\(\left(5^2\times2^3-7^3\times2\right)\div2\times6-7\div2^5\)

\(=\left(25\times8-343\times2\right)\div2\times6-7\div32\)

\(=\left(200-686\right)\div2\times6-7\div32\)

\(=-486\div2\times6-7\div32\)

\(=-1458-0,21875\)

\(=-1458,21875\)

\(36\cdot4-4\cdot\left[82-7\cdot11\right]^2:4-2016^0\)

=9-1-5^2

=8-25=-17

(24*5-5^2*2):(5*2)-3

=(120-50)/10-3

=7-3=4

\(\left(5.2^2-20\right):\left(5+3^2:6\right)\\ =\left(5.4-20\right):\left(5+9:6\right)\\ =\left(20-20\right):\left(5+\dfrac{3}{2}\right)\\ =1:\dfrac{13}{2}=\dfrac{2}{13}\)

(5*2^2-20):5+3^2/6

=(20-20):5+9/6

=3/2

viết hẳn ra đi đừng viết mở ngoặc rồi đóng ngoặc

[(27^4:9^5)+(625^3:125^4)]-2^3

=[(531441:59049)+(244140625:244140625)]-8

=[9+1]-8

=10-8

=2

Nếu dk thì cko mik nhoa

bạn viết khó hiểu quá

                         =(-5)² .(7/45+11/45)

                          =25 . 2/5

                                =10

\(\left(-5\right)^2.\frac{7}{45}+\left(-5\right)^2.\frac{11}{45}\)

\(=\left(-5\right)^2.\left(\frac{7}{45}+\frac{11}{45}\right)\)

\(=25.\frac{2}{5}\)

\(=10\)

làm ra phép tính bn ơi

* Đề bài như này ạ ? * :

10² - [ 60 : ( 5² - 3 . 5 ) ]

= 100 - [ 60 : 10 ]

= 100 - 6

= 94

Học tốt ạ;-;

10²-[60:(5²-3.5)]

=100-[60:(25-15)]

=100-[60:10]

=100-6

=94