\(\Leftrightarrow2\cdot7^x\cdot\dfrac{1}{7}-7^x\cdot49+341=0\)

\(\Leftrightarrow7^x=7\)

hay x=1

x=1

( 3x - 2⁴ ) . 7⁵ = 2.7⁶ .1/2017⁰

( 3x - 2⁴ ) . 7⁵ =235298

( 3x - 2⁴ ) = 235298 : 7⁵ 

( 3x - 2⁴ ) =14

3x = 14 + 2⁴ 

3x = 30

x = 0

dung 100%

\(\left(3x-2^4\right).7^5=2.7^6.\frac{1}{2017^0}\)

\(\Leftrightarrow\left(3x-16\right).7^5=2.7^6.1\)

\(\Leftrightarrow3x-16=\frac{2.7^6}{7^5}\)

\(\Leftrightarrow3x-16=2.7\)

\(\Leftrightarrow3x-16=14\)

\(\Leftrightarrow3x=30\)

\(\Leftrightarrow x=10\)

Nhưng mình làm cách này có được không :  (Tự nhiên nghĩ được)

(3x-2^4).7^5=2.7^6.1/2017^0 

(3x-2^4).7^5=2.7.7^5.1

3x-16=2.7   ( Bớt cả hai vế cho 7^5)

3x=14+16

x=30:3

x=10

219 - 7(x + 1) = 10²

7(x + 1) = 219 - 10²

7(x + 1) = 219 - 100

7(x + 1) = 119

x + 1 = 119 : 7

x + 1 = 17

x = 17 - 1

x = 16

--------------------

(3x - 2⁴) . 7³ = 2.7⁴

(3x - 16).7³ = 2.7⁴

3x - 16 = 2.7⁴:7³

3x - 16 = 2.7

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

Lời giải:

$10+2x=4^5:4^3=4^2=16$

$2x=16-10=6$

$x=6:2=3$

---------

$2x-6^2:18=3.2^2$
$2x-2=12$

$2x=14$

$x=14:2=7$

--------------

$70-5(x-3)=3.2^5=96$

$5(x-3)=70-3.2^5=-26$

$x-3=\frac{-26}{5}$

$x=3+\frac{-26}{5}=\frac{-11}{5}$

------------------

$19-7(x+1)=10^2=100$

$7(x+1)=19-100=-81$

$x+1=\frac{-81}{7}$

$x=\frac{-81}{7}-1=\frac{-88}{7}$

------------

$(3x-2^4).7^3=2.7^4$

$3x-16=2.7^4:7^3=2.7=14$

$3x=14+16=30$

$x=30:3=10$

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345/7

\(7^{x+2}+2.7^{x-1}=\frac{345}{7}\Leftrightarrow7^{x+3}+2.7^x=345\Leftrightarrow7^x\left(7^3+2\right)=345\)

\(\Rightarrow7^x345=345\Rightarrow7^x=1\Rightarrow x=0\)

Vậy \(x=0\)

Ta có: 5².7³.11².x - 5².7².11⁴ = 0

=> 5².7².11²(7x - 11²) = 0

=> 7x - 121 = 0

=> 7x = 121

=> x = 121 : 7

=> x = 121/7