a, x^7. x^3= x^10

b, (x^2)^5=x^10

c, x^12: x^2= x^10

\(2^{24}=\left(2^3\right)^{21}=8^{21}\)

2²⁴= 8⁸

`2^24 = 2^(3.8) = (2^3)^8 = 8^8`

\(\text{Câu hỏi :}\)

\(\text{5 x 5 x 5 x 5 x 3 x 3 = ?}\)

\(\text{Trả lời :}\)

\(\text{5 x 5 x 5 x 5 x 3 x 3 = 5^4 x 3^2}\)

\(5\times5\times5\times5\times3\times3=5^4\times3^2\)

5x5x5x5x3x3= 5³x3²

\(\left(\frac{4}{9}\right)^2\)

\(\left(\frac{4}{9}\right)^2\)

\(\left(\frac{2}{3}\right)^4\)

\(=\frac{4^2}{9^2}=\left(\frac{4}{9}\right)^2\)

dễ mà : A=2^21-1

cách giải chờ sau đi
 

\(\frac{8}{125}\)không thể viết được dưới dạng một luỹ thừa.

\(\frac{8}{27}=\left(\frac{2}{3}\right)^3\)

\(A=1+2+2^2+2^3+...+2^{100}\)

\(\Rightarrow2A=2+2^2+2^3+...+2^{200}+2^{201}\)

\(2A-A=A=\left(2+2^2+2^3+...+2^{201}\right)-\left(1+2+2^2+2^3+...+2^{200}\right)\)

\(\Rightarrow A=2^{201}-1\Rightarrow A+1=2^{201}-1+1=2^{201}\)

ta có
A= 1+2+2²+2³+...+2²⁰⁰
2A= 2+2²+2³+...+2²⁰¹
2A-A=(2+2²+2³+...+2²⁰¹)-(1+2+2²+2³+...+2²⁰⁰)
A=2²⁰¹ - 1
A+1=2²⁰¹

 

a) \(3^5.4^5=\left(3.4\right)^5=12^5\)

b) \(8^5.2^3=\left(2^3\right)^5.2^3=2^{15}.2^3=2^{15+3}=2^{18}\)

\(3^5.4^5=3+4^5=7^5\)

\(8^5.2^3=8+2^{5+3}=10^8\)

Ko biết nữa !

a, 12⁵

b, 2¹⁸

Hok tốt