Tim X
x(2x-1)(x+5) - (2x^2 +1)(x + 4.5) =3.5
giup minh nha
Tìm x :
a) x(2x-1)(x+5)-(2x^2+1)(x+4.5)=3.5
dấu .(chấm) là nhân nha
timx
x(2x-1)(x+5)-(2x^2+1)(x+4.5)=3.5
\(\Leftrightarrow x\left(2x^2+10x-x-5\right)-\left(2x^3+9x^2+x+4.5\right)=3.5\)
\(\Leftrightarrow2x^3+9x^2-5x-2x^3-9x^2-x-4.5=3.5\)
=>-6x=8
hay x=-4/3
2x - ( x - 3 ) = 1/2
Tim x.
Giup minh nha
\(2x-\left(x-3\right)=\frac{1}{2}\)
\(\Leftrightarrow2x-x+3=\frac{1}{2}\)
\(\Leftrightarrow2x-x=\frac{1}{2}-3\)
\(\Leftrightarrow x\left(2-1\right)=\frac{1}{2}-\frac{6}{2}\)
\(\Leftrightarrow x=\frac{-5}{2}\)
\(2x-\left(x-3\right)=\frac{1}{2}\)
\(\Leftrightarrow2x-x+3=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}-3\)
\(\Leftrightarrow x=\frac{1}{2}-\frac{6}{2}=-\frac{5}{2}\)
2x- x + 3 = 1/2
x = 1/2 - 3
x=- 5 /2
Tim x
a, 2(x- 1/3)+3x=7/4
b, x-1/3 == 27/x-1
c, 2x +1/x+3= 2x+3/ x +5
Tick nha!
a. \(2\left(x-\dfrac{1}{3}\right)+3x=\dfrac{7}{4}\)
=> \(2x-\dfrac{2}{3}+3x=\dfrac{7}{4}\)
=> \(2x+3x=\dfrac{7}{4}+\dfrac{2}{3}\)
=> \(5x=\dfrac{29}{12}\)
=> \(x=\dfrac{29}{60}\)
Câu b và c vế 2 mk ko biết dấu / của bạn là chia hay phân số
#Yiin
tìm x
\(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4.5\right)=3.5\)
#)Giải :
\(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Leftrightarrow\left(2x^2-x\right)\left(x+5\right)-2x^3-9x^2-x-4,5=3,5\)
\(\Leftrightarrow2x^3+10x^2-x^2-5x-2x^3-9x^2-x-4,5=3,5\)
\(\Leftrightarrow-5x-4,5=3,5\)
\(\Leftrightarrow-5x=8\)
\(\Leftrightarrow x=-\frac{8}{5}\)
\(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Leftrightarrow\left(2x^2-x\right)\left(x+5\right)-\left(2x^3+9x^2+x+4,5\right)=3,5\)
\(\Leftrightarrow2x^3+10x^2-x^2-5x-2x^3-9x^2-x-4,5=3,5\)
\(\Leftrightarrow-6x=8\)
\(\Leftrightarrow x=\frac{-8}{6}=\frac{-4}{3}\)
giai dum minh bai nay voi :c=x/2x-2+x^2+1/2-2x^2
a)tim x de a co nghia
b)rut gon bieu thuc c
c)tim gia tri cua x de bieu thuc kia =1/2
giúp mình cảm ơn nhìu nha !
tim x biet
a) 4(x+1)^2-9(x+2)^2=0
b) 4(x+1)^2+(2x-1)^2-8(x+1)(x-1)=11
giai cach lam giup minh nha
viết vế trái dưới dang tich roi tim x : câu a) x mũ 2 -4x +3 =0 . Câu b) x mũ 2 - 13/6 x +1>0 . Câu c) 2x mũ 2 - 7x + 5 < hoac bang 0 . giải nhanh giùm minh nha minh tick cho
ho minh nha
\(\frac{7^{x+1}+7^{x+2}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
\(\Leftrightarrow\frac{7^x.7+7^x.7^2+7^x}{57}=\frac{5^{2x}.1+5^{2x}.5+5^{2x}.5^3}{131}\)
\(\Leftrightarrow\frac{7^x\left(7+49+1\right)}{57}=\frac{5^{2x}\left(1+5+125\right)}{131}\)
\(\Leftrightarrow\frac{7^x.57}{57}=\frac{5^{2x}.131}{131}\)
<=> 7x = 52x
<=> \(\frac{7^x}{5^{2x}}=1\)
<=> \(\frac{7^x}{25^x}=1\)
<=> \(\left(\frac{7}{25}\right)^x=1\)
<=> x = 0