Đáp số: 4700

32.27 + 47.73 + 27.15

= (32.27+27.15)+47.73

=27.(32+15)+47.73

= 27.47 + 47.73

= 47.(27+73)

= 47. 100

=4700

giải luôn ko ghi đề bài nhé

(99.53+49.47)+200

149+200

349

HỌC TỐT ^^

99 . 53 + 49 . 47 + 200

= (49 + 50) . 53 + 49 . 47 + 200

= 49 . 53 + 49 . 47 + 53 . 50 + 200

= 49 . (53 + 47) + 2650 + 200

= 4900 + 2850

= 7750

Em cảm ơn ạ

\(\dfrac{5}{7}\).\(\dfrac{-3}{11}\)-\(\dfrac{5}{7}\).\(\dfrac{8}{11}\)+1\(\dfrac{5}{7}\)

= \(\dfrac{5}{7}\).(\(\dfrac{-3}{11}\) - \(\dfrac{8}{11}\)) + 1\(\dfrac{5}{7}\)

= \(\dfrac{5}{7}\). -1             + 1\(\dfrac{5}{7}\)

= \(\dfrac{-5}{7}\)               +1\(\dfrac{5}{7}\)

= -1

\(\dfrac{5}{7}.-\dfrac{3}{11}-\dfrac{5}{7}.\dfrac{8}{11}+1\dfrac{5}{7}\)

\(=\dfrac{5}{7}.\left(\dfrac{3}{11}-\dfrac{8}{11}\right)+1\dfrac{5}{7}\)

\(=\dfrac{5}{7}.\left(-1\right)+1\dfrac{5}{7}\)

\(=1\)

15 - (+72) + (+75) + (+72)

= 15 - 72 + 75 + 72

= -57 + 75 + 52

= 18 + 52

= 70

 1-2-3+4+5-6-...+2009-2010

=(1-2-3+4)+(5-6-7+8)+...+(2009-2010)

=    0        +      0       +....+    (-1)

=      -1

\(1-2-3+4+5-6-.....+2009-2010\)

\(=1-2-3+4+5-6-7+8+.....+2006-2007-2008+2009-2010\)(bước này là mk viết rõ ra thôi)

\(=\left(1-2-3+4\right)+\left(5-6-7+8\right)+...+\left(2006-2007-2008+2009\right)-2010\)

\(=0+0+......+0-2010\)

\(=-2010\)

~ học tốt ~

nhớ  

\(\dfrac{1}{12345}-3\dfrac{3}{4}+0,125+3\dfrac{3}{4}-\dfrac{1}{8}-\dfrac{1}{12345}\)

\(=\left(\dfrac{1}{12345}-\dfrac{1}{12345}\right)+\left(-3\dfrac{3}{4}+3\dfrac{3}{4}\right)+\left(0,125-\dfrac{1}{8}\right)\)

\(=0+0+\left(\dfrac{1}{8}-\dfrac{1}{8}\right)\)

\(=0\)

#Toru

\(\Leftrightarrow5^3\times\left(-2\right)^3\times\left(-61\right)\times1\)\(1\)

\(=[5\times\left(-2\right)]^3\times\left(-61\right)\)

\(=\left(-10\right)^3\times\left(-61\right)\)

\(=\left(-1000\right)\times\left(-61\right)\)

\(=61000\)

\(\frac{-7}{9}\cdot\frac{4}{11}+\frac{-7}{9}\cdot\frac{7}{11}+5\frac{7}{9}\)

\(=\frac{-7}{9}\cdot\left[\frac{4}{11}+\frac{7}{11}\right]+5\frac{7}{9}\)

\(=\frac{-7}{9}\cdot1+5+\frac{7}{9}\)

\(=\frac{-7}{9}+5+\frac{7}{9}=\frac{-7}{9}+\frac{7}{9}+5=5\)

\(\frac{-7}{9}.\frac{4}{11}+\frac{-7}{9}+\frac{7}{11}+5\frac{7}{9}\)

\(=\frac{-7}{9}.\left(\frac{4}{11}+\frac{7}{11}\right)+\frac{52}{9}\)

\(=\frac{-7}{9}.1+\frac{52}{9}\)

\(=\frac{-7}{9}+\frac{52}{9}\)

\(=\frac{45}{9}=5\)

-7/9 . 4/11 + (-7/9) . 7/11+ 5 . 7/9= -7/9 .( 4/11+ 7/11)+(-5) .(- 7/9)

                                               = -7/9 . 1 +(-5) . (-7/9)

                                               = -7/9.(1 + -5)

                                               = -7/9 . (-4)

                                               =28/4

cho mình chữa lại đề nha: cái phân số cuối 7/13 chữa lại thành 7/23.