\(=\frac{75}{100}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\left(-\frac{1}{3}\right)^2\)

\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}-\frac{1}{9}\)

\(=\frac{-3}{4}+\frac{6}{5}-\frac{1}{9}\)

\(=\frac{9}{20}-\frac{1}{9}\)

\(=\frac{61}{180}\)

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)

= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)

= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=\frac{-30}{40}+\frac{48}{40}+\frac{-6}{40}=\frac{12}{40}=\frac{3}{10}\)

CHÚC BN HK TỐT #

= \(\frac{75}{100}-\frac{3}{2}+\frac{6}{5}-"-\frac{1}{2}"^3=\frac{75}{100}-\frac{3}{2}+\frac{6}{5}-\frac{53}{40}=\)\(-\frac{3}{4}+-\frac{1}{8}=-\frac{1}{4}\)

hok tốt

nhớ ...

\(=-\frac{3}{4}+\frac{6}{5}-\left(\frac{-1}{8}\right)\))

=\(-\frac{3}{4}+\frac{6}{5}+\frac{1}{8}\)

=\(\frac{9}{20}+\frac{1}{8}\)

=\(\frac{23}{40}\)

Vậy..........

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{6}{5}+\frac{1}{8}\)

= \(\frac{30}{40}-\frac{60}{40}+\frac{48}{40}+\frac{5}{40}\)

= \(\frac{23}{40}\)

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)

= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)

= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=-\frac{30}{40}+\frac{48}{40}-\frac{-6}{40}=\frac{24}{40}=\frac{3}{5}\)

BÀI NÀY ĐÚNG NÈ 

CHÚC BN HỌC TỐT # 

\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}\)

\(=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}\)

\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}\)

\(=\frac{15}{20}-\frac{30}{20}+\frac{24}{20}\)

\(=\frac{9}{20}\)

bt rùi nhưng ko chắc lắm

9/20 nhe

\(\frac{5}{7}\times\frac{1}{3}-\frac{5}{7}\times\frac{1}{4}-\frac{5}{7}\times\frac{1}{2}\)

\(=\frac{5}{7}\times\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right)\)

\(=\frac{5}{7}\times\left(\frac{4}{12}-\frac{3}{12}-\frac{6}{12}\right)\)

\(=\frac{5}{7}\times\left(\frac{4-3-6}{12}\right)\)

\(=\frac{5}{7}\times\frac{-5}{12}\)

\(=\frac{5\times\left(-5\right)}{7\times12}\)

\(=\frac{-25}{84}\)

\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)

= \(\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right).1\)

\(=\frac{5}{7}.\frac{-5}{12}\)

\(=-\frac{25}{84}\)

\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{1}{4}\)

\(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{5}{12}-\frac{1}{4}\)

\(\frac{3}{4}-\frac{3}{2}+\frac{5}{24}-\frac{1}{4}\)

\(\frac{18}{24}-\frac{36}{24}+\frac{5}{24}-\frac{6}{24}\)

-19/24

\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)

\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

\(=\frac{5}{7}.0=0\)

c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)

\(=\frac{27}{5}.10=27.2=54\)

\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)

\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)

cho mk hỏi, bn có thể lm thêm c d dc ko

bài 2:thực hiện phép tính

a. 75% - 1$\frac{1}{2}$+0,5:$\frac{5}{12}$

= \(\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}\)

\(= \dfrac{9}{20} \)

b, -1$\frac{1}{4}$.$\frac{{\left(-2\right)}^2}{5}$+$\frac{1}{5}$:2

\(= \dfrac{-5}{4}.\dfrac{4}{5}+\dfrac{1}{10}\)

\(= \dfrac{-9}{10}\)

3/4-3/2+1/2:5/12-1/4

3/4-3/2+1/2.12/5-1/2

3/4-3/2+6/5-1/2

3/4-6/4+6/5-1/2

-3/4+6/5-1/2

-15/20+24/20-10/20

9/20-10/20

-1/20

sao bạn tự đăng tự giải thế? hay là bạn giải cho ai à?

ukm bn