a: \(x^4+3x^3+x^2+3x\)

\(=x\left(x^3+3x^2+x+3\right)\)

\(=x\left(x+3\right)\left(x^2+1\right)\)

c: \(x^2-xy-x+y\)

\(=x\left(x-y\right)-\left(x-y\right)\)

\(=\left(x-y\right)\left(x-1\right)\)

a) \(x^2-5xy+6y^2\)

\(=x^2-3xy-2xy+6y^2\)

\(=x\left(x-3y\right)-2y\left(x-3y\right)\)

\(=\left(x-2y\right)\left(x-3y\right)\)

b) \(16\left(x-1\right)^2-36y^2\)

\(=\left(4x-4\right)^2-\left(6y\right)^2\)

\(=\left(4x+6y-4\right)\left(4x-6y-4\right)\)

c) \(4\left(x+y\right)-12\left(x+y\right)^2\)

\(=\left(x+y\right)\left[4-12\left(x+y\right)\right]\)

\(=4\left(x+y\right)\left[1-3x-3y\right]\)

\(1,=3xy\left(x^2+2xy+y^2\right)=3xy\left(x+y\right)^2\\ 2,=7xy\left(2x-3y+4xy\right)\\ 3,=\left(x-1\right)\left(x^2-4\right)=\left(x-2\right)\left(x+2\right)\left(x-1\right)\\ 4,=\left(x-y\right)\left(10x+8\right)=2\left(5x+4\right)\left(x-y\right)\\ 5,=\left(b-c\right)\left(8a-6b\right)=2\left(4a-3b\right)\left(b-c\right)\\ 6,=\left(x-1\right)\left(x^2-16\right)=\left(x-4\right)\left(x+4\right)\left(x-1\right)\\ 7,=x\left(x-y\right)+5\left(x-y\right)=\left(x-y\right)\left(x+5\right)\\ 8,=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)=4x\left(2x+1\right)\\ 9,=\left(2x-3y\right)\left(4x^2+6xy+9y^2\right)\\ 10,=\left(x-1\right)^2-4y^2=\left(x-2y-1\right)\left(x+2y-1\right)\)

Bài này khó dữ chị ơi! Em chỉ mới học lớp 4! Sorry chị nha!

em bó tay.com. vn

em mới lớp 5 thui chị ơi

\(a,4\left(2-x\right)^2+xy-2y\)

\(=4\left(2-x\right)^2-y\left(2-x\right)\)

\(=4-y\left(2-x\right)^2\left(2-x\right)\)

\(=\left(2-x\right)\left[\left(2-x\right)4-y\right]\)

\(=\left(2-x\right)\left(4x-8+y\right)\)

\(c,x^3+y^3+z^3-3xyz\)

\(=x^3+y^3+z^3+3x^2y-3x^2y+3xy^2-3xy^2-3xyz\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-3x^2y-3xy^2+z^3-3xyz\)

\(=\left(x+y\right)^3-3xy\left(x+1\right)+z^3-3xyz\)

\(=\left[\left(x+y\right)^3+z^3\right]-3xy\left(x+y\right)-3xyz\)

\(=\left[\left(x+y\right)+z\right]\left[\left(x+y\right)^2-\left(x+y\right)z+z^2\right]-3xy\left(x+y+z\right)\)

\(=\left(x+y+z\right)\left(x^2+2xy+y^2-xz-yz+z^2\right)-3xy\left(x+y+z\right)\)

\(=\left(x+y+z\right)\left(x^2+y^2+z^2-xy-xz-yz\right)\)

a) 4(2 - x)² + xy - 2y = 4(x - 2)² + y(x - 2) = (4x - 8 + y)(x - 2)

b) 2(x - 1)³ - 5(x - 1)² - (x - 1) = (x - 1)[2(x - 1)² - 5(x - 1) - 1]

= (x - 1)(2x² - 4x + 2 - 5x + 5 - 1) = (x - 1)(2x² - 9x + 6)

c) x³ + y³ + z³ - 3xyz = (x + y)(x² - xy + y²) + z³ - 3xyz

= (x + y)³ + z³ - 3xy(x + y) - 3xyz = (x + y + z)(x² + 2xy + y² - xz - yz + z²) - 3xy(x + y + z)

= (x + y + z)(x² + y² + z² - xz - yz + 2xy - 3xy) = (x + y + z)(x² + y² + z² - xy - yz - xz)

Thanks bạn nhen!

giúp mk phần a) nha

a) x^2-9x+20

= x^2+4x+5x+20

=(x^2+4x)+(5x+20)

=x(x+4)+5(x+4)

=(x+4)(x+5)

2: \(8xy-24xy+16x\)

\(=8x\cdot y-8x\cdot3y+8x\cdot2\)

\(=8x\left(y-3y+2\right)=8x\left(-2y+2\right)\)

\(=-16y\left(y-1\right)\)

3: \(xy-x=x\cdot y-x\cdot1=x\left(y-1\right)\)

11: \(2mx-4m2xy+6mx\)

\(=2mx-2my\cdot4y+2mx\cdot3\)

\(=2mx\left(1-4y+3\right)\)

\(=2mx\left(4-4y\right)=8mx\left(1-y\right)\)

12: \(7x^2y^5-14x^3y^4-21y^3\)

\(=7y^3\cdot x^2y^2-7y^3\cdot2x^3y-7y^3\cdot3\)

\(=7y^3\left(x^2y^2-2x^3y-3\right)\)

13: \(2\left(x-y\right)-a\left(x-y\right)\)

\(=2\cdot\left(x-y\right)-a\cdot\left(x-y\right)\)

\(=\left(x-y\right)\left(2-a\right)\)

a, x²+2x+1+x+1

=(x²+2x+2)+x

=(x²+2x+1²)+x

=(x+1)²+x

=(2x+1)²

=(2x-1).(2x+1 )

c,xy-y-2x-2

=(xy-2x)-(y-2)

=x.(y-2)-(y-2) 

=(y-2).x

e,xy+xz+y²+yz

=(xy+y²)+(xz+yz)

=y.(x+y)+z.(x+y)

=(x+y).(y+z)

d,x³+x²+x+1

=(x³+x²)+(x+1)

=x².(x+1)+(x+1)

=x².(x+1)

b,y²+xy+x+2y+1

=(y²+2y)+(xy+x+1)

=y.(y+2) + x.(y+2)

=(y+2).(y+x)

\(x^2-2x+1+x+1\)

\(=\left(x+1\right)^2+\left(x+1\right)\)

\(=\left(x+1\right)\left(x+1+1\right)\)

\(=\left(x+1\right)\left(x+2\right)\)