67-23=??
B= tan^2 67°+ 2cos^2 16°-cotg^2 23° + 2sin^2 16°- 2cotg 37°/tan 53° A= cotg 67° . Cotg 23°-2(cos 45°. sin 64°)^2-2sin 23°/3cos 67°- sin^2 26°
\(B=tan^267^0-cot^223^0+2\cdot\left(sin^216^0+cos^216^0\right)-2\)
\(=0+2\cdot1-2=0\)
\(A=cot67\cdot tan67-2\left(\dfrac{\sqrt{2}}{2}\cdot sin64\right)^2-2\cdot\dfrac{sin23}{3\cdot sin23}-sin^226^0\)
\(=1-2\cdot\dfrac{1}{2}\cdot sin^264^0-\dfrac{2}{3}-sin^226^0\)
\(=1-1-\dfrac{2}{3}=-\dfrac{2}{3}\)
256, 23 + 12, 56 =
56, 23 + 12, 45 =
89, 67 - 23, 45 =
1, 23 + 34, 67
19, 56 + 45, 65 =
tinh nhanh
28(29-23) - 29(28-23)
(-167). (67-34)-67.(34-167)
28(29-23) - 29(28-23)
= 812-644-812+667
= 23
(-167).(67-34)-67.(34-167)
= -11189+5678-2278+11189
= 3400
28(29-23) - 29(28-23)
= 812-644-812+667
= 23
(-167).(67-34)-67.(34-167)
= -11189+5678-2278+11189
= 3400
28(29-23) - 29(28-23)
= 812-644-812+667
= 23
(-167).(67-34)-67.(34-167)
= -11189+5678-2278+11189
= 3400
đây nha
tick cho mk nha
67 + 12 = ?
67 + 23 = ?
\(67+12=79\)
\(67+23=90\)
hok tốt
Bài 2. (1 điểm) Thực hiện phép tính:
a) $67. 36 + 67. 65 - 67$;
b) $(7^{23}. 45 + 7^{23}. 4) \, : \, 7^{25}$.
a)
=67.(36+65-1)
=67.100
=6700
b)
=[723.(45+4)]:725
=[723. 49 ]:725
=[723. 72 ]:725
=725 :725
=1
a) 67.36 + 67.65 - 67 = 67.\(\left(36+65-1\right)\) = 67. 100 = 6700
b) \(\left(7^{23}.45+7^{23}.4\right):7^{25}\) = \(7^{23}.\left(45+4\right):7^{25}=7^{23}.7^2:7^{25}=1\)
Tính: 23 x 67 + 23 x 34 - 23
23 x 67 +23 x 24 -23 = 23 x \(\left(67+34-1\right)\)=23x 100 = 2300
đúng nhé
mình chán tính nhanh lắm rùi bạn lấy máy tính casio bấm cho nhanh
23+45+34+67+89+14+67+69+34=
23 + 67 = ?
23 + 78 = ?
23 + 67 = 90
23 + 78 =101
Ủng hộ nha !
tính bằng cách hợp lí nhất
a) 31/23 - (7/23 + 8/23)
b) (1/3 + 12/67 + 13/41 ) - (79/67 - 28/41 )
c) 38/45 - ( 8/45 - 17/51- 3/11 )
Tính hợp lí: a. 31/23 - (7/23 + 8/23). b.(1/3 + 12/67+13/41) - (79/67 - 28/41). c. 38/45 - (8/45 - 17/51 - 3/11)
\(a\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)
\(=\frac{31}{23}-\frac{7}{23}-\frac{8}{23}\)
\(=\frac{16}{23}\)
Hot
tốt
!
a)\(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)=\frac{31}{23}-\frac{8}{23}+\frac{7}{23}=1+\frac{7}{23}=1\frac{7}{23}\)
b)\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)=\left(\frac{13}{41}+\frac{28}{41}\right)+\left(\frac{79}{67}-\frac{12}{67}\right)-\frac{1}{3}=1+1-\frac{1}{3}\)
\(=2-\frac{1}{3}=\frac{5}{3}\)