\(\left(1+\frac{2}{3}-\frac{1}{4}\right)\left(0,8-\frac{3}{4}\right)^2\)
Giải giúp mình nhé, thank!
Tính:
\(\frac{0,8\div\left(\frac{4}{5}\times1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{5}\right)\div\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\times2\frac{2}{17}}+\left(1,2\times0,5\right)\div\frac{4}{5}\)
giúp mình với nhé mn, nhanh nha mình cần gấp
ta có:4/5:(4/5*5/4)/16/25-1/25+(27/25-2/25):4/7/(59/9-13/4)*36/17+6/5*1/2
=4/5:3/5+7/4:7+3/5
=4/3+1/4+3/5
=3/2+3/5=21/10
Giúp mình với ạ:
1) (0,4x-2) - (1,5x+1)- (-4x-0,8)=3,6
2) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
3) x+2x+3x+4x+...+100x=-21
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
giúp mình nhé
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}-\frac{3}{2}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{6}{5}\)
\(=-8+\left(\frac{3}{2}-\frac{3}{2}\right)+1+\frac{6}{5}\)
\(=-7+\frac{6}{5}\)
\(=\frac{-35}{5}+\frac{6}{5}=-\frac{29}{5}\)
\(F=\frac{\left(\frac{53}{4}-2\frac{5}{27}-\frac{65}{6}\right).\left(230+\frac{1}{25}\right)+46\frac{3}{4}}{\left(\frac{24}{7}+3\frac{1}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
giúp mình nhé các bạn
\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)
giải thích ra nhé
=\(\frac{-16}{5}.\frac{-15}{64}+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)
= \(\frac{-16.\left(-15\right)}{5.64}+\left(\frac{12}{15}-\frac{34}{15}\right).\frac{2}{7}\)
=\(\frac{-1.\left(-3\right)}{1.4}+\left(\frac{-22}{15}\right).\frac{2}{7}\)
=\(\frac{3}{4}-\frac{44}{105}=\frac{315}{420}-\frac{176}{420}=\frac{139}{420}\)
\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)
\(=0,75+\left(0,8-\frac{34}{15}\right):\frac{7}{2}\)
\(=0,75+\frac{46}{15}:\frac{7}{2}\)
\(=0,75+\frac{46}{15}.\frac{2}{7}\)
\(=0,75+\frac{92}{105}=\frac{683}{420}\)
Tính \(S=\left(1+\frac{1}{2}\right)\left(1+\frac{1}{2}+\frac{1}{3}\right)\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)+...+\left(1+\frac{1}{2}+...+\frac{1}{10}\right)\)
Các bạn giúp mình nhé !~~~
Tính
a) \(\left( {\frac{4}{5} - 1} \right):\frac{3}{5} - \frac{2}{3}.0,5\)
b) \(1 - {\left( {\frac{5}{9} - \frac{2}{3}} \right)^2}:\frac{4}{{27}}\)
c)\(\left[ {\left( {\frac{3}{8} - \frac{5}{{12}}} \right).6 + \frac{1}{3}} \right].4\)
d) \(0,8:\left\{ {0,2 - 7.\left[ {\frac{1}{6} + \left( {\frac{5}{{21}} - \frac{5}{{14}}} \right)} \right]} \right\}\)
a)
\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)
b)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Giúp mình với, mình đang cần gấp lắm nhé các bạn!
tính
A=\(1+\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+1.\left(1+2+3+4\right)\frac{1}{100}.\left(1+2+3+4+...+100\right)\)
Các bạn giúp mình nha. Thank các bạn nhiều