3. A

4. A

5. C

6. B

37. What is the price of the bicycle? (How much)

=> How much does the bicycle costs?

38. The tea doesn't taste the same as the one I usually drink. (from)

=> The tea tastes diferrently from the one I usually drink.

39. I really like listening to pop ballad songs. (fond)

=> I'm really fond of listening to pop ballad songs.

40. I want some iced tea because I am hot. (so)

=> I am hot so I want some iced tea.

37 How much is the bicycle?

38 This tea tastes different from the one I usually drink

39 I am really fond of pop ballad sóng

40 I am hot so I want some iced tea

Câu 1:

\(1,\\ a,=\sqrt{28,9\cdot90}=\sqrt{2601}=51\\ b,=\dfrac{\sqrt{15}}{5}\\ 2,ĐK:4x+16\ge0\Leftrightarrow x\ge-4\\ 3,\\ a,3\sqrt{2}=\sqrt{18}>\sqrt{15}\\ b,=6-2\cdot3-2=-2\)

Câu 2:

\(1,\\ a,=6\sqrt{3}+8\sqrt{3}-3\sqrt{3}=11\sqrt{3}\\ b,=\dfrac{\sqrt{5}+\sqrt{3}+\sqrt{5}-\sqrt{3}}{5-3}=\dfrac{2\sqrt{5}}{2}=\sqrt{5}\\ 2,\\ A=\dfrac{x\sqrt{x}-3x-x\sqrt{x}-3x}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\cdot\dfrac{-\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}{\sqrt{3}\sqrt{x}}\\ A=\dfrac{6x}{\sqrt{3}\sqrt{x}}=2\sqrt{3x}\)

\(3,\Leftrightarrow2x-3=7\Leftrightarrow x=5\)

\(A=\left(x^2+y^2\right)^2-2x^2y^2=18^2-2\cdot5^2=274\)

1 B 

2 A

3 D

4 A

5 A

6 C

1:

#include <bits/stdc++.h>
using namespace std;
const long long maxn=1e6+10;
long long a[maxn],i,n;
int main()
{
    freopen("sxso.inp","r",stdin);
    freopen("sxso.out","w",stdout);
    cin>>n;
    for (i=1; i<=n; i++)
        cin>>a[i];
    sort(a+1,a+n+1);
    for (i=n; i>=1; i--)
        cout<<a[i]<<" ";
    return 0;
}

a và b có thể bằng 0 hoặc 5