giúp e 2 bài tìm x với
250:(10-x)=25 3x-2018:2=23
250 : ( 10 - x) = 25
3x - 2018 : 2 = 23
( 9x - 21) : 3 = 2
53 ( 9 - x) = 53
\(a,250:\left(10-x\right)=25\\ \Rightarrow10-x=250:25\\ \Rightarrow10-x=10\\ \Rightarrow x=10-10=0\\ b,3x-2018:2=23\\ \Rightarrow3x-1009=23\\ \Rightarrow3x=23+1009\\ \Rightarrow3x=1032\\ \Rightarrow x=1032:3=344\\ c,\left(9x-21\right):3=2\\ \Rightarrow9x-21=2\times3\\ \Rightarrow9x-21=6\\ \Rightarrow9x=21+6\\ \Rightarrow9x=27\\ \Rightarrow x=27:9=3\)
\(d,53\left(9-x\right)=53\\ \Rightarrow9-x=53:53\\ \Rightarrow9-x=1\\ \Rightarrow x=9-1=8\)
Bài 5. Tìm số nguyên x, biết:
1) 156 – (x + 32) = 115 2) (x – 34) - 97 = 0 3) 115 + (115 – x) = 215 4) 25 – 3.(6 – x) = 22 5) (x : 23 + 45) . 67 = 8911 Bài 6. Tìm số tự nhiên x, biết: 1) 3 x = 9 2) 2 . 3x = 10 . 312 + 8 . 274 3) (x + 1)2 = 25 4) (25 – 2x)3 : 5 – 3 2 = 42 5) 2 x+2 – 2 x = 48 GIÚP MÌNH VỚI MÌNH ĐANG CẦN GẤPTYUIUYGBGJCYYHBVJHBNGHJK.;;JHGFFDSAQWERTYUIO
Tìm x biết
a) (x-2018).3=0
b)2018.(3x-18)=0
c)25+(15+x)=75
d)136-2(164-x)=30
e)30-(14+2x)=8
f)56:(3x-1)=7
Lưu ý: 3x là 3.x, 2x là 2.x nha
Làm ơn hãy giúp mình
a) ( x - 2018 ) . 3 = 0
=> x - 2018 = 0
=> x = 2018
b) 2018 . ( 3x - 18 ) = 0
=> 3x - 18 = 0
=> 3x = 18
=> x = 6
c) 25 + ( 15 + x ) = 75
40 + x = 75
x = 35
d) 136 - 2 ( 164 - x ) = 30
2 ( 164 - x ) = 106
164 - x = 53
x = 111
e) 30 - ( 14 + 2x ) = 8
14 + 2x = 22
2x = 8
x = 4
f) 56 : ( 3x - 1 ) = 7
3x - 1 = 8
3x = 9
x = 3
\(a.\left(x-2018\right).3=0\)
\(x-2018=0\)
\(x=2018\)
~ mấy câu sau cx giống vậy nhé bạn ~
nếu bạn thấy câu nào khó thì nt cho mik nhe
a) ( x - 2018 ) . 3 = 0
( x - 2018 ) = 0
x = 0 + 2018
x= 2018
b) 2018( 3x - 18 ) = 0
3x - 18 = 0
3x = 18
x = 18 : 3
x = 6
c) 25 + ( 15+x ) = 75
15 + x = 50
x = 50 - 15
x = 35
d) 136 - 2( 164 - x ) = 30
2( 164 - x ) = 106
164 - x = 53
x = 111
e) 30 - ( 14 + 2x ) = 8
14 + 2x = 22
2x = 8
x = 4
f) 56 : ( 3x - 1 ) = 7
3x - 1 = 8
3x = 9
x = 3
trả lời giúp mình với
a 65-4^x+2=2018^0
b120+2.(3x-17)=2018^0
c 5^2x-3-2.5^2=5^2
d 30-[4:(x-2)+15]=3
e 740:(x+10)=10^2-2.13
g [(6x-39):7].4=12
bài 5:tìm x biết
a)400-5x=200 b)250:x+10=20
c)96-3(x+8)=42 d)36:(x-5)=2^2
e)15.5(x-35)-525=0 f)[3.(70-x)+5]:2=46
giúp mình vs
a) 400 - 5x = 200
5x = 200
x = 40
b) 250 : x + 10 = 20
250 : x = 10
x = 25
c) 96 - 3 ( x + 8 ) = 42
3 ( x + 8 ) = 54
( x + 8 ) = 54 : 3
x + 8 = 18
x = 18 - 8
x = 10
d) 36 : ( x - 5 ) = 22
36 : ( x - 5 ) = 4
x - 5 = 36 : 4
x - 5 = 9
x = 9 + 5
x = 14
e) 15 x 5 ( x - 35 ) - 525 = 0
75 ( x - 35 ) - 525 = 0
75 ( x - 35 ) = 525
x - 35 = 7
x = 7 + 35
x = 42
f) [ 3 x ( 70 - x ) + 5 ] : 2 = 46
[ 3 x ( 70 - x ) + 5 ] = 92
3 x ( 70 - x ) = 87
70 - x = 87 : 3
70 - x = 29
x = 41
a)5x=400-200 b)250:x=20-10 c)96-3(x+8)=42
5x=200 250:x=10 3(x+8)=96-42
x=200:5 x=250:10 3(x+8)=54
x=40 x=25 x+8=54:3
Vậy x = 40 Vậy x = 25 x+8=18
d)36:(x-5)=4 e)15.5(x-35)-525=0+525 x=18-8 15.5(x-35)=525 x=10
x-5=9 5(x-35)=525:15 x=9-5=4 5(x-35)=35 Vậy x=10
Vậy x = 4 x-35=35:5 f){3.(70-x)+5}=46.2
x-35=7 {3.(70-x)+5}=92
x=7+35 3.(70-x)=92-5
x=42 3.(70-x)=87
Vậy x=42 70-x=87:3
70-x=29
x=70-29
x=41
Vậy x= 41
tìm x biết
x - 30%x + 4x - 1/3 = 1/2 : 7/8
x + 2x + 3x + ... + 9x = 459 - 32
( x - 23) : 14 + 25 = 42 - 12018
Bài 1, Tìm giá trị nguyên x biết, E= -5-x/x-2 đạt giá trị nguyên
Bài 2, Tìm x,y thuộc N biết, 25-y^2=8x-2012^2
Bài 3, a) Tìm các số nguyên tố x,y sao cho: 51x+26y=2000
b) Tìm STN x,y biết: 7.(x-2004)^2=23-y^2
c) Tìm x,y nguyên: xy+3x-y=6
d) Tìm mọi số nguyên tố thỏa mãn: x^2+2y^2=1. ai làm nhanh hộ mk tich nha. cần mai luôn rồi. Xin trân trọng cảm ơn!
Bài 1:
Để E nguyên thì \(x+5⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;7;-7\right\}\)
hay \(x\in\left\{3;1;9;-5\right\}\)
giúp mình với ạ cần luôn nhá. mk sẽ tick cho!
Tìm x
25-{14-[(2-x)-(x+13)+23]} = 62-{8-[(2x-10)-(29-3x)+8]}
25-{14-[(2-x)-(x+13)+23]}=62-{8-[(2x-10)-(29-3x)+8]}
<=>25-14+2-x-x-13+23=62-8+2x-10-29+3x+8
<=>13-x-x-13+23=2x+3x+8-10-29
<=>-x-x+23=2x+3x+(-31)
<=>23-(x+x)=2x+2x-31
<=>23-2x=2x+3x-31
<=>23+31=2x+2x+3x
<=>54=x(2+2+3)
<=>54=x.7
=>x=54/7
Vậy x=54/7
<=>54=x.7
Bài 1:
a. Tính:
1+22+23+....+29+210
b. Tìm x biết:
a] 60 - 3 . [x-1] = 23. 3
b] [3x - 2]3 = 2 . 25
c] 5x+1 - 5x = 500
d] x2 = x4
a) Đặt: \(A=1+2^2+2^3+...+2^{10}\)
\(\Rightarrow2A=2\left(1+2^2+2^3+...+2^9+2^{10}\right)\)
\(\Rightarrow2A=2+2^3+2^4+...+2^{10}+2^{11}\)
\(\Rightarrow2A-A=\left(2+2^3+2^4+...+2^{10}+2^{11}\right)-\left(1+2^2+2^3+...+2^{10}\right)\)
\(\Rightarrow A=\left(2^3-2^3\right)+\left(2^4-2^4\right)+...+\left(2-1\right)+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=0+0+...+1+\left(2^{11}-2^2\right)\)
\(\Rightarrow A=1+2^{11}-2^2=1+2048-4=2045\)
Vậy: \(1+2^2+2^3+...+2^{10}=2045\)
b)
a] \(60-3\left(x-1\right)=2^3\cdot3\)
\(\Rightarrow60-3\left(x-1\right)=24\)
\(\Rightarrow3\left(x-1\right)=36\)
\(\Rightarrow x-1=12\)
\(\Rightarrow x=13\)
b] \(\left(3x-2\right)^3=2\cdot2^5\)
\(\Rightarrow\left(3x-2\right)^3=2^6\)
\(\Rightarrow\left(3x-2\right)^3=\left(2^2\right)^3\)
\(\Rightarrow3x-2=2^2\)
\(\Rightarrow3x=6\)
\(x=2\)
c] \(5^{x+1}-5^x=500\)
\(\Rightarrow5^x\left(5-1\right)=500\)
\(\Rightarrow5^x\cdot4=500\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
d] \(x^2=x^4\)
\(\Rightarrow x=x^2\)
\(\Rightarrow x-x^2=0\)
\(\Rightarrow x\left(1-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\1-x=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)