tìm n thuộc N biết :
a)3.5^n+2+4.5^n-3=19.5^10
b)11.6^x-1+2.6^x-1=11.6^11+2.6^13
c)\(\frac{2^{4-x}}{16^5}=32^6\)
tim n thuộc N biết :
a)3.5n+2+4.5n-3=19.510
b)11.6x-1+2.6x+1=11.611+2.613
c)\(\frac{2^{4-x}}{16^5}=32^6\)
A)3.5n.52+4.5n:53=19.9765625
5n(3.52+4:53)=185546875
5n.\(\frac{12}{5}\)=185546875
b) mình chắc chắn x = 12 không cần tk đâu
tim n thuộc N biết :
a)3.5n+2+4.5n-3
b)11.6x-1+2.6x+1=11.611+2.613
c)\(\frac{2^{4-x}}{16^5}=32^6\)
b)11.6x-1+2.6x+1=11.611+2.613
11.6x-1+2.6x+1 = 11. 612-1+ 2. 612+1
=> x= 12
c) 24-x / 165 = 326
24-x / 220= 230
24-x = 250
=> 4-x = 50
x= -46
c) \(\frac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\)
\(2^{4-x}:2^{20}=\left(2^5\right)^6\)
\(2^{4-x}=2^{30}.2^{20}\)
\(2^{4-x}=2^{50}\)
=> \(4-x=50\)
=> \(x=4-50=-46\)
vậy x = -46
tìm n thuộc N biết :
a)3.5n+2+4.5n-3=19.510
b)11.6x-1+2.6x-1=11.611+2.613
tim n thuộc N biết :
a)3.5n+2+4.5n-3=19.510
b)11.6x-1+2.6x+1=11.611+2.613
b) \(11\cdot6^{x-1}+2\cdot6^{x+1}=11\cdot6^{11}+2\cdot6^{13}\)
\(\Leftrightarrow11\cdot6^{x-1}+2\cdot6^{x+1}=11\cdot6^{12-1}+2\cdot6^{12+1}\)
\(\Leftrightarrow x=12\)
tìm x thuộc n
a)3.5n+2+4.5n-3=19.510
b)11.6x-1+2.6x+1=11.611+2.613
help me :(( mjk tick cho
a: \(\Leftrightarrow3\cdot5^n\cdot25+4\cdot5^n\cdot\dfrac{1}{125}=19\cdot5^{10}\)
\(\Leftrightarrow5^n\cdot\left(75+\dfrac{4}{125}\right)=19\cdot5^{10}\)
\(\Leftrightarrow5^n\simeq2472903,228\)(vô lý)
b: \(\Leftrightarrow6^x\cdot11\cdot\dfrac{1}{6}+2\cdot6^x\cdot6=11\cdot6^{11}+2\cdot6^{11}\cdot36\)
\(\Leftrightarrow6^x\left(\dfrac{11}{6}+12\right)=6^{11}\cdot83\)
\(\Leftrightarrow6^x=6^{12}\)
hay x=12
Tìm n \(\in N\)BIẾT :
a)3.5n+2+4.5n-3=19.510
b)11.6x-1+2.6x+1=11.611+2.613
c)\(\frac{2^{4-x}}{16^5}=32^6\)
\(\alpha\delta\phi\Phi\Omega\sigma\partial\infty\Delta\lambda\pi\exists\omega\sigma\lambda\approx\)
giúp mk nha!các bạn yêu ! hi!ai nhanh mk tk cho 3 tk nào mk !ngày nào mk cx tk !
tìm x biết :
a) (-2)x=87trên 83
b) 3x= 98trên 273.812
c)3.5x+2+4.5x-3=19.510
d) 11.6x-1+2.6x+1= 11.611+2.613
g) 33x+ 27x+9-33=330
h) 2.3x=10.312+8.274
Tìm x
a, (x-2)^5=(x-2)^3
b,(x-3)^3=(x-3)^2 c,11.6^x-1+2.6^x+1 =11.6^11+2.6^13
d, 6.8^x-1+8^x-1=6.8^19+8^21
a: =>(x-2)^3*[(x-2)^2-1]=0
=>(x-2)(x-3)(x-1)=0
=>\(x\in\left\{1;2;3\right\}\)
b: =>(x-3)^2*(x-3-1)=0
=>(x-3)(x-4)=0
=>x=3 hoặc x=4
c: =>\(11\cdot\dfrac{6^x}{6}+2\cdot6^x\cdot6=6^{11}\left(11+2\cdot6^2\right)\)
=>6^x(11/6+12)=6^12(11/6+12)
=>x=12
Tìm x :
11.6x-1+2.6x+1=11.611 + 2.613
=> \(11.6^{x-1}+2.6^{x-1+2}=11.6^{11}+2.6^{11+2}\)
=>\(11.6^{x-1}+2.6^{x-1}.6^2=11.6^{11}+2.6^{11}.6^2\)
=>\(6^{x-1}\left(11+2.6^2\right)=6^{11}\left(11+2.6^2\right)\)
=>\(6^{x-1}=6^{11}\)
=>\(x-1=11\)
=>\(x=12\)
Tíck giùm mik nha !