Rút gọn biểu thức sau :
a/ A = \(\frac{8\cdot4\cdot125\cdot25+96524+3476}{10\cdot125\cdot4\cdot25\cdot8}\)
b/ B = \(\frac{5+55+555+5555}{9+99+999+9999}\)
( dấu chấm là dấu nhân nha)
\(\frac{0,8\cdot0,04\cdot1,25\cdot25+0,6524+0.3476}{10\cdot125\cdot4\cdot25\cdot8}\)
làm giúp mik, mik vộiiii
\(\frac{0,8.0,04.1,25.25+0,6524+0,3476}{10.125.4.25.8}\)
\(=\frac{\left(0,8.1,25\right).\left(0,04.25\right)+\left(0,6524+0,3476\right)}{10.\left(125.8\right).\left(25.4\right)}\)
\(=\frac{1.1+1}{10.1000.100}\)
\(=\frac{1}{500000}\)
nếu mà ra phân số thì mình tính là \(\frac{2}{1000000}\)
nếu mà mình lấy 2:1000000=0,000002
chưa chắc là mình tính đúng đâu bạn nhớ tính lại nhé
chú bạn học giỏi nha
Rút gọn: A=\(\frac{5+55+555+5555}{9+99+999+9999}\)
\(A=\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)
Tớ làm luôn
A=\(\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}\)
A=\(\frac{5}{9}\)
\(A=\frac{\left(5.1+5.11+5.111+5.1111\right)}{9.1+9.11+9.111+9.1111}\)
\(A=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}\)
\(\Rightarrow A=\frac{5}{9}\)
Chúc em học tốt^^
Rút gọn
A = \(\frac{5+55+555+5555}{9+99+999+9999}\)
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)\(\frac{5}{9}\)
dấu chấm bạn cứ hiểu là nhân nhé !
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5+11x5+111x5+1111x5}{9+11x9+111x9+1111x9}\)\(=\frac{5x5x5x5}{9x9x9x9}=\frac{625}{6561}\)
A = \(\frac{6170}{11106}=\frac{5}{9}\)
Tính bằng cách hợp lí :
a, A=\(\dfrac{32\cdot125\cdot25+64\cdot125\cdot0,125}{2+4+6+...+98+100}\)
b, B=\(\dfrac{12\cdot194+6\cdot437\cdot2+3\cdot369\cdot4}{1+5+9+...+57+61+65\cdot2-26}\)
tính nhanh :
\(\frac{1}{1\cdot4}\)+\(\frac{1}{4\cdot7}\)+\(\frac{1}{7\cdot10}\)+....+\(\frac{1}{22\cdot25}\)
dấu chấm là dấu nhân nha
Gọi \(A=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{22.25}\)
\(\Leftrightarrow\)\(3A=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{22.25}\)
\(\Leftrightarrow\)\(3A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)
\(\Leftrightarrow\)\(3A=1-\frac{1}{25}\)
\(\Leftrightarrow\)\(3A=\frac{24}{25}\)
\(\Leftrightarrow\)\(A=\frac{24}{25}:3\)
\(\Leftrightarrow\)\(A=\frac{24}{25}.\frac{1}{3}\)
\(\Leftrightarrow\)\(A=\frac{8}{25}\)
Vậy \(A=\frac{8}{25}\)
Đặt \(C=\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}\)
\(\Rightarrow3C=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+....+\frac{3}{22.25}\)
\(\Rightarrow3C=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)
\(\Rightarrow3C=1-\frac{1}{25}=\frac{24}{25}\)
\(\Rightarrow C=\frac{24}{25}:3=\frac{8}{25}\)
Vậy \(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}=\frac{8}{24}\)
tính nhanh
e) \(\frac{0,1997+2,5\cdot12,5\cdot0,4\cdot0,08+0,8003}{1,25\cdot2,5\cdot8\cdot4}\)
g)\(\frac{\left(10,6524+0,3476\right)\cdot125\cdot0,4+8}{4\cdot0,1\cdot8\cdot0,25\cdot125}\)
e)\(\frac{0,1997+2,5\cdot12,5\cdot0,4\cdot0,08+8,003}{1,25\cdot2,5\cdot8\cdot4}=\frac{0,1997+1+8,003}{100}=\frac{2}{100}=\frac{1}{50}\)
g)\(\frac{\left(10,6524+0,3476\right)\cdot125\cdot0,4+8}{4\cdot0,1\cdot8\cdot0,25\cdot125}=\frac{11\cdot125\cdot0,4+8}{100}=\frac{558}{100}=5,58\)
Mk bó tay, chân.
Bạn ''Nguyễn Tiến Dũng'' làm đúng ròi đó.
Hok tốt !
rút gọn phân số : 5+55+555+5555 phần 9+99+999+9999
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)
bực quá đúng là bất công vừa làm bài , vừa đăng bài giups cuối cùng chẳng được gì
tính\(\frac{9^{4^{ }}\cdot27^5\cdot3^6\cdot4^4}{3^8\cdot8^{14}\cdot24\cdot3\cdot8^2}\)
\(\frac{5\cdot415\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot2^{19}-7\cdot2^{19}.27^6}\)
\(\frac{8^5\cdot24^4\cdot72^2}{16^{12}\cdot125^2\cdot94^4}\)
Câu 1 : \(1,321338308x10^{-4}\)
Câu 2 : \(1316,572106\)
Câu 3 : \(1,641302619x10^{-13}\)
Ủng hộ nhé,tớ đang âm.
rút gọn:5+55+555+5555/9+99+999+9999.
giúp mình với,ai đúng mình tick cho
\(\frac{5+55+555+5555}{9+99+999+9999}=\)
\(=\frac{5x\left(1+11+111+1111\right)}{9x\left(1+11+111+1111\right)}=\frac{5}{9}\)