\(18,2:x=1,4\times4\)

\(\Rightarrow18,2:x=5,6\)

\(\Rightarrow x=3,25\)

    \(\frac{3}{5}\times x=\frac{2}{3}-\frac{2}{7}\)

\(\Rightarrow\frac{3}{5}\times x=\frac{8}{21}\)

\(\Rightarrow x=\frac{40}{63}\)

tíc nha

18,2 : x =1,4 x 4

18,2 : x =5,6

x = 18,2 ; 5,6

x = 3,25

\(18,2:x=1,4\cdot4\)

             \(x=5,6\)

             \(x=18,2:5,6\)

             \(x=3,25\)   

\(\frac{3}{5}\cdot x=\frac{2}{3}-\frac{2}{7}\)

         \(x=\frac{8}{21}\)

         \(x=\frac{8}{21}:\frac{3}{5}\)

         \(x=\frac{40}{63}\)

a)(3/4-5/6+7/12).(-12/7)=1/2.(-12/7)

=6/7

b)1,4.15/49-(4/5+2/3):11/5=1,4.15/49-22/15:11/5

=3/7-2/3=-5/21

(3/4-5/6+7/12)×(-12/7)

=(9/12-10/12+7/12)×(-12/7)

=(-1/12+7/12)×(-12/7)

=6/12×(-12/7)

=1/2×(-12/7)

=-12/14

=-6/7

=1,4 x\(\dfrac{15}{49}-\) \(\left(\dfrac{4}{5}+\dfrac{2}{3}\right)\) : 2\(\dfrac{1}{5}\)

=  \(\dfrac{3}{7}\) - \(\dfrac{22}{15}\) : \(\dfrac{11}{5}\)

= \(\dfrac{3}{7}\) -  \(\dfrac{2}{3}\)

= \(-\dfrac{5}{21}\) 

( 2\(\dfrac{1}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(x\)) = \(\dfrac{3}{4}\)

  \(\dfrac{11}{5}\) + \(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\)

            \(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\) - \(\dfrac{11}{5}\)

           \(\dfrac{3}{5}\)\(x\) = - \(\dfrac{29}{20}\)

             \(x\) = -\(\dfrac{29}{12}\)

3\(\dfrac{1}{3}\) x \(x+16\)\(\dfrac{3}{4}\)= 13,25

\(\dfrac{10}{3}\) x \(x\) + \(\dfrac{67}{4}\) = 13,25

\(\dfrac{10}{3}\) x \(x\) = 13,25 - \(\dfrac{67}{4}\)

\(\dfrac{10}{3}\times x=\) \(\dfrac{103}{28}\) 

          \(x\) = \(\dfrac{103}{28}:\dfrac{10}{3}\)

          \(x=\) \(\dfrac{309}{280}\)

2:

a: =>2/3:x=1,4-2,4=-1

=>x=-2/3

b: =>x/5=25/30-19/30=6/30=1/5

=>x=1

3:

Số học sinh giỏi là 40*1/4=10 bạn

Số học sinh khá là 30*3/5=18 bạn

Số học sinh TB là 30-18=12 bạn

1/ a/\(-\frac{7}{18}=\left(-\frac{7}{2}\right)\left(\frac{1}{9}\right)\)

b/\(-\frac{7}{18}=\left(-\frac{7}{9}\right):2\)

2/

a/\(\frac{7}{15}\cdot\left(-\frac{3}{8}-\frac{3}{7}\right)=\frac{7}{15}\cdot\left(-\frac{45}{56}\right)=-\frac{3}{8}\)

b/\(\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+-\frac{4}{4}\right):\frac{3}{7}\)

\(=\left(-\frac{7}{20}\right):\frac{3}{7}+\left(-\frac{2}{5}\right):\frac{3}{7}\)

\(=\left(-\frac{49}{60}\right)+\left(-\frac{14}{15}\right)=-\frac{7}{4}\)

c/\(\frac{2}{3}\cdot\left(-\frac{5}{2}\right)+\frac{10}{15}\cdot\left(-\frac{3}{7}\right)-\frac{2}{3}\cdot\left(-\frac{5}{3}\right)\)

\(=\frac{2}{3}\cdot\left(-\frac{5}{2}-\frac{3}{7}+\frac{5}{3}\right)=-\frac{53}{63}\)

3/

\(2-\left(3-x\right)=-\frac{3}{2}\)

\(2-3+x=-\frac{3}{2}\)

\(x=-\frac{3}{2}+3-2=-\frac{1}{2}\)

4/ 

a/ Ta có 2 trường hợp:

TH1: \(x-3,5=7,5\)

\(x=7,5+3,5=11\)

TH2: \(x-3,5=-7,5\)

\(x=-7,5+3,5=-4\)

b/ Ta có 2 trường hợp:

TH1:\(x-0,4=3,6\)

\(x=4\)

TH2: \(x-0,4=-3,6\)

\(x=-3.2\)

c/ Ta có 2 trường hợp:

TH1:\(x+\frac{4}{5}=\frac{3}{2}\)

\(x=\frac{7}{10}\)

TH2:\(x+\frac{4}{5}=-\frac{3}{2}\)

\(x=-\frac{32}{10}\)

a) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}\)

\(=\dfrac{5}{7}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)

\(=\dfrac{5}{7}\times1\)

\(=\dfrac{5}{7}\)

b) \(\dfrac{1}{10}+\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{9}{10}-1\)

\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{1}{10}+\dfrac{9}{10}-1\right)\)

\(=1+0\)

\(=1\)

c) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}+\dfrac{2}{7}\)

\(=\dfrac{5}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\dfrac{2}{7}\)

\(=\dfrac{5}{7}+\dfrac{2}{7}\)

\(=1\)

d) \(\dfrac{2}{7}+\dfrac{2}{8}+\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{4}{7}\)

\(=\left(\dfrac{2}{8}+\dfrac{1}{4}\right)+\left(\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{4}{7}\right)\)

\(=\left(\dfrac{1}{4}+\dfrac{1}{4}\right)+1\)

\(=\dfrac{1}{2}+1\)

\(=\dfrac{3}{2}\)

e) \(\dfrac{4}{5}+\dfrac{3}{10}+\dfrac{2}{10}+0,7\)

\(=\dfrac{4}{5}+\dfrac{5}{10}+\dfrac{7}{10}\)

\(=\dfrac{4}{5}+\dfrac{12}{10}\)

\(=\dfrac{4}{5}+\dfrac{6}{5}\)

\(=\dfrac{10}{5}\)

\(=2\)

g) \(362\times728+326\times272\)

\(=326\times\left(728+272\right)\)

\(=326\times1000\)

\(=326000\) 

a) |4 (x-1)| = 12

=> 4(x-1) = 12 hoặc -12

Với 4(x-1) = 12

=> x-1 = 12:4

=> x-1 = 3

=> x= 3+1

=> x=4

Với 4(x-1) = -12

x-1 = (-12) : 4

x-1 = -3
x = -2

b) |2x +1| - 5 = 10

|2x +1| = 10 +5

|2x +1| = 15

=> |2x +1| = 15 hoặc -15

Với 2x +1 = 15

2x = 14

=> x= 14 :2

=> x=7

Với 2x+1 = -15

2x = (-15) -1

2x = -16

=> x= (-16) :2

=> x= -8
\dfrac{1}{2}