Tính tổng
a) 9+99+999+...+999999
b) 1+11+111+...+1111111
c)1.2 + 2.3+3.4+4.5+...+98.99
d) 1.3.5 + 3.5.7+5.7.9+...+95.97.99
a) \(\dfrac{2}{1.2.3}+\dfrac{2}{2.3.4}+\dfrac{2}{3.4.5}+...+\dfrac{2}{18.19.20}\)
b) \(\dfrac{4}{1.3.5}+\dfrac{4}{3.5.7}+\dfrac{4}{5.7.9}+...+\dfrac{4}{21.23.25}\)
c) \(\dfrac{3}{1.2}-\dfrac{5}{2.3}+\dfrac{7}{3.4}-\dfrac{9}{4.5}+...+\dfrac{39}{19.20}-\dfrac{41}{20.21}\)
d) \(\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot\dfrac{24}{25}\cdot...\cdot\dfrac{99}{100}\cdot\dfrac{120}{121}\)
e) \(\left(1+\dfrac{7}{9}\right)\left(1+\dfrac{7}{20}\right)\left(1+\dfrac{7}{33}\right)\left(1+\dfrac{7}{48}\right)...\left(1+\dfrac{7}{180}\right)\)
Các bạn không nhất thiết phải làm hết, làm cho nó dễ hiểu được thì càng tốt để mk vận dụng
a: \(=\dfrac{1}{1\cdot2}-\dfrac{1}{2\cdot3}+\dfrac{1}{2\cdot3}-\dfrac{1}{3\cdot4}+...+\dfrac{1}{18\cdot19}-\dfrac{1}{19\cdot20}\)
=1/2-1/380
=179/380
b: \(=\dfrac{1}{1\cdot3}-\dfrac{1}{3\cdot5}+\dfrac{1}{3\cdot5}-\dfrac{1}{5\cdot7}+...+\dfrac{1}{21\cdot23}-\dfrac{1}{23\cdot25}\)
\(=\dfrac{1}{3}-\dfrac{1}{575}=\dfrac{572}{1725}\)
c: \(=1+\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}-\dfrac{1}{20}-\dfrac{1}{21}\)
=1-1/21
=20/21
d: \(=\left(1-\dfrac{1}{9}\right)\left(1-\dfrac{1}{16}\right)\cdot...\cdot\left(1-\dfrac{1}{121}\right)\)
\(=\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{10}{11}\cdot\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{12}{11}\)
\(=\dfrac{2}{11}\cdot\dfrac{12}{2}=\dfrac{12}{11}\)
Tính:
A=1.2.3+2.3.4+3.4.5+4.5.6+5.6.7+6.7.8+7.8.9+8.9.10
B=1.3.5+3.5.7+5.7.9+7.9.11+......+95.97.99
C=1.2.3+3.4.5+5.6.7+7.8.9+........+98.99.100
D=1.22+2.32+3.42+4.52+....+99.1002
Tính tổng:
A=1.2.3+2.3.4+3.4.5+...…+99.100.101
B=1.2+3.4+51.6+…+99.100
C=1.3+3.5+5.7+…+97.99
D=1.3.5+3.5.7+…+95.97.99
lấy 1 chia cho các tổng rồi áp dụng công thức là ra
Tính tổng : C = 1.3.5 + 3.5.7 + 5.7.9 + .... + 93.95.97 + 95.97.99
Tính tổng :
a,1.22+2.32+3.42+...+99.1002
b,1.32+3.52+5.72+...+97.992
c,1+4+9+16+25+36+...+10000
d,1.3.5-3.5.7+5.7.9-7.9.11+...-97.99.101
Tính:
a)1^2+2^2-3^2+4^2-.........-19^2+20^2
b)1.2.3+3.4.5+......99.100.101
c)1.3.5+3.5.7+......+95.97.99
d)9+99+999+............+99...9(10 số 9)
Tính tổng :
a,1.22+2.32+3.42+...+99.1002
b,1.32+3.52+5.72+...+97.992
c,1+4+9+16+25+36+...+10000
d,1.3.5-3.5.7+5.7.9-7.9.11+...-97.99.101
a)1.22 + 2.32 + 3.42 + ... + 99.1002
= 1.2(3 - 1) + 2.3(4 - 1) + 3.4(5 - 1) + ... + 99.100(101 - 1)
= 1.2.3 - 1.2 + 2.3.4 - 2.3 + 3.4.5 - 3.4 + ... + 99.100.101 - 99.100
= (1.2.3 + 2.3.4 + 3.4.5 + ... + 99.100.101) - (1.2 + 2.3 + 3.4 + ... + 99.100)
Bài 5) Tính giá trị của biểu thức
a) A=1.2+2.3+3.4+...+9.10
b) B=3.4+4.5+5.6+...+198.199+199.200
c) C=1.2.3+2.3.4+3.4.5+...+8.9.10
d) D=31.32.33+32.33.34+...+58.59.60
e) E=1.3+3.5+5.7+...+95.97+97.99
f) F=51.53+53.55+...+153.155+155.157
g) G=1.3.5+3.5.7+...+15.17.19+17.19.21
h) H=2.4+4.6+6.8+...+96.98+98.100
Bài 5:
a) Ta có: \(A=1\cdot2+2\cdot3+3\cdot4+...+9\cdot10\)
\(\Leftrightarrow3\cdot A=3\cdot\left(1\cdot2+2\cdot3+3\cdot4+...+9\cdot10\right)\)
\(\Leftrightarrow3A=1\cdot2\cdot\left(3-0\right)+2\cdot3\cdot\left(4-1\right)+3\cdot4\cdot\left(5-2\right)+...+9\cdot10\cdot\left(11-8\right)\)
\(\Leftrightarrow3A=1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+3\cdot4\cdot5-2\cdot3\cdot4+...+8\cdot9\cdot10-8\cdot9\cdot10+9\cdot10\cdot11\)
\(\Leftrightarrow3\cdot A=9\cdot10\cdot11=90\cdot11=990\)
hay A=330
Vậy: A=330
G=1.3.5+3.5.7+5.7.9+...+95.97.99
Tính tổng G
\(G=1.3.5+3.5.7+5.7.9+...+95.97.99\)
\(G=1+99.\left(3+5+7+...+97\right)\)\
\(G=100.\left[\left(3+97\right)+\left(5+95\right)+...+\left(49+51\right)\right]\)
\(G=100.\left(100.24\right)\)
\(G=100.2400=240000\)