1: 4\5
>, <, = ?
4 + 1 … 4 | 5 – 1 … 5 | 3 + 0 … 3 |
4 + 1 … 5 | 5 – 0 … 5 | 3 + 1 … 4 |
4 – 1 … 4 | 3 + 1 … 3 | 3 + 1 … 5 |
Lời giải chi tiết:
4 + 1 > 4 | 5 – 1 < 5 | 3 + 0 = 3 |
4 + 1 = 5 | 5 – 0 = 5 | 3 + 1 = 4 |
4 – 1 < 4 | 3 + 1 > 3 | 3 + 1 < 5 |
Dễ nhỉ !
Ai đồng tình thì cho mình nha !
4 + 1 > 4 | 5 – 1 < 5 | 3 + 0 = 3 |
4 + 1 = 5 | 5 – 0 = 5 | 3 + 1 = 4 |
4 – 1 < 4 | 3 + 1 > 3 | 3 + 1 < 5 |
1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5 1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+3+5+5+1+1+1+1+1+2+4+4+4+4+4+5+5+4+4+4+3+0+3+5+5+1+1.0+0+0+0+0+0+0+0++5+4+4+4+3+3+5+5+7= ? CHỈ CÓ NHỮNG NGƯỜI THÔNG MINH MỚI LÀM ĐC ĐÚNG TÔI TÍCH CHO MỖI NGƯỜI 1 CÁI
tự đi mà l.m nhìn ngứa cả mắt
>, < , = ?
5 – 2 … 4 | 5 – 4 … 2 | 4 + 1 … 5 |
5 – 2 …. 3 | 5 – 3 … 1 | 5 – 1 … 5 |
5 – 2 … 2 | 5 – 1 …. 4 | 5 – 4 … 0 |
Lời giải chi tiết:
5 – 2 < 4 | 5 – 4 < 2 | 4 + 1 = 5 |
5 – 2 = 3 | 5 – 3 > 1 | 5 – 1 < 5 |
5 – 2 > 2 | 5 – 1 = 4 | 5 – 4 > 0 |
5-2<4 5-4<2 4+1=5
5-2=3 5-3>1 5-1<5
5-2>2 5-1=4 5-4>0
So sánh: 4^9+4^8+4^7+..+4+1/4^10+4^9+4^8+...+4+1 và 5^9+5^8+5^7+...+5+1/5^10+5^9+5^8+...+5+1
Các bạn giúp mk nhé mk đang cần gấp ^_^
`lim(50 xx frac{1 - (4/5)^{n}}{1 - 4/5} + 4/5 xx 50 xx frac{1- (4/5)^{n-1}}{1 - 4/5})`
\(lim\left(50.\dfrac{1-\left(\dfrac{4}{5}\right)^n}{1-\dfrac{4}{5}}+\dfrac{4}{5}.50.\dfrac{1-\left(\dfrac{4}{5}\right)^{n-1}}{1-\dfrac{4}{5}}\right)\) \(=50.\dfrac{1}{\dfrac{1}{5}}+\dfrac{4}{5}.50.\dfrac{1}{\dfrac{1}{5}}=450\)
Tính:
5 - 1 = 1 + 4 = 2 + 3 =
5 - 2 = 4 + 1 = 3 + 2 =
5 - 3 = 5 - 1 = 5 - 2 =
5 - 4 = 5 - 4 = 5 - 3 =
5 - 1 = 4 1 + 4 = 5 2 + 3 = 5
5 - 2 = 3 4 + 1 = 5 3 + 2 = 5
5 - 3 = 2 5 - 1 = 4 5 - 2 = 3
5 - 4 = 1 5 - 4 = 1 5 - 3 = 2
5-1=4 1+4=5 2+3=5
5-2=3 4+1=4 3+2=5
5-3=2 5-1=4 5-2=3
5-4=1 5-4=1 5-3=2
Bài 1
a, Tính P=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+....+1/2012(1+2+3+...+2012)
b,Tìm x thỏa mãn 4^5+4^5+4^5+4^5/3^5+3^5+3^5.6^5+6^5+6^5+6^5+6^5+6^5/2^5+2^5=2^x
Kho..................wa.....................troi.....................thi......................lanh.................ret.......................ai........................tich..........................ung.....................ho........................minh.....................cho....................do....................lanh
Kho..................wa.....................troi.....................thi......................lanh.................ret.......................ai........................tich..........................ung.....................ho........................minh.....................cho....................do....................lanh
BT7: Tính
\(3,C=\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)...\left(5^{16}+1\right)\)
\(4,D=15\left(4^2+1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(5,E=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)...\left(5^{128}+1\right)+\left(5^{256}-1\right)\)
3: =(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^4-1)(5^4+1)(5^8+1)(5^16+1)
=(5^8-1)(5^8+1)(5^16+1)
=(5^16-1)(5^16+1)
=5^32-1
4:
D=(4^4-1)(4^4+1)(4^8+1)*....*(4^64+1)
=(4^8-1)(4^8+1)*...*(4^64+1)
=...
=4^128-1
5: =(5^2-1)(5^2+1)(5^4+1)*...*(5^128+1)+(5^256-1)
=(5^4-1)(5^4+1)*...*(5^128+1)+5^256-1
=5^256-1+5^256-1
=2*5^256-2
3, \(C=\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)....\left(5^{16}+1\right)\)
\(C=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)....\left(5^{16}+1\right)\)
\(C=\left(5^4-1\right)\left(5^4+1\right)....\left(5^{16}+1\right)\)
\(C=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(C=\left(5^{16}-1\right)\left(5^{16}+1\right)\)
\(C=5^{32}-1\)
4, \(D=15\left(4^2+1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(D=\left(4^2-1\right)\left(4^2+1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(D=\left(4^4-1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(D=\left(4^8-1\right)\left(4^8+1\right)...\left(4^{64}+1\right)\)
\(D=\left(4^{16}-1\right)\left(4^{16}+1\right)...\left(4^{64}+1\right)\)
\(D=\left(4^{32}-1\right)\left(4^{32}+1\right)\left(4^{64}+1\right)\)
\(D=\left(4^{64}-1\right)\left(4^{64}+1\right)\)
\(D=4^{128}-1\)
5, \(E=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)...\left(5^{256}+1\right)\)
\(E=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)...\left(5^{128}+1\right)\left(5^{256}+1\right)\)
\(E=\left(5^4-1\right)\left(5^4+1\right)....\left(5^{256}+1\right)\)
....
\(E=\left(5^{128}-1\right)\left(5^{128}+1\right)\left(5^{256}+1\right)\)
\(E=\left(5^{256}-1\right)\left(5^{256}+1\right)\)
\(E=5^{512}-1\)
1+1+1+1+1+1+1=?
2+2+2+2+2+2+2=?
3+3+3+3+3+3+3=?
4+4+4+4+4+4+4=?
5+5+5+5+5+5=?
>, <, = ?
4 – 1 … 5 – 1 | 5 – 3 … 4 – 2 |
5 – 2 … 4 + 1 | 4 + 0 … 5 – 4 |
Lời giải chi tiết:
4 – 1 < 5 – 1 | 5 – 3 = 4 – 2 |
5 – 2 < 4 + 1 | 4 + 0 > 5 – 4 |