Tính
a, \(\frac{101+100+....+2+1}{101-100+99-98+...+3-2+1}\)
b, \(\frac{423134.846267-423133}{423133.846267+423134}\)
A=101+100+99+98+....+3+2+1/101-100+99-98+...+3-2+1
B=423134.846267-423133/423133.846267+423134
\(A=\frac{101+100+99+98+..+3+2+1}{101-100+99-98+..+3-2+1}=\frac{101\times\frac{102}{2}}{1+1+..+1}=\frac{101\times102}{2\times51}=101\)
\(B=\frac{423134.846267-423133}{423133.846267+423134}=\frac{423134^2+423134.423133-423133}{423133^2+423133.423134+423134}=\frac{423134^2+423133^2}{423134^2+423133^2}=1\)
Tính
a, A=\(\frac{101-100+99-98+...+3-2+1}{101+100+99+98+...+3+2+1}\)
b, B=\(\frac{423133.846267+423134}{423134.846267-423133}\)
Tính:
a) A = \(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b) B = \(\frac{423134.546267-423133}{423133.846267+423134}\)
a) A\(\frac{101+100+99+98+.....+3+2+1}{101-100+99-98+.....+3-2+1}\)
b) B=\(\frac{423134\cdot846267-423133}{423134\cdot846267-423134}\)
ai nhanh mình tích cho
tinh nhanh
a) A= 33(1-2/3)(1-2/5)...(1-2/99)
b) B=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
c) C=423134x846267-423133/423133x846267+423134
Bạn giỏi bạn làm đi đã ngu zồi thích tỏ ra minh ngu hơn. Bạn sợ bạn nếu ko nói câu đấy người ta tưởng bạn khôn chắc
Thực hiện phép tính
a) A= 33(1-2/3)(1-2/5)...(1-2/99)
b) B=101+100+99+98+...+3+2+1 / 101-100+99-98+...+3-2+1
c) C=423134x846267-423133 / 423133x846267+423134
Tính
a)A=101+100+99+98+…+3+2+
101-100+99+98+…+3-2+1
b)B=3737.43-4343.37
2+4+6+…+100
A = \(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
B =\(\frac{3737\cdot4343\cdot37}{2+4+6+...+100}\)
\(A=\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
\(A=\frac{\left(\frac{101-1}{1}+1\right)\left(\frac{101+1}{2}\right)}{\left(\frac{101-1}{2}+1\right)\left(\frac{101+1}{2}\right)-\left(\frac{100-2}{2}+1\right)\left(\frac{100+2}{2}\right)}=\frac{101.51}{51.51-50.51}\frac{101.51}{51}=101\)
câu b có nhầm dấu k pn s tử toàn dấu nhân . s k tick cho chị câu a à
rút gọn :\(\frac{101+100+99+98+.,.+3+2+1}{101-100+99-98+...+3-2+1}\)
\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
\(=\frac{\left(101+1\right).100:2}{\left(101-100\right)+\left(99-98\right)+...+\left(3-2\right)+1}\)
\(=\frac{5050}{1+1+...+1+1}\)(51 chữ số 1)
= \(\frac{5050}{51}\)