\(\left(\frac{1}{8}\right)^4:\left(-\frac{1}{4}\right)^5\)

\(=\frac{1}{8^4}:\frac{-1}{4^5}\)

\(=\frac{1}{2^{12}}:\frac{-1}{2^{10}}\)

\(=\frac{1}{2^{12}}.\frac{2^{10}}{-1}=\frac{1}{-4}\)

a.2.8.16=2^1.2^3.2^4=2^8

b.25.5.125=5^2.5^1.5^3=5^6

1. a. 2.8.16=16.16=\(16^2\)

    b. 25.5.125=125.125=\(125^2\)

    c. \(\frac{2}{3}.\frac{4}{9}.\frac{8}{27}=\frac{8}{27}.\frac{8}{27}=\left(\frac{8}{27}\right)^2\)

k cho em nha, em nhớ là em bày chị rồi mà

c.2^6/3^6

l) 27^8=(3³)⁸=3²⁴

=>27⁸:3²²=3²⁴:3²²

=3^24-22=3²

m) 8^4=(2³)⁴=2¹²

4⁵=(2²)⁵=2¹⁰

=>8⁴:4⁵=2¹²:2¹⁰

=2^12-10=2²

a) \(27^8:3^{22}\)

\(=\left(3^3\right)^8:3^{22}\)

\(=3^{24}:3^{22}=3^{24-22}\)

\(=3^2\)

b) \(8^4:4^5\)

\(=\left(2^3\right)^4:\left(2^2\right)^5\)

\(=2^{12}:2^{10}=2^{12-10}=2^2\)

d)\(-\frac{8}{27}=\frac{\left(-2\right)^3}{3^3}=\left(-\frac{2}{3}\right)^3\)

h)\(-\frac{27}{64}=\frac{\left(-3\right)^3}{4^3}=\left(-\frac{3}{4}\right)^3\)

\(\frac{-8}{27}=\frac{\left(-2\right)^3}{3^3}\)

\(\frac{-27}{64}=\frac{-3^3}{4^3}\)

\(a,=\frac{2}{3}.\frac{2^2}{3^2}.\frac{2^3}{3^3}=\frac{2.2^2.2^3}{3.3^2.3^3}=\frac{2^6}{3^6}\)

\(b,=\frac{3}{4}.\frac{3^2}{4^2}.\frac{3^3}{4^3}=\frac{3.3^2.3^3}{4.4^2.4^3}=\frac{3^6}{4^4}\)

Mk nhầm chút nhé câu b\(=\frac{3^6}{4^6}\)

thanks

Ta có:

\(\begin{array}{l}{\left( {\frac{1}{4}} \right)^8} = {[{\left( {\frac{1}{2}} \right)^2}]^8} = {(\frac{1}{2})^{2.8}} = {(\frac{1}{2})^{16}};\\{\left( {\frac{1}{8}} \right)^3} = {[{(\frac{1}{2})^3}]^3} = {(\frac{1}{2})^{3.3}} = {(\frac{1}{2})^9}\end{array}\)