Tính
a)\(\frac{5}{6}\)+\(6\frac{5}{6}\).(\(11\frac{94}{1591}-6\frac{38}{1517}\)):\(8\frac{11}{43}\)
b) \(1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
c)\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}-\left(1,2.0,5\right):\frac{4}{5}\)
\(8\frac{1}{5}\times\left(11\frac{94}{1591}-6\frac{38}{1517}\right)\div8\frac{11}{43}\)
\(8\frac{1}{5}\)X \(\left(11\frac{94}{1592}-6\frac{38}{1517}\right):8\frac{11}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{17606}{1592}-\frac{9140}{1517}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{26708302}{2415064}-\frac{14550880}{2415064}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\frac{12157422}{2415064}:\frac{355}{43}\)
= \(\frac{49845430200000006}{12075320}:\frac{355}{43}\)
= \(\frac{5358383746500001}{1071684650}\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\\ =8\frac{1}{5}.5\frac{60}{1763}:8\frac{11}{43}\\ =41\frac{12}{43}:8\frac{11}{43}\\ =5\)
giá trị biểu thức A=\(8\frac{1}{5}\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
8 la hon so ma
6 cung la hon so
11 cung lka hon so
bai nay co giao lop em day roi nhung em moi lop 4 thoi
Tính: \(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{37.11.15.37}\right)\)
Thực hiện phép tính : \(8\frac{1}{5}\times \left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
tính
a , A = \(\left[\frac{4}{11}.\left(\frac{1}{25}\right)^0+\frac{7}{22}.2\right]^{2010}-\left(\frac{1}{2^2}:\frac{8^2}{4^4}\right)^{2009}\)
b , B =\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}+\left(1,2.0,5\right):\frac{4}{5}\)
\(a,A=\left[\frac{4}{11}.\left(\frac{1}{25}\right)^0+\frac{7}{22}.2\right]^{2010}-\left(\frac{1}{2^2}:\frac{8^2}{4^4}\right)^{2009}\)
\(A=\left(\frac{4}{11}.1+\frac{7}{11}\right)^{2010}-\left(\frac{1}{2^2}.2^2\right)^{2009}\)
\(A=1-1=0\)
\(b,B=\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}+\left(1,2.0,5\right):\frac{4}{5}\)
\(B=\frac{0,8:1}{\frac{3}{5}}+\frac{\left(1\right):\frac{4}{7}}{\left(\frac{59}{9}-\frac{13}{4}\right).36}\)
\(B=0,8.\frac{5}{3}+\frac{\frac{7}{4}}{\frac{119}{36}.36}\)
\(B=\frac{4}{3}+\frac{7}{4}.\frac{1}{119}\)
\(B=\frac{4}{3}+\frac{1}{68}=\frac{275}{204}\)
Tính
\(a,\frac{5}{6}+6\frac{5}{6}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(b,1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
Tớ ko bít phải làm sao bây giờ ?
tô ? ko ? bít ?
-_-! ai thick tích cu !
mk chỉ tính đc kết quả phần a) thôi..
a, = 5
\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}+\left(1,2.0,5\right):\frac{4}{5}\)
Ta có: \(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\frac{\left(1,2\cdot0,5\right)}{\frac{4}{5}}\)
\(=\frac{\frac{4}{5}:\left(\frac{4}{5}\cdot\frac{5}{4}\right)}{\frac{16}{25}-\frac{1}{25}}+\frac{\left(\frac{27}{25}-\frac{2}{25}\right)\cdot\frac{7}{4}}{\left(\frac{59}{9}-\frac{13}{4}\right)\cdot\frac{36}{17}}+\frac{6}{5}\cdot\frac{1}{2}\cdot\frac{5}{4}\)
\(=\frac{\frac{4}{5}}{\frac{3}{5}}+\frac{\frac{7}{4}}{\frac{119}{36}\cdot\frac{36}{17}}+\frac{3}{4}\)
\(=\frac{4}{5}\cdot\frac{5}{3}+\frac{7}{4}\cdot\frac{1}{7}+\frac{3}{4}=\frac{4}{3}+\frac{1}{4}+\frac{3}{4}=\frac{7}{3}\)
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