(1-99/99)x(1-100/100)x.......x(1-2010/2010)=?
(1-99/99)x(1-100/100)x.......x(1-2010/2010)=?
(17-100 + 83 ) x ( 1 + 3 + 5 + ........+99 ) + 2010
(17-100+83)x(1+3+5+...+99)+2010
=>(17+83-100)x(99-1):2+1+2010
=>0x50+2010
=>2010
|x-1|+|x-2|+......+|x-99|+|x-100|=6050
2.Thu gọn biểu thức
A=|2010-x|+|2009-x|+...........+|2-x|+|1-x| với :
a)x>2010
b)x=1005
c)x<1
Tìm x :
( 100 - 99 + 98 - 97 + 96 - 95 + .......+ 4 - 3 + 2 - 1 ) : 50 + 2010 - 12 x X = 91
(1+1+1+.............+1+1):50+2010-12xX=91
(1x50):50+2010-12xX
50:50+2010-12xX=91
1+2010-12xX=91
2011-12xX=91
12xX=2011-91
12xX=1920
x=1920:12
x=160
( 100-99+98-97+96-95+....+4-3+2-1):50+2010-12.x=91
( 100- 99+ 98- 97+ 96- 95+...+ 4- 3+ 2- 1): 50+ 2010- 12. X= 91.
A: 50+ 2010- 12. X= 91.
Xét A= 100- 99+ 98- 97+ 96- 95+...+ 4- 3+ 2- 1.
Dãy A có số các số hạng là:
( 100- 1): 1+ 1= 100( số)
Ta ghép 2 số hạng vào 1 nhóm được 50 nhóm.
A=( 100- 99)+( 98- 97)+( 96- 95)+...+( 4- 3)+( 2- 1).
A= 1+ 1+ 1+...+ 1+ 1( 50 số 1)
A= 1x 50.
A= 50.
=> A: 50+ 2010- 12. X= 91.
=> 50: 50+ 2010- 12. X= 91.
=> 1+ 2010- 12. X= 91.
=> 2011- 12. X= 91.
=> 12. X= 2011- 91.
=> 12. X= 1920.
=> X= 1920: 12.
=> X= 160.
Vậy X= 160.
(100-99+98+97+96-95+.....................+4-3+2-1)/50+2010-12*X=91
|x-1|+|x-2|+......+|x-99|+|x-100|=6050
2.Thu gọn biểu thức
A=|2010-x|+|2009-x|+...........+|2-x|+|1-x| với :
a)x>2010
b)x=1005
c)x<1
Bài 1:
Theo đề bài ta có: \(x\ge100\)
\(\Rightarrow\left|x-1\right|+\left|x-2\right|+...+\left|x-100\right|=x-1+x-2+...+x-100=6050\)
Ta có: \(x-1+x-2+...+x-100=6050\)
\(\Rightarrow\left(x+x+...+x\right)-\left(1+2+...+100\right)=6050\)
\(\Rightarrow100x-5050=6050\)
\(\Rightarrow100x=11100\)
\(\Rightarrow x=111\)
Vậy \(x=111\)
200 - 18 : (372:3.x-1)-28=166
(100-99+98-97+96-95+...+4-3+2-1):50+2010-12.x=91
x-(31/3+31/15+31/35+31/63+31/99+31/143)=9/13
#)Giải :
\(200-18:\left(372:3x-1\right)-28=166\)
\(\Leftrightarrow200-18:\left(372:3x-1\right)=194\)
\(\Leftrightarrow18:\left(372:3x-1\right)=6\)
\(\Leftrightarrow372:3x-1=3\)
\(\Leftrightarrow3x-1=124\)
\(\Leftrightarrow3x=125\)
\(\Leftrightarrow x=\frac{125}{3}\)
200 - 18 : (372 : 3 . x - 1) - 28 = 166
=> 200 - 18 : (372 : 3.x - 1) = 166 + 28
=> 200 - 18 : (372 : 3.x) - 1) = 194
=> 18 : (372 : 3.x - 1) = 200 - 194
=> 18 : (372 : 3.x - 1) = 6
=> 372 : 3.x - 1 = 18 : 6
=> 372 : 3.x - 1 = 3
=> 372 : 3.x = 3 + 1
=> 372 : 3.x = 4
=> 3.x = 372 : 4
=> 3.x = 93
=> x = 93 : 3
=> x = 31
#)Next:
\(\left(100-99+98-97+...+2-1\right):50+2010-12x=91\)
\(\Leftrightarrow\left[\left(100-99\right)+\left(98-97\right)+...+\left(2-1\right)\right]:50+2010-12x=91\)
\(\Leftrightarrow\left[1+1+...+1\right]:50+2010-12x=91\)
\(\Leftrightarrow50:50+2010-12x=91\)
\(\Leftrightarrow1+2010-12x=91\)
\(\Leftrightarrow2011-12x=91\)
\(\Leftrightarrow12x=1920\)
\(\Leftrightarrow x=160\)
2010-1-2-3-...............-99-100