow2\cdot x-3=5\)

\(\Rightarrow2\cdot x=3+5\)

\(\Rightarrow2\cdot x=8\)

\(\Rightarrow x=\dfrac{8}{2}=4\)

________________

\(\left(3\cdot x-2\right)-1=3\)

\(\Rightarrow3\cdot x-2=3+1\)

\(\Rightarrow3\cdot x-2=4\)

\(\Rightarrow3\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{3}=2\)

a: =>2(x-1)=2

=>x-1=1

=>x=2

b: =>2(x-2)=6

=>x-2=3

=>x=5

c; =>2x-3=5

=>2x=8

=>x=4

d: =>3x-2=4

=>3x=6

=>x=2

e: =>2(6-x)=4

=>6-x=2

=>x=4

f: =>x-2=5

=>x=7

g: =>10-2x=4

=>2x=6

=>x=3

h: =>2x+4=3

=>2x=-1

=>x=-1/2

j: =>x+2=12

=>x=10

l: =>2x+3=3

=>2x=0

=>x=0

\(6-2\left(x-1\right)=4\\ 2\left(x-1\right)=6-4=2\\ x-1=\dfrac{2}{2}=1\\ x=1+1=2\)

\(2\left(6-x\right)+1=5\\ 2\left(6-x\right)=5-1=4\\ 6-x=\dfrac{4}{2}=2\\ x=6-2=4\)

\(\left(4+2x\right)-1=8\\ 3\left(4+2x\right)=8+1=9\\ 4+2x=\dfrac{9}{3}=3\\ 2x=3-4=-1\\ x=-\dfrac{1}{2}\)

\(2\left(x-2\right)+1=7\\ 2\left(x-2\right)=7-1=6\\ x-2=\dfrac{6}{2}=3\\ x=3+2=5\)

\(20+\left(x-2\right)=25\\ x-2=25-20=5\\ x=5+2=7\)

\(\left(x+2\right)-5=7\\ x+2=7+5=12\\ x=12-2=10\)

\(\left(2x-3\right)+4=9\\ 2x-3=9-4=5\\ 2x=5+3=8\\ x=\dfrac{8}{2}=4\)

\(\left(10-\dfrac{2}{x}\right)-1=3\\ 10-\dfrac{2}{x}=3+1=4\\ \dfrac{2}{x}=10-4=6\\ x=\dfrac{2}{6}=\dfrac{1}{3}\)

\(\left(3+2x\right)-1=3\\ 3+2x=3+1=4\\ 2x=4-3=1\\ x=\dfrac{1}{2}\)

\(\left(3x-2\right)-1=3\\ 3x-2=3+1=4\\ 3x=4+2=6\\ x=\dfrac{6}{3}=2\)

Dễ mak 

nhưng mik nhìn đề thấy dài quá nên ko muốn làm 

hihi^_$

Trả lời :

k bình luận linh tinh nx

~HT~