0.5x - 2/3x = 7/12

<=> 1/2x - 2/3x = 7/12

<=> (1/2 - 2/3).x = 7/12

<=> -1/6.x = 7/12

<=> x = 7/12 : -1/6

<=> x = -7/2

Vậy x = -7/2

Chưa ai giải à?

\(x=\frac{3}{4}x+\frac{3}{4}\)

\(\Leftrightarrow x-\frac{3}{4}x=\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{4}x=\frac{3}{4}\)

\(\Leftrightarrow x=\frac{3}{4}:\frac{1}{4}=3\)

Bạn ghi lại đề đi bạn

theo đề ta có 

(3x+2)(x+3) = (0,5x+2)(5x+7) 

=> 3x^2 + 11x + 6 = 2,5x+13,5x+14 

..................

từ đây bn tự giải tìm x

a ) \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)

\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(3x-1\right)\left(5x+7\right)\)

\(\Leftrightarrow3x\left(5x+1\right)+2\left(5x+1\right)=3x\left(5x+7\right)-\left(5x+7\right)\)

\(\Leftrightarrow15x^2+3x+10x+2=15x^2+21x-5x-7\)

\(\Leftrightarrow15x^2+13x+2=15x^2+16x-7\)

\(\Leftrightarrow13x+2=16x-7\)

\(\Leftrightarrow13x-16x=-7-2\)

\(\Leftrightarrow-3x=-9\)

\(\Rightarrow x=3\)

b ) tương tự

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\Rightarrow\left(x+1\right)\left(x+3\right)=\left(0,5x+2\right)\left(2x+1\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+0,5x+4x+2\)

\(\Rightarrow x^2+3x+x-x^2-0,5x-4x=2-3\)

\(\Rightarrow-\frac{1}{2}x=-1\)

\(\Rightarrow x=2\)

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)

\(\Rightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+4x+0,5x+2\)

\(\Rightarrow x^2+3x+x+3-x^2-4x-0,5x-2=0\)

\(\Rightarrow1-0,5x=0\)

\(\Rightarrow\frac{1}{2}x=1\Leftrightarrow x=2\)

0.5x=2/3+7/12

1/2x=5/4

x=2.5