tính nhanh ;\(\frac{3737.43-4343.37}{2+4+6+......+100}\)
ta có
3737 . 43 - 4343 . 37 = ( 3700 + 37) . 43 - (4300+43) . 37
= 3700 . 43 + 37 .43 - 4300 . 37 + 43 . 37
= 43 . 37 . ( 3700 . 43 - 4300 . 37)
= 1591 . (159100 - 159100)
= 1591 . 0
= 0
vậy \(\frac{3737.43-4343.37}{2+4+6+....+100}\)= 0
đap số 0
1 nha bạn
Chúc các bạn học giỏi
Tết vui vẻ nha
tính
a. A= 101+100+99+98+....+3+2+1/101-100+99-98+...+3-2+1
b,B= 3737.43-4343.37/2+4+6+...+100
tính D=\(\frac{3737.43-4343.37}{2+4+6+...+100}\)
giúp mk nhé
\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.101.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.4343-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.\left(37-37\right)}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.0}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{0}{2+4+6+...+100}\)
\(\Rightarrow D=0\)
Vậy D = 0
\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
Biến đổi tử số ta có :
\(D_1=3737.43-4343.37\)
\(\Rightarrow D_1=37.101.43-4343.37\)
\(\Rightarrow D_1=\left(43.101\right).37-4343.37\)
\(\Rightarrow D_1=4343.37-4343.37\)
\(\Rightarrow D_1=4343\left(37-37\right)=4343.0=0\)
Thay vào , ta có :
\(\frac{0}{2+4+6+...+100}=0\div\left(2+4+6+...+100\right)=0\)
Vậy : D = 0
Tính \(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(D=\frac{37.101.43-43.101.37}{2+4+6+..+100}=\frac{0}{2+4+...+100}=0\)
\(\dfrac{3737.43-4343.37}{2+4+6+...+100}\)
`(3737.43-4343.37)/(2+4+...+100)`
`= (101.37.43-101.43.37)/(2+4+...+100)`
`=0/(2+4+...+100) = 0`
\(\dfrac{3737.43-4343.37}{2+4+6+...+100}\)
Gọi \(A=2+4+6+...+100\)
Số số hạng: \(\left(100-2\right):2+1=50\)
Tổng dạy: \(\left(2+100\right).50:2=2550\)
Gọi \(B=3737.43-4343.37\)
\(B=101.37.43-101.43.37=0\)
\(\Rightarrow\dfrac{3737.43-4343.37}{2+4+6+...+100}=\dfrac{0}{2550}=0\)
Tính nhanh
a)A=\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b)\(\frac{3737.43-4343.37}{2+4+6+...+100}\)
B=3737.43 - 4343.37 /2+4+6+...+100
C=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
Các bạn tính giùm mình với
B=\(\frac{3737.43-4343.37}{2+4+6+..+100}=\frac{101.37.43-101.43.37}{2+4+6+...+100}\)=\(\frac{101\left(37.43-43.37\right)}{2+4+6+...100}=\frac{0}{2+4+6+...+100}\)=0
C=\(\frac{101+100+99+...+2+1}{101-100+99-98+...+3-2+1}=\frac{\left(101+1\right)101:2}{\left(101-100\right)+\left(99-98\right)+...+\left(3-2\right)+1}\)(dưới mẫu có 51 số 1)
=\(\frac{5151}{51}\)=101
Đào Thụy Anh làm phần thứ 1 thì thừa phần thứ 2 thì thiếu
1/ Tinh nhanh
a/ 48 .45 + 55 . 48
b/ 57 . 37 + 57 . 23 + 57 . 40
c/ 25 . 5 . 4 . 17 . 2
d/ 127 . 45 + 55 . 127 - 27 . 100
e/ 543 + 165 + 457 + 35
g/ 13 . 58 . 4 + 32 . 26 . 2 + 52 . 10
h/ 25 . 5 . 4 . 17 . 2
k/ (3737 . 43 - 4343 . 37 ) : ( 2 + 4 + 6 + ... + 100 )
i/ 1 + 5 + 9 + ... + 29 + 33 + 37
Giup mik bai nay nha,Thank cac ban nhieu
a)48.45+55.48=(45+55).48=100.48=4800
b)57.37+57.23+57.40=57.(23+37+40)=57.100=5700
c)25.5.4.17.2=(25.4).(5.17.2)=100.170=17000
d)127.45+55.127-27.100=127.(45+55)-(27.100)=127.100-27.100=(127-27).100=100.100=10000
e)543+165+457+35=(543+457)+(165+35)=1000+200=1200
g)13.58.4+32.6.2+52.10=(52.58)+(52.32)+52.10=52.(58+32+10)=52.100=5200
h)25.5.4.17.2=(25.4).(17.2.5)=100.170=17000
k)(3737.43-4343.37):(2+4+6+...+100)=(37.101.43-43.101.37):(2+4+6+...+100)=0.(2+4+6+...+100)=0
i)1+5+9+...+29+33+37=(1+37)+(5+33)+...=190
a=4800
b=5700
c=17000
d=10000
e=1200
...
phần còn lại bạn tự làm nhé
a/ 48.45+48.55
=48.(45+55)
=48.100
=4800
các bài sau tương tự nhé
Tính
a) \(C=\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b) \(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(D=\frac{37.101.43-43.101.37}{2+4+6+...+100}\)
\(D=\frac{37.\left(101.43-43.101\right)}{2+4+6+...+100}\)
\(D=\frac{37.0}{2+4+6+...+100}\)
\(D=\frac{0}{2+4+6+...+100}=0\)
Vậy \(D=0\)
ngắn gọn
