Tính thuận tiện nhất
2/7×9 + 2/9×11 + 2/11×13 ....+ 2/75×77
tính bằng cách thuận tiện nhất
a, 20,23 x 21 + 20,23 x 80 - 20,23
b, 5/13 x 7/11 + 5/13 x 2/11 + 8/13 x 9/11
\(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\left(\dfrac{7}{11}+\dfrac{2}{11}\right)+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\dfrac{9}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{9}{11}\times\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{9}{11}\times1\)
\(=\dfrac{9}{11}\)
a) \(20,23\times21+20,23\times80-20,23\)
\(=20,23\times\left(21+80-1\right)\)
\(=20,23\times100\)
\(=2023\)
\(\dfrac{5}{13}\) \(\times\) \(\dfrac{7}{11}\) + \(\dfrac{5}{13}\) \(\times\) \(\dfrac{2}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\left(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}\right)\)+ \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\)\(\times\) (\(\dfrac{7}{11}\) + \(\dfrac{2}{11}\)) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\) \(\times\) \(\dfrac{9}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{9}{11}\) \(\times\)( \(\dfrac{5}{13}\) +\(\dfrac{8}{13}\))
= \(\dfrac{9}{11}\) \(\times\) 1
= \(\dfrac{9}{11}\)
tính bằng cách thuận tiện nhất
a,3/5*7/9+11/9*3/5-3/10
b,14/13chia 1/2+3/13*2-2*7/13
a,3/5*7/9+11/9*3/5-3/10=3/5*(7/9+11/9)-3/10
=3/5*18/9-3/10
=3/5*2-3/10
=6/5-3/10
=12/10-3/10
=9/10
b,14/13:1/2+3/13*2-2*7/13=14/13*2+3/13*2-2*7/13
=2*(14/13+3/13-7/13)
=2*10/13
=20/13
a/ ( 7/9 + 11/9 ) x 3/5 - 3/10
= 2 x 3/5 - 3/10
= 6/5 - 3/10
= 9/10
b/ 14/13 : 1/2 + 3/13 x 2 - 2 x 7/13
14/13 x 2/1 + 3/13 x 2 - 2 x 7/13
2 x ( 14/13 + 3/13 - 7/13 )
2 x 10/13
20/13
BÀI 3: TÍNH BẰNG CÁCH THUẬN TIỆN NHẤT
245 x 11 + 11 x 365 78 x 75 + 75 x 89 + 75 x 123 2 x 250 x 50 x 8
(76 : 7) x 4 (372 x 15) x 9 (56 x 23 x 4) : 7
tính bằng cách thuận tiện nhất :
a)(976+865)+135 =
b)(2/5 +7/9)+3/5=
19/11+(8/13+3/11)=
Tính bằng cách thuận tiện nhất
A)3/5*7/9+11/9*3/5-3/10=
-B)14/13:1/2+3/12*2-2*7/13=
1 tính bằng cách thuận tiện nhất
a)3/5*7/9+11/9*3/5-3/10
b)14/13:1/2+3/13*2-2*7/13
giải đầy đủ nha!!!
Tính bằng cách thuận tiện nhất: a)1678*24+77*1678-1678 b)2/5 + 4/11 + 3/5 + 18/11 + 1/4 +1/6 c) 7/9x7 + 7/9x4 - 7/9x10 e)13/7x 2/3 - 6/7 : 6/4 +14/21 g)5/9x2/6+-5/9x3/6
a) \(1678\cdot24+77\cdot1678-1678=1678\left(24+77-1\right)=167800\)
b) Ta có: \(\dfrac{2}{5}+\dfrac{4}{11}+\dfrac{3}{5}+\dfrac{18}{11}+\dfrac{1}{4}+\dfrac{1}{6}\)
\(=\left(\dfrac{2}{5}+\dfrac{3}{5}\right)+\left(\dfrac{4}{11}+\dfrac{18}{11}\right)+\dfrac{1}{4}+\dfrac{1}{6}\)
\(=3+\dfrac{1}{4}+\dfrac{1}{6}\)
\(=\dfrac{36}{12}+\dfrac{3}{12}+\dfrac{2}{12}=\dfrac{41}{12}\)
c) \(\dfrac{7}{9\cdot7}+\dfrac{7}{9\cdot4}-\dfrac{7}{9\cdot10}\)
\(=\dfrac{7}{9}\left(\dfrac{1}{7}+\dfrac{1}{4}-\dfrac{1}{10}\right)\)
\(=\dfrac{7}{9}\cdot\left(\dfrac{20}{140}+\dfrac{35}{140}-\dfrac{14}{140}\right)\)
\(=\dfrac{7}{9}\cdot\dfrac{41}{140}=\dfrac{41}{180}\)
Tính thuận tiện:
a) 3/5 × 7/9 + 11/9 × 3/5 - 3/10
b) 14/13 : 1/2 + 3/13 × 2 - 2 × 7/13
A)\(\frac{3}{5}\times\frac{7}{9}+\frac{11}{9}\times\frac{3}{5}-\frac{3}{10}\\ =\frac{3}{5}\times\left(\frac{7}{9}+\frac{11}{9}\right)-\frac{3}{10}\\ =\frac{3}{5}\times\frac{18}{9}-\frac{3}{10}=\frac{3\times2}{5}-\frac{3}{10}\)
\(=\frac{6}{5}-\frac{3}{10}=\frac{12}{10}-\frac{3}{10}=\frac{9}{10}\)
1/11 +2/11+3/11+4/11+5/11+6/11+7/11+8/11+9/11+10/11
tính bằng cách thuận tiện nhất
=(1/11+10/11)+(2/11+9/11)+(3/11+8/11)+(4/11+7/11)+(5/11+6/11)
=11/11+11/11+11/11+11/11+11/11
=1+1+1+1+1
=5
=1+2+3+4+5+6+7+8+9+10 trên 11
= (1+9)+(2+8)+3+7)+(4+6)+5+10 trên 11
=10+10+10+10+10+5 trên 11
=10x5+5 trên 11
=50+5 trên 11
=55/11
=5
trên có nghĩa là (tất cả) phần 11 nha.
1/11+2/11+3/11+4/11+5/11+6/11+7/11+8/11+9/11+10/11
=(1/11+10/11)+(2/11+9/11)+(3/11+8/11)+(4/11+7/11)+(5/11+6/11)
=1+1+1+1+1
=5
chúc bạn học tốt!