lần sau chuyển số kg gạo là 2850*3=8550(kg)
còn lại số kg gạo là 34560 -2850-8550=23160(kg)
đáp số 23160 kg gạo

= 135 + 135 - 135

=  135 +0

= 135

135

=135(37+64-1)=135*100=13500

=135x (124-23-1)

=135 x 100

=13500

   135 x 124 - 135 x 23 - 135

= 135 x 124 - 135 x 23 - 135 x 1

= 135 x ( 124 - 23 - 1)

= 135 x ( 101 - 1)

= 135 x 100

= 13500

=135x (124-23-1)

=135 x 100

=13500

(135.269-133)-(135.269-135)

=(135.269-135.269)+(135-133)

=0+2

=2

Đáp án: 135 x 80 + 20 x 135    =   135 x ( 80 + 20 )

135⁹¹ - 135⁸⁹ = 135⁸⁹ x ( 135² - 1 ) 

135¹⁰⁰ - 135⁹⁹ = 135⁹⁹ x ( 135 - 1 ) = 135⁹⁹ x 134 = 135⁸⁹ x 135¹⁰ x 134 = 135⁸⁹ x  ( 135¹⁰ x 134 )

Có : 135² - 1 < 135¹⁰ x 134

=> 135⁸⁹ x ( 135² - 1 ) < 135⁸⁹ x ( 135¹⁰ x 134 )

=> 135⁹¹ - 135⁸⁹ < 135¹⁰⁰ - 135⁹⁹

Ta có:

\(135^{91}-135^{89}=135^{89}\times\left(135^2-1\right)\)

\(135^{100}-135^{99}=135^{99}\times\left(135-1\right)=135^{99}\times134=135^{89}\times134=135^{89}\times\left(135^{10}\times34\right)\)

Có: \(135^2-1< 135^{10}\times134\)

\(\Rightarrow135^{89}\times\left(135^2-1\right)< 135^{89}\times\left(135^{10}\times134\right)\)

\(\Rightarrow135^{91}-135^{89}< 135^{100}-135^{99}\)

Vậy \(135^{91}-135^{89}< 135^{100}-135^{99}\)

135 x 37 + 135 +  62 x 135

= 135 x 37 + 135 x 1 +  62 x 135

= 135 x ( 37 + 1 + 62)

 = 135 x 100

= 13500

Ta có:

60 = 2^2 .3.5;     90 = 2.3^2.5;     135 = 3^3 .5

<-> ƯCLN(60, 90, 135) = 3.5 = 15.

ƯC(60, 90, 135) = Ư(15) = {1, 3, 5, 15}

--thoT-T--

\(60=2^2.3.5\)

\(90=2.3^2.5\)

\(135=3^3.5\)

\(\Rightarrow ƯCLN(60;90;135)=3.5=15\)