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-25-(x+5) = 415 + 5(x-83)

=> -25-x-5=415+5x-415

=> -30-x-5x = 0

=> -30=6x

=> x = -5 

`-25-(x+5)=415+5(x-83)`

`<=> -25-x-5=415+5x-415`

`<=> -x-5x=415-415+25+5`

`<=> -6x=30`

`<=> x=-5`

-25 - ( x+5 ) = 415 + 5(x- 83)

\(-25-x-5-415-5x+415=0\)

\(-30-6x=0\)

\(6x=-30\)

\(x=-30:6=-5\)

Vậy x=-5

- 25 - ( x + 5 ) = 415 + 5( x - 83 )

- 25 - x-5= 415+ 5x -415

- 30-x = 415 -415 +5x

-30-x = 5x

-30= x+ 5x

-30 = 6x

-30:6= x

-5 = x

Vậy...

-25 - ( x + 5 ) = 415 + 5( x - 83 )

     -25 - x - 5 = 415 + 5x - 415

 ( -25 - 5 ) - x = ( 415 - 415 ) +5x

          -30 - x = 5x

               -30 = 5x + x

               -30 = 6x

                  x = ( -30) :6

                  * = -5

Tìm x biết :

\(-25-\left(x+5\right)=415+5.\left(x-83\right)\)

\(\Rightarrow-25-x-5=415+5x-415\)

\(\Rightarrow6x=20\)

\(\Rightarrow x=\frac{10}{3}\)

c)

-25-x-5=415+5x-415

x-5x=-25-415-415+5

-4x=-20

x=5

k nhé

a)x-12-2x-31=-11

   x-2x-12-31=-11

   -1x=-11+31+12

    -x=33

b)-2x-14+3x-6=-2

   -2x+3x-14-6=-2

    x=-2+6+14

    x=18

\(-25\cdot\left(x+5\right)=415+\left(x-83\right)\)

\(\Leftrightarrow-25x-125=415+x-83\)

\(\Leftrightarrow26x=-457\)

\(\Leftrightarrow x=-\frac{457}{26}\)

cái gì trừ cái gì vậy -25

Mình chép sai đề, mình xin phép làm lại nhé :

\(-25-\left(x+5\right)=415+\left(x-83\right)\)

\(\Leftrightarrow-25-x-5=415+x-83\)

\(\Leftrightarrow2x=-362\Leftrightarrow x=-181\)

Vậy \(x=-181\)

a, 3- (17-x) = 289 - (36+289)

3 - (17 - x )= 289 - 325

3 - (17 - x )= -36

17 - x =3 - (-36)

17 - x =39

       x = 17 - 39

       x = -22

b, 25- (x+5) = - 415 - (15 - 415)

25 - ( x + 5)= -415 - (-400)

25-( x + 5 ) =-15

x + 5 = 25 - (-15)

x+5 =40

x = 40 -5

x=35

hok tốt !