Rút gọn
a) \(\left(x+2y\right)^2+4y\)
b) \(\left(2x-3\right)\left(2x+3\right)-4x^2\)
c)\(\left(3x+1\right)^2-\left(x+1\right)\left(x-1\right)\)
Rút gọn biểu thức :
a) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)
b) \(\left(4x^2-3y\right).2y-\left(3x^2-4y\right).3y\)
c) \(3y^2\left[\left(2x-1\right)+y+1\right]-y\left(1-y-y^2\right)+y\)
a) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)
\(=3x^2-6x-5x+5x^2-8x^2+24\)
\(=24-11x\)
b) \(\left(4x^2-3y\right)\cdot2y-\left(3x^2-4y\right)\cdot3y\)
\(=8x^2y-6y^2-9x^2y+12y^2\)
\(=6y^2-x^2y\)
c) \(3y^2\left[\left(2x-1\right)+y+1\right]-y\left(1-y-y^2\right)+y\)
\(=3y^2\cdot\left(2x-1+y+1\right)-y\cdot\left(1-y-y^2\right)+y\)
\(=6xy^2-3y^2+3y^3+3y^2-y+y^2+y^3+y\)
\(=4y^3+y^2+6xy^2\)
Bài 1 :Rút gọn
\(\left(4x^2-3y\right)a2y-\left(3x^2-4y\right)3y\)
\(4x^2\left(5x-3y\right)-x^2\left(4x+y\right)\)
\(2ax^2-a\left(1+2x^2\right)-\left\{a-x\left(x+a\right)\right\}\)
Bài 2:Tìm x
a)\(2x\left(x+1\right)-x^2\left(x+2\right)+x^3-x+1=0\)
b)\(4x\left(3x+2\right)-6x\left(2x+5\right)+21\left(x-1\right)=0\)
Bài 3:Rút gọn
\(x\left(1+x+x^2+...+x^9\right)-\left(1+x+x^2+...+x^9\right)\)
1. Thực hiện phép tính
a) \(\left(3x^2y-6xy+9x\right).\left(\frac{-4}{3xy}\right)\)
b) \(\left(\frac{1}{3}x+2y\right).\left(\frac{1}{9}x^2-\frac{2}{3}xy+4y^2\right)\)
c) (x-2) ( \(x^2-5x+1\)) + x ( \(x^2+11\))
d) (x - 3y ) \(\left(x^2+3xy+9y^2\right)\)
e) \(\left(3+x\right)\left(x^2+3x-5\right)\)
f) (x+2)(x-2)-(2x+1)
2. Rút gọn biểu thức
a ) \(\left(3x+2\right)^2+2\left(2+3x\right)\left(1-2y\right)+\left(2y-1\right)^2\)
b ) \(\left(3x+1\right)^2-2\left(3x+1\right)\left(3x+5\right)+\left(3x+5\right)^2\)
c) \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
cau a : (3x^2y-6xy+9x)(-4/3xy)
=-4/3xy.3x^2y+4/3xy.6xy-4/3xy.9x
=-4x+8-8y
cau b : (1/3x+2y)(1/9x^2-2/3xy+4y^2)
=(1/3)^3-2/9x^2y+8y^3+4/3xy^2+2/9x^2y-4/3xy^2+8y^3
=(1/3)^3 + (2y)^3x-2
cau c : (x-2)(x^2-5x+1)+x(x^2+11)
=x^3-5x^2+x-2x^2+10x-2+x^3+11x
=2x^3-7x^2+22x-2
cau d := x^3 + 6xy^2 -27y^3
cau e := x^3 + 3x^2 -5x - 3x^2y - 9xy = 15y
cau f := x^2-2x+2x -4-2x-1
= x(x-2)-5
cau e la + 15y ko phai =15y
Rút gọn các biểu thức:
\(A=\left(x+3\right)\left(x^2-3x+9\right)-\left(54+x^3\right)\)
\(B=\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(C=\left(2x+1\right)^2+\left(1-3x\right)^2+2\left(2x+1\right)\left(3x-1\right)\)
\(D=\left(x-2\right)\left(x^2+2x+4\right)-\left(x+1\right)^3+3\left(x-1\right)\left(x+1\right)\)
a)
\(A=\left(x+3\right)\left(x^2-3x+9\right)-\left(54+x^3\right)\)
\(=x^3-3x^2+9x+3x^2-9x+27-54-x^3\)
\(=-27\)
or
\(A=x^3+27-54-x^3=-27\)
b)
\(B=\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=8x^3+y^3-8x^3+y^3=2y^3\)
c)
\(C=\left(2x+1\right)^2+\left(1-3x\right)^2+2\left(2x+1\right)\left(3x-1\right)\)
\(=\left(2x+1+3x-1\right)^2=\left(5x\right)^2=25x^2\)
d)
\(D=\left(x-2\right)\left(x^2+2x+4\right)-\left(x+1\right)^3+3\left(x-1\right)\left(x+1\right)\)
\(=x^3-8-\left(x-1\right)^3+3\left(x-1\right)\left(x+1\right)\)
\(=6x^2-3x-10\)
Rút gọn:
a) \(\left(x-2y\right)\left(3xy+5y^2+x^2\right)\)
b) \(\left(2x+3\right)\left(4x^2-6x+9\right)-2\left(4x^3-1\right)\)
c) \(\left(x-3y\right)^2-2\left(x-3y\right)\left(3y+x\right)+\left(x+3y\right)^2\)
d) \(\left(x^2-x+1\right)\left(x-1\right)-3x\left(x+1\right)^2\)
Rút gọn các biểu thức sau
a, \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
a: \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
\(=2x\left(4x^2-4x+1\right)-3x\left(x^2-9\right)-4x\left(x^2+2x+1\right)\)
\(=8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x\)
\(=x^3-16x^2+25x\)
Rút gọn các biểu thức :
a, \(\left(3x+5\right)^2+\left(3x-5\right)^2-\left(3x+2\right)\left(3x-2\right)\)
b, \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
\(c,\left(x+y-z\right)^2+2\left(z-x-y\right)\left(x+y\right)+\left(x+y\right)^2\)
\(a,\left(3x+5\right)^2+\left(3x-5\right)^2-\left(3x+2\right)\left(3x-2\right)=9x^2+30x+25+9x^2-30x+25-9x^2+4=9x^2+54\)
\(b,BT=2x\left(4x^2-4x+1\right)-3x\left(x^2-9\right)-4x\left(x^2+2x+1\right)=8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x=x^3-16x^2+25x\)
\(c,BT=\left(x+y-z\right)^2-2\left(x+y-z\right)\left(x+y\right)+\left(x+y\right)^2=\left(x+y-z-x-y\right)^2=z^2\)
Bài 1: Rút gọn các biểu thức sau:
a) \(3x^2\) - 2x( 5+ 1,5x) +10
b) 7x ( 4y- x) + 4y( y-7x) - 2( \(2y^2\) - 3,5x)
c) \(\left\{2x-3\left(x-1\right)-5\left[x-4\left(3-2x\right)+10\right]\right\}.\left(-2x\right)\)
Bài 2: Tìm x, biết:
a) 3( 2x -1) - 5( x -3) + 6( 3x -4) = 24
b) \(2x^2+3\left(x^2-1\right)=5x\left(x+1\right)\)
c) \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=3\)
d) \(3x\left(x+1\right)-2x\left(x+2\right)=-1-x\)
Bài 3: Tính giá trị của các biểu thức sau:
a)\(A=x^2\left(x+y\right)-y\left(x^2+y^2\right)+2002\) Với \(x=1;y=-1\)
b) \(B=5x\left(x-4y\right)-4y\left(y-5x\right)-\dfrac{11}{20}\) Với \(x=-0,6;y=-0,75\)
Bài 4: Chứng tỏ rằng giá trị của biểu thức sau không phụ thuộc vào giá trị biến:
a) \(2\left(2x+x^2\right)-x^2\left(x+2\right)+\left(x^3-4x+3\right)\)
b) \(z\left(y-x\right)+y\left(z-x\right)+x\left(y+z\right)-2yz+100\)
c) \(2y\left(y^2+y+1\right)-2y^2\left(y+1\right)-2\left(y+10\right)\)
Bài 5: Tính giá trị của biểu thức:
a) \(A=\left(x-3\right)\left(x-7\right)-\left(2x-5\right)\left(x-1\right)\) Với \(x=0;x=1;x=-1\)
b) \(B=\left(3x+5\right)\left(2x-1\right)+\left(4x-1\right)\left(3x+2\right)\) Với \(\left|x\right|=2\)
c) \(C=\left(2x+y\right)\left(2z+y\right)+\left(x-y\right)\left(y-z\right)\) Với \(x=1;y=1;z=\left|1\right|\)
Bài 1:
a) \(3x^2-2x(5+1,5x)+10=3x^2-(10x+3x^2)+10\)
\(=10-10x=10(1-x)\)
b) \(7x(4y-x)+4y(y-7x)-2(2y^2-3,5x)\)
\(=28xy-7x^2+(4y^2-28xy)-(4y^2-7x)\)
\(=-7x^2+7x=7x(1-x)\)
c)
\(\left\{2x-3(x-1)-5[x-4(3-2x)+10]\right\}.(-2x)\)
\(\left\{2x-(3x-3)-5[x-(12-8x)+10]\right\}(-2x)\)
\(=\left\{3-x-5[9x-2]\right\}(-2x)\)
\(=\left\{3-x-45x+10\right\}(-2x)=(13-46x)(-2x)=2x(46x-13)\)
Bài 2:
a) \(3(2x-1)-5(x-3)+6(3x-4)=24\)
\(\Leftrightarrow (6x-3)-(5x-15)+(18x-24)=24\)
\(\Leftrightarrow 19x-12=24\Rightarrow 19x=36\Rightarrow x=\frac{36}{19}\)
b)
\(\Leftrightarrow 2x^2+3(x^2-1)-5x(x+1)=0\)
\(\Leftrightarrow 2x^2+3x^2-3-5x^2-5x=0\)
\(\Leftrightarrow -5x-3=0\Rightarrow x=-\frac{3}{5}\)
\(2x^2+3(x^2-1)=5x(x+1)\)
Bài 2:
c) \(2x(5-3x)+2x(3x-5)-3(x-7)=3\)
\(\Leftrightarrow 2x(5-3x)-2x(5-3x)-3(x-7)=3\)
\(\Leftrightarrow -3(x-7)=3\)
\(\Leftrightarrow x-7=-1\Rightarrow x=6\)
d)
\(3x(x+1)-2x(x+2)=-1-x\)
\(\Leftrightarrow 3x^2+3x-(2x^2+4x)+x+1=0\)
\(\Leftrightarrow x^2+1=0\)
Vô lý vì \(x^2+1\geq 0+1=1>0\) với mọi $x$
Vậy không tồn tại $x$ thỏa mãn.
Rút gọn:
a) \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
b) \(\left(a-b+c\right)^2-\left(b-c\right)^2+2ab-2ac\)
a) \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
\(=2x\left(4x^2-4x+1\right)-3x\left(x^2-9\right)-4x\left(x^2+2x+1\right)\)
\(=8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x\)
\(=x^3-16x^2+25x\)
b) \(\left(a-b+c\right)^2-\left(b-c\right)^2+2ab-2ac\)
\(=a^2+b^2+c^2-2ab+2ac-2bc-\left(b^2-2bc+c^2\right)+2ab-2ac\)
\(=a^2+b^2+c^2-2ab+2ac-2bc-b^2+2bc-c^2+2ab-2ac\)
\(=a^2\)
Siêu sao bóng đá Lần sau nhớ gõ Latex nhé, tiêu đề bạn nên viết rõ ra như là Toán lớp 8 nhân đa thứ với đa thức chẳng hạn