so sanh \(\sqrt{49-16}\) va\(\sqrt{49}\) -\(\sqrt{16}\)
\(\sqrt{0,04}\) va \(0,04\)
\(8\) va \(\sqrt{8}\)
a,\(\sqrt{1}+\sqrt{9}+\sqrt{25}+\sqrt{49}+\sqrt{81}\) c\(\sqrt{0,04}+\sqrt{0,09}+\sqrt{0,16}\)
b,\(\sqrt{\dfrac{1}{4}}+\sqrt{\dfrac{1}{9}}+\sqrt{\dfrac{1}{36}}+\sqrt{\dfrac{1}{16}}\) e\(\sqrt{2^2}+\sqrt{4^2}+\sqrt{\left(-6^2\right)}+\sqrt{\left(-8^2\right)}\)
j,\(\sqrt{1,44}-\sqrt{1,69}+\sqrt{1,96}\)
g, \(\sqrt{\dfrac{4}{25}}+\sqrt{\dfrac{25}{4}}+\sqrt{\dfrac{81}{100}}+\sqrt{\dfrac{9}{16}}\)
d\(\sqrt{81}-\sqrt{64}+\sqrt{49}\)
a)\(\sqrt{1}\)+\(\sqrt{9}\)+\(\sqrt{25}\)+\(\sqrt{49}\)+\(\sqrt{81}\)
=1+3+5+7+9
=25
b)=\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{6}\)+\(\dfrac{1}{4}\)
=\(\dfrac{6}{12}\)+\(\dfrac{4}{12}\)+\(\dfrac{2}{12}\)+\(\dfrac{3}{12}\)
=\(\dfrac{15}{12}\)
c) =0,2+0.3+0,4
= 0.9
d) =9-8+7
=8
j) =1,2-1,3+1.4
= (-0,1)+1,4
=1,4
g) \(\dfrac{2}{5}\)+\(\dfrac{5}{2}\)+\(\dfrac{9}{10}\)+\(\dfrac{3}{4}\)
= (\(\dfrac{4}{10}\)+\(\dfrac{15}{10}\)+\(\dfrac{9}{10}\))+\(\dfrac{3}{4}\)
= \(\dfrac{14}{5}\)+\(\dfrac{3}{4}\)
=\(\dfrac{56}{20}\)+\(\dfrac{15}{20}\)
= \(\dfrac{71}{20}\)
Nhớ tick cho mk nha~
bai 1 : tinh
\(\sqrt{49}\); \(\sqrt{-49}\) ; \(\sqrt{0,01}\)
bai 2 : so sanh
a,15 va \(\sqrt{235}\)
b,\(\sqrt{7}\)+ \(\sqrt{15}\)va 7
bai 3 ; tinh hop ly
A = 7,3.10,5-7,3.15+2,7.10,5-15.2,7
bai 4 : so sanh
a, 1,(05) va 0,(31)
b, 3,0(21) va 3,021
c,0,001 va 0,(001)
d,1,(31) va 1,(313)
So sanh
16 va \(\sqrt{15}\). \(\sqrt{17}\)
Ta có :
√15.√17= √16-1.√16+1
=√162-1
Vì 162-1 < 162 nên
√162-1< √162
Vậy 16> √15.√17
\(\sqrt{15}\cdot\sqrt{17}=\sqrt{255}< \sqrt{256}=16\)
\(16=\sqrt{16^2}\)
\(16^2=\left(15+1\right).\left(17-1\right)=15.17-15+17=15.17+2\)
Mà \(15.17+2>15.17\)
\(\Leftrightarrow\sqrt{15.17+2}>\sqrt{15.17}\)
\(\Leftrightarrow16>\sqrt{15}.\sqrt{17}\)
\(\sqrt{24}+\sqrt{63}+3\)va 16 .so sanh
Ta có \(16=5+8+3=\sqrt{25}+\sqrt{64}+3.\)
do : \(25>24\Rightarrow\sqrt{25}>\sqrt{24}\); \(64>63\Rightarrow\sqrt{64}>\sqrt{63}\)
=> \(\sqrt{25}+\sqrt{64}+3>\sqrt{24}+\sqrt{63}+3\)
=> \(\sqrt{24}+\sqrt{63}+3< 16\)
ta có căn64>căn63 (1)
căn25>căn24 (2)
167>3 (3)
cộng vế theo vế (1);(2);(3)
=>căn64+căn25+167=16>căn24+căn63+3
1/ so sánh
a/\(\sqrt{25+9}\)\(va\sqrt{25}+\sqrt{9}\)
b/\(\sqrt{0,04}+\sqrt{0,25}\) và \(5,4+7\sqrt{0,36}\)
\(0,5\sqrt{100}-\sqrt[]{\frac{4}{25}}va\left(\sqrt{\frac{10}{9}}-\sqrt{\frac{9}{16}}\right):5\)
so sanh
(1+1_1/4+1_1/2+1_3/4+2+2_1/4+2_1/2+2_3/4+......+4_3/4) : 23 tính nhanh !!!!! Ai nhanh mình kêu anh chị mình vào nha !! Mình cần gấp lắm !! Cảm ơn mọi người
so sanh \(\sqrt{8}\)va \(\sqrt{5}\)+1
có \(\sqrt{8}\)<\(\sqrt{9}\)=3
\(\sqrt{5}\)+1>\(\sqrt{4}\)+1=3
suy ra \(\sqrt{5}\)+1>\(\sqrt{8}\)
\(64.\left(\dfrac{-1}{8}\right)^2+3,5.\sqrt{\dfrac{16}{49}}-\sqrt{49}:4\)
Trong các số sau đây số nào có căn bậc hai cho biết căn bậc hai không âm của số đó :
36 ; -3600 ; - 0,125 ; 36/49 ; 121 ; 0,04 ; \(\sqrt{\frac{16}{81}}\); \(\sqrt{\frac{49}{9}}\)
cây kiếm hay cây rùi nặng hơn vậy