a) \(x+5=20-\left(12-7\right)\)

\(\Rightarrow x+5=20-5\)

\(\Rightarrow x+5=15\)

\(\Rightarrow x=15-5\)

\(\Rightarrow x=10\)

b) \(15-\left(3+2x\right)=2^2\)

\(\Rightarrow3+2x=15-4\)

\(\Rightarrow3+2x=11\)

\(\Rightarrow2x=11-3\)

\(\Rightarrow2x=8\)

\(\Rightarrow x=\dfrac{8}{2}\)

\(\Rightarrow x=4\)

c) \(-11-\left(19-x\right)=50\)

\(\Rightarrow19-x=-11-50\)

\(\Rightarrow19-x=-61\)

\(\Rightarrow x=61+19\)

\(\Rightarrow x=80\)

d) \(159-\left(25-x\right)=43\)

\(\Rightarrow25-x=159-43\)

\(\Rightarrow25-x=116\)

\(\Rightarrow x=25-116\)

\(\Rightarrow x=-91\)

e) \(\left(79-x\right)-43=-\left(17-52\right)\)

\(\Rightarrow\left(79-x\right)-43=52-17\)

\(\Rightarrow79-x-43=35\)

\(\Rightarrow36-x=35\)

\(\Rightarrow x=1\)

f) \(\left(7+x\right)-\left(21-13\right)=32\)

\(\Rightarrow7+x-8=32\)

\(\Rightarrow x-1=32\)

\(\Rightarrow x=32+1\)

\(\Rightarrow x=33\)

g) \(-x+20=-15+8+13\)

\(\Rightarrow-x+20=6\)

\(\Rightarrow x=20-6\)

\(\Rightarrow x=14\)

h) \(-\left(-x+13-142\right)+18=55\)

\(\Rightarrow x-13+142+18=55\)

\(\Rightarrow x+147=55\)

\(\Rightarrow x=55-147\)

\(\Rightarrow x=-92\)

\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)

\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)

\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)

\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)

1)\(3,5\cdot x+1,54\cdot3,5=15\)

    \(3,5\left(x+1,54\right)=15\)

                 \(x+1,54=\frac{15}{3,5}\)

                 \(x+1,54=\frac{30}{7}\)

                                \(x=\frac{30}{7}-1,54\)

                                 \(x=\frac{30}{7}-\frac{77}{50}\)

                               \(x=\frac{961}{350}\)

\(20+\frac{12}{x-2019}=32\)

             \(\frac{12}{x-2019}=32-20\)

              \(\frac{12}{x-2019}=12\)

               \(x-2019=\frac{12}{12}\)

              \(x-2019=1\)

                               \(x=1+2019\)

2)

\(\frac{3}{7}\cdot\frac{4}{13}+\frac{3}{7}\cdot\frac{9}{13}+5\frac{4}{7}\)

\(=\frac{3}{7}\cdot\frac{4}{13}+\frac{3}{7}\cdot\frac{9}{13}+13\cdot\frac{3}{7}\)

\(=\frac{3}{7}\left(\frac{4}{13}+\frac{9}{13}+13\right)\)

\(=\frac{3}{7}\cdot14\)

\(=6\)

3.5*(x-1.54)=15

x+1.54=15;3.5

x+1.54=4.28

x=4.28-1.54

x=2.74

chưa suy nghĩ

3,5×(x+1,54)=15

(x+1,54)=15:3,5

(x+1,54)=30/7

(x+77/50)=30/7

x=30/7-77/50

x=961/350

a. -13 - (5-x) = -10
-13 - 5 + x = -10
x = -10 + 13 + 5
x = 8
Vậy x = 8
b, -3x - 15 = 2x - 20
-3x - 2x = -20 + 15
-5x = -5
x = -5 : (-5)
x = 1
Vậy x = 1
c, 5 - (x-3)^2 = 20
(x-3)^2 = 5 - 20 
(x-3)^2 = -15 ( vô lí )

Vậy không có giá trị x thỏa mãn
d. | x - 12 | - (-5) = 12
| x - 12 | = 12 + (-5)
| x - 12 | = 7
x - 12  = + - 7
(+) x - 12 = 7           (+) x - 12 = -7
x = 7 + 12                        x     = -7 + 12
X = 19                              x     = 5

Vậy x thuộc { 19 ; 5 }
 

1) \(\dfrac{11}{12}\times\dfrac{28}{13}-\dfrac{11}{12}\times\dfrac{15}{13}=\dfrac{11}{12}\times\left(\dfrac{28}{13}-\dfrac{15}{13}\right)=\dfrac{11}{12}\times\dfrac{13}{13}=\dfrac{11}{12}\times1=\dfrac{11}{12}\)

Vậy biểu thức trên có kết quả là : \(\dfrac{11}{12}\)

2) \(x+653=87\times11\)

    \(x+653=957\) 

    \(x=957-653\)

    \(x=304\)

Vậy `x = 304 `

3) \(\text{70 000 + 800 + 20 + 9}=70829\)

12 + 13 =20 + x

25 = 20 +x

20 + x =25

       x =25 - 20 

        x =5

t nha bn thak nhìu

12 + 13 = 20 + x 

25 = 20 + x 

x = 25 - 20 

x = 5 

12 + 13 = 20 - x

25 = 20 - x

x = 25 - 20 

x = 5

a,x+9=20-(12-75)-(-8)

  x+9=20-(-63) + 8

  x+9 = 20 + 63 + 8

  x+9 = 91

   x    = 91 - 9

   x    = 82.

Vậy x = 82.

b,2.|x-3|=16-(-3)-(-13)-2

 2.|x-3|=16 + 3 + 13 - 2

  2.|x-3|= 30

     |x-3| = 30:2

     |x-3| = 15

\(\Rightarrow\orbr{\begin{cases}x-3=15\\x-3=-15\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=18\\x=-12\end{cases}}\)

Vậy x \(\in\){ 18 ; -12 }

# HOK TỐT #

a, x+9=20-(12-75)-(-8)

x+9=91

x    =91-9

x    =82

b,2.|x-3|=16-(-3)-(-13)-2

2.|x-3| =30

|x-3|=30:2

|x-3|=15

--> x-3=15             hoặc              x-3= -15

    x=15+3                                    x= -15+3

     x=18                                       x= -12

Vậy x thuộc {18;-12}

a,x+9=20-(12-75)-(-8)

   x+9=20-12+75+8

   x+9=8+75+8

   x+9=83+8

   x+9=91

       x=91-9

       x=82

Vậy x=82

b,2.|x-3|=16-(-3)-(-13)-2

   2.|x-3|=16+3+13-2

   2.|x-3|=19+13-2 

   2.|x-3|=32-2 

   2.|x-3|=30

      |x-3|=30:2

      |x-3|=15

\(\Rightarrow\orbr{\begin{cases}x-3=15\Rightarrow x=15+3=18\\x-3=-15\Rightarrow x=-15+3=-12\end{cases}}\)

Vậy.......................................................

a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)

= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)

= - 1 + 1  - \(\dfrac{11}{20}\)

=   0 - \(\dfrac{11}{20}\)

= - \(\dfrac{11}{20}\)

b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)

= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)

= \(\dfrac{10}{12}\)

= \(\dfrac{5}{6}\)

c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)

= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)

= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)

= \(\dfrac{14}{3}\)

d; 1,25 : \(\dfrac{15}{20}\) + [25% - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)

= 1,25  x \(\dfrac{20}{15}\) + [\(\dfrac{1}{4}\) - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)

=  \(\dfrac{5}{3}\) - \(\dfrac{7}{12}\) : 4 x \(\dfrac{2}{3}\)

= \(\dfrac{5}{3}\) - \(\dfrac{7}{48}\).\(\dfrac{2}{3}\)

= \(\dfrac{5}{3}\) - \(\dfrac{7}{72}\)

= \(\dfrac{113}{72}\)