2.7^x-1-7^x+2+341=0
2.7^x-1-7^x+2+341=0
\(\Leftrightarrow2\cdot7^x\cdot\dfrac{1}{7}-7^x\cdot49+341=0\)
\(\Leftrightarrow7^x=7\)
hay x=1
tìm x : x.(1/5+1/4) - ( 1/7+1/8 ) = 0
b 5^2.7^3.11^2+5^2.7^2.11 = 0
Tìm x, biết : \(\left(3x-2^4\right).7^5=2.7^6.\frac{1}{2017^0}\)
( 3x - 24 ) . 75 = 2.76 .1/20170
( 3x - 24 ) . 75 =235298
( 3x - 24 ) = 235298 : 75
( 3x - 24 ) =14
3x = 14 + 24
3x = 30
x = 0
dung 100%
\(\left(3x-2^4\right).7^5=2.7^6.\frac{1}{2017^0}\)
\(\Leftrightarrow\left(3x-16\right).7^5=2.7^6.1\)
\(\Leftrightarrow3x-16=\frac{2.7^6}{7^5}\)
\(\Leftrightarrow3x-16=2.7\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=10\)
Nhưng mình làm cách này có được không : (Tự nhiên nghĩ được)
(3x-2^4).7^5=2.7^6.1/2017^0
(3x-2^4).7^5=2.7.7^5.1
3x-16=2.7 ( Bớt cả hai vế cho 7^5)
3x=14+16
x=30:3
x=10
Tìm x biết
219-7 ( x+1 ) = 10²
( 3x - 2⁴ ) . 7³ = 2.7⁴
219 - 7(x + 1) = 10²
7(x + 1) = 219 - 10²
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
--------------------
(3x - 2⁴) . 7³ = 2.7⁴
(3x - 16).7³ = 2.7⁴
3x - 16 = 2.7⁴:7³
3x - 16 = 2.7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
Tìm x biết
219-7 ( x+1 ) = 10²
( 3x - 2⁴ ) . 7³ = 2.7⁴
Lời giải:
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
---------
$2x-6^2:18=3.2^2$
$2x-2=12$
$2x=14$
$x=14:2=7$
--------------
$70-5(x-3)=3.2^5=96$
$5(x-3)=70-3.2^5=-26$
$x-3=\frac{-26}{5}$
$x=3+\frac{-26}{5}=\frac{-11}{5}$
------------------
$19-7(x+1)=10^2=100$
$7(x+1)=19-100=-81$
$x+1=\frac{-81}{7}$
$x=\frac{-81}{7}-1=\frac{-88}{7}$
------------
$(3x-2^4).7^3=2.7^4$
$3x-16=2.7^4:7^3=2.7=14$
$3x=14+16=30$
$x=30:3=10$
(3.|x|.2 mũ 4).7 mũ 2018=2.7 mũ 2019. 1/2019 mũ 0
Giải gấp hộ mình nhé huhu
dssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
7 mũ x+2+2.7 mũ x-1=345
\(7^{x+2}+2.7^{x-1}=\frac{345}{7}\)
\(7^{x+2}+2.7^{x-1}=\frac{345}{7}\Leftrightarrow7^{x+3}+2.7^x=345\Leftrightarrow7^x\left(7^3+2\right)=345\)
\(\Rightarrow7^x345=345\Rightarrow7^x=1\Rightarrow x=0\)
Vậy \(x=0\)
a/\(^{3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]}\)
b/(x+1)+(x+2)+(x+3)+....+(x+100)=205550
c/Ix-5I=18+2x(-8)
d/\(\left(3x-2^4\right).7^5=2.7^6.\frac{1}{2009^0}\)
b/100x+(1+2+3+...+100)=205550
100x+5050=205550
100x=205550-5050
100x=200500
x=200500/100
x=2005
d/(3x-24).75=2.76.1/20090
(3x-24).75=2.76.1
(3x-24)=2.76:75
(3x-24)=2.7
3x-16=14
3x=14+16
3x=30
x=30/10=3
b) ( \(x\)+ 1 ) + ( \(x\)+ 2 ) + ( \(x\)+ 3 ) + ... + ( \(x\)+ 100 ) = 205550
\(x\)x 100 + ( 1 + 2 + 3 + ... + 100 ) = 205550
\(x\)x 100 + 5050 = 205550
\(x\)x 100 = 205550 - 5050
\(x\)x 100 = 200500
\(x\)= 200500 : 100
\(x\)= 2005