\(\frac{1}{2}.x+\frac{3}{5}.x=-\frac{33}{25}\)

\(\Leftrightarrow x.\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{25}\)

\(\Leftrightarrow x.\frac{11}{10}=-\frac{33}{25}\)

\(\Leftrightarrow x=-\frac{33}{25}:\frac{11}{10}\)

\(\Leftrightarrow x=-\frac{6}{5}\)

Vậy \(x=\frac{6}{5}\)

\(\frac{1}{2}.x+\frac{3}{5}.x=-\frac{33}{25}\)

\(x.\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{25}\)

\(x.\left(\frac{5}{10}+\frac{6}{10}\right)=-\frac{33}{25}\)

\(x.\frac{11}{10}=-\frac{33}{25}\)

         \(x=-\frac{33}{25}:\frac{11}{10}\)

              \(x=-\frac{33}{25}.\frac{10}{11}\)

            \(x=-\frac{6}{5}\)

Vậy \(x=-\frac{6}{5}\)

Chúc bạn học tốt !!!

\(\frac{1}{2}\).x+\(\frac{3}{5}\).x=\(\frac{33}{25}\)

x.\((\frac{1}{2}\)+\(\frac{3}{5})\)=\(\frac{33}{25}\)

x.\((\frac{5}{10}+\frac{6}{10})=\frac{33}{25}\)

\(x.\frac{11}{10}=\frac{33}{25}\)

\(x=\frac{33}{25}:\frac{11}{10}\)

x=\(\frac{6}{5}\)

câu a 25-5.(x-13) bằng mấy bạn

b, 2³.(x-7)=3.2⁵

=>2³.(x-7)=96

=>8.(x-7)=96

=>x-7=96:8

=>x-7=12

=>x=12+7

=>x=19

c,33+3.|x-1| =7²-2019⁰

=>33+3.|x-1| =48

=>3.|x-1| =48-33

=>3.|x-1| =15

=>|x-1| =15:3

=>|x-1| =5

=>x-1= ± 5

=>x-1=5    =>x=5-1  =>x=4

    x-1= -5  =>x=-5-1  =>x=-6

Dấu // là giá trị tuyệt đối

\(6-2\left(x-1\right)=4\)

\(\Rightarrow2\left(x-1\right)=6-4\)

\(\Rightarrow2\left(x-1\right)=2\)

\(\Rightarrow x-1=1\)

\(\Rightarrow x=1+1=2\)

________________

\(2\cdot\left(x-2\right)+1=7\)

\(\Rightarrow2\cdot\left(x-2\right)=7-1\)

\(\Rightarrow2\cdot\left(x-2\right)=6\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=3+2=5\)

_______________

\(\left(2\cdot x-3\right)+4=9\)

\(\Rightarrow2\cdot x-3=5\)

\(\Rightarrow2\cdot x=3+5\)

\(\Rightarrow2\cdot x=8\)

\(\Rightarrow x=\dfrac{8}{2}=4\)

________________

\(\left(3\cdot x-2\right)-1=3\)

\(\Rightarrow3\cdot x-2=3+1\)

\(\Rightarrow3\cdot x-2=4\)

\(\Rightarrow3\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{3}=2\)

a: =>2(x-1)=2

=>x-1=1

=>x=2

b: =>2(x-2)=6

=>x-2=3

=>x=5

c; =>2x-3=5

=>2x=8

=>x=4

d: =>3x-2=4

=>3x=6

=>x=2

e: =>2(6-x)=4

=>6-x=2

=>x=4

f: =>x-2=5

=>x=7

g: =>10-2x=4

=>2x=6

=>x=3

h: =>2x+4=3

=>2x=-1

=>x=-1/2

j: =>x+2=12

=>x=10

l: =>2x+3=3

=>2x=0

=>x=0

\(6-2\left(x-1\right)=4\\ 2\left(x-1\right)=6-4=2\\ x-1=\dfrac{2}{2}=1\\ x=1+1=2\)

\(2\left(6-x\right)+1=5\\ 2\left(6-x\right)=5-1=4\\ 6-x=\dfrac{4}{2}=2\\ x=6-2=4\)

\(\left(4+2x\right)-1=8\\ 3\left(4+2x\right)=8+1=9\\ 4+2x=\dfrac{9}{3}=3\\ 2x=3-4=-1\\ x=-\dfrac{1}{2}\)

\(2\left(x-2\right)+1=7\\ 2\left(x-2\right)=7-1=6\\ x-2=\dfrac{6}{2}=3\\ x=3+2=5\)

\(20+\left(x-2\right)=25\\ x-2=25-20=5\\ x=5+2=7\)

\(\left(x+2\right)-5=7\\ x+2=7+5=12\\ x=12-2=10\)

\(\left(2x-3\right)+4=9\\ 2x-3=9-4=5\\ 2x=5+3=8\\ x=\dfrac{8}{2}=4\)

\(\left(10-\dfrac{2}{x}\right)-1=3\\ 10-\dfrac{2}{x}=3+1=4\\ \dfrac{2}{x}=10-4=6\\ x=\dfrac{2}{6}=\dfrac{1}{3}\)

\(\left(3+2x\right)-1=3\\ 3+2x=3+1=4\\ 2x=4-3=1\\ x=\dfrac{1}{2}\)

\(\left(3x-2\right)-1=3\\ 3x-2=3+1=4\\ 3x=4+2=6\\ x=\dfrac{6}{3}=2\)

Tìm x

a) 17 + 33 : ( 2 . x - 1 ) = 20

33 :( 2 . x - 1 )= 20 - 17

33 :( 2 . x - 1 ) = 3 

2 . x - 1 = 33 : 3 

2 . x - 1 = 11 

2 . x = 11 - 1 = 10 

x = 10 : 2 

x = 5 

b) 25 - [ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 21

[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 25 - 21 

[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 4 

( 2 . x + 5 ) . 7 - 15 = 5 x 4 

( 2 . x + 5 ) . 7 - 15 = 20 

( 2 . x + 5 ) . 7 = 20 + 15 

( 2 . x + 5 ) . 7 = 35 

2 . x + 5 = 35 : 7 

2 . x + 5 = 5 

2 . x = 5 - 5 

2 . x = 0 

x = 0 

hok tốt

a) \(17+33:\left(2x-1\right)=20\)

\(\Rightarrow33:\left(2x-1\right)=20-17\)

\(\Rightarrow33:\left(2x-1\right)=3\)

\(\Rightarrow2x-1=33:3\)

\(\Rightarrow2x-1=11\)

\(\Rightarrow2x=11+1\)

\(\Rightarrow2x=12\)

\(\Rightarrow x=12:2\)

\(\Rightarrow x=6\)

Vậy x = 6

b) \(25-\left[\left(2x+5\right)\times7-15\right]:5=21\)

\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=25-21\)

\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=4\)

\(\Rightarrow\left(2x+5\right)\times7-15=4\times5\)

\(\Rightarrow\left(2x+5\right)\times7-15=20\)

\(\Rightarrow\left(2x+5\right)\times7=20+15\)

\(\Rightarrow\left(2x+5\right)\times7=35\)

\(\Rightarrow2x+5=35:7\)

\(\Rightarrow2x+5=5\)

\(\Rightarrow2x=5-5\)

\(\Rightarrow2x=0\)

\(\Rightarrow x=0:2\)

\(\Rightarrow x=0\)

Vậy x = 0

_Chúc bạn học tốt_

a ) 17 + 33 : ( 2 . x - 1 ) = 20

      33 : ( 2x - 1 ) = 20 - 17 

     33 : ( 2x - 1 ) = 3

          2x - 1 = 33 : 3

         2x - 1 = 11

         2x = 11 - 1

          2x = 10 

         x = 10 : 2

      x = 5

Vậy x = 5

b) 25 - [ ( 2x + 5 ) . 7 - 15 ] : 5 = 21

[ ( 2x + 5 ) . 7 - 15 ] : 5 = 25 - 21

[ ( 2x + 5 ) . 7 - 15 ] : 5 = 4

( 2x + 5 ) . 7 - 15 = 4 x 5 

( 2x + 5 ) . 7 - 15  = 20

( 2x + 5 ) . 7 = 20 + 15

( 2x + 5 ) . 7 = 35

2x + 5 = 35 : 7

2x + 5 = 5

2x = 5 - 5

2x = 0

x = 0 : 2

x = 0

Vậy x = 0

x.3+1/2+3/2+5/2=33

x.3+9/2=33

x.3+4,5=33

x.3=33-4,5

x.3=28,5

x=28,5:3

x=9,5

47. (23 + 50)- 23. ( 47+50 )

= 47. 23+ 47. 50- 23. 47 - 23. 50

=47. 50 - 23. 50

= 50 .( 47 -23)

=50. 24 = 1200

(-33 ). (-5) - 33 . 4 + 33

= 33 ( 5 - 4 + 1)

=33 . 2 = 66

giup minh voi 

1,

\(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) : (-5) -\(\dfrac{3}{16}\) . \(\left(-2\right)^2\)

= \(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) . \(\dfrac{-1}{5}\) - \(\dfrac{3}{16}\) . 4

= \(\dfrac{6}{7}\) + \(\dfrac{1}{8}\) - \(\dfrac{3}{4}\)

= \(\dfrac{48}{56}\) + \(\dfrac{7}{56}\) - \(\dfrac{42}{56}\)

= \(\dfrac{13}{56}\)

3,

a,\(\dfrac{3}{5}\)x - \(\dfrac{7}{10}\)x = \(\dfrac{-1}{2}\)

x.(\(\dfrac{3}{5}\) - \(\dfrac{7}{10}\)) = \(\dfrac{-1}{2}\)

x.\(\dfrac{-1}{10}\)= \(\dfrac{-1}{2}\)

x =\(\dfrac{-1}{2}\):\(\dfrac{-1}{10}\)

x = 5

c, (2,5x - 3,6) : \(\dfrac{15}{7}\) = -1

( \(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\)) : \(\dfrac{15}{7}\) = -1

\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = -1 . \(\dfrac{15}{7}\)

\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = \(\dfrac{-15}{7}\)

\(\dfrac{5}{2}\)x = \(\dfrac{-15}{7}\) + \(\dfrac{18}{5}\)

\(\dfrac{5}{2}\)x = \(\dfrac{51}{35}\)

x =\(\dfrac{51}{35}\) : \(\dfrac{5}{2}\)

x = \(\dfrac{102}{175}\)

Mình không biết có chỗ nào sai không nữa.