a/ = (-0,125 . 8) . (-5,3)

= (-1) . (-5,3)

= 5,3

b/ = (0,4 . 2,5) . (-6,37)

= 1 . (-6,37)

= 6,37

c/ = (-10) . (-7,9)

= 79

a) ( - 6,37 x 0,4 ) x 2,5

=-6,37 x (0,4 x 2,5)

=-6,37 x 1

=-6,37

b) ( -0,125 ) x ( -5,3 ) x 8

=(-0,125 x 8) x (-5,3)

=-1 x (-5,3)

=5,3

c) ( -2,5 ) x ( -4 ) x ( -7,9 )

=[(-2,5) x (-4)] x (-7,9)

=10 x (-7,9)

=-79

a)(-6,37x0,4)x2,5=-6,37x(0,4x2,5)=-6,37x1=-6,37

b)(-0,125)x(-5,3)x8=(-0,125x8)x(-5,3)=-1x(-5,3)=5,3

c)(-2,5)x(-4)x(-7,9)=[(-2,5)x(-4)]x(-7,9)=10x(-7,9)=-79

a)

\(\left(-6,37.0,4\right)2,5=\left(-6,37\right).\left(\frac{2}{5}.\frac{5}{2}\right)=1.\left(-6,37\right)=-6,37\)

b)

\(\left(-0,125\right)\left(-5,3\right).8=\left[\left(-\frac{1}{8}\right).8\right]\left(-5,3\right)=\left(-1\right)\left(-5,3\right)=5,3\)

c)

\(\left(-2,5\right).\left(-4\right).\left(-7,9\right)=\left[\left(-\frac{5}{2}\right).\left(-4\right)\right]\left(-7,9\right)=10.\left(-7,9\right)=-79\)

d)

\(\left(-0,375\right).4\frac{1}{3}.\left(-2\right)^3=\left(-\frac{3}{8}\right).\frac{12}{3}.\left(-8\right)=12\)

a) [ 2,9+(-2,9)] + [ (-4,2)+4,2]+ 3,7

= 0+0+3,7

= 3,7

b)2,8.[(-6,5)+(-3,5)

= 2,8 . (-10)

= -28

c) - 6,37 . ( 0,4 . 2,5 )

= -6,37.1

= -6,37

d) ( -0,125 . 8) .( -5,3)

= -1. ( -5,3)

= 5,3

xong rồi đó

\(a\))\(2,9+3,7+\left(-4,2\right)+\left(-2,9\right)+4,2\)

\(=3,7\)

\(b\))\(\left(-6,5\right).2,8+2,8.\left(-3,5\right)\)

\(=2,8.\left(-6,5-3,5\right)\)

\(=2,8.\left(-10\right)\)

\(=-28\)

\(c\))\(\left(-6,37.0,4\right).2,5\)

\(=\left(-6,37\right).\left(0,4.2,5\right)\)

\(=-6,37\)

\(d\))\(\left(-0,125\right).\left(-5,3\right).8\)

\(=\left(-5,3\right).\left(-1\right)\)

\(=5,3\)

a) Ta có: \(2.9+3.7+\left(-4.2\right)+\left(-2.9\right)+4.2\)

\(=\left(2.9-2.9\right)+\left(-4.2+4.2\right)+3.7\)

\(=0+0+3.7\)

\(=3.7\)

b) Ta có: \(\left(-6.5\right)\cdot2.8+2.8\cdot\left(-3.5\right)\)

\(=2.8\cdot\left(-6.5-3.5\right)\)

\(=2.8\cdot\left(-10\right)\)

\(=-28\)

c) Ta có: \(\left(-6.37\cdot0.4\right)\cdot2.5\)

\(=-6.37\cdot0.4\cdot2.5\)

\(=-6.37\cdot\left(0.4\cdot2.5\right)\)

\(=-6.37\cdot1\)

\(=-6.37\)

d) Ta có: \(\left(-0.125\right)\cdot\left(-5.3\right)\cdot8\)

\(=0.125\cdot8\cdot5.3\)

\(=\left(0.125\cdot8\right)\cdot5.3\)

\(=1\cdot5.3=5.3\)

a) \(=\left(\frac{-337}{100}:\frac{40}{100}\right).\frac{250}{100}=\frac{-337}{40}.\frac{40}{16}=-\frac{337}{16}\)

b) \(=\frac{-1}{8}.\left(-5,3\right).8=\frac{-1}{8}.8.\left(-5,3\right)=-1.\left(-5,3\right)=5,3\)

c) \(=10.\left(-7,9\right)=-79\)

d) \(=-\frac{3}{8}.\frac{13}{3}.\left(-8\right)=\left[-\frac{3}{8}.\left(-8\right)\right].\frac{13}{3}=3.\frac{13}{3}=13\)

a)(-3,37:0,4).2,5

=(-8,425).2,5

=-21,0625

b) (-0,125) . (-5,3) . 8

=(-0,125).8.(-5,3)

=(-1).(-5,3)

=5,3

c)(-2,5).(-4).(-7,9)

=10.(-7,9)

=-79

d)(-0,375).\(4\frac{1}{3}\).(-2)³

=(-0,375).(-2)³.\(4\frac{1}{3}\)

=3.\(\frac{13}{3}\)

=13

a) (-6,37.0,4).2,5

= (0,4.2,5).(-6,37)

= 1. (-6,37)

= -6,37

b) (-0,125).(-5,3).8

= (-0,125.8).(-5,3)

= -1. (-5,3)

= 5,3

c) (-2,5).(-4).(-7,9)

= ((-2,5).(-4)). (-7,9)

= 10. (-7,9)

= -79

d) (-0,375). \(4\frac{1}{3}\). \(\left(-2^3\right)\)

= (-0,375). \(\frac{13}{3}\). (-8)

= ((-0,375).(-8)). \(\frac{13}{3}\)

= 3. \(\frac{13}{3}\)

= 13

a.-6,37

b.5,3

c.-79

d.17,295