Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)

\(\Leftrightarrow100x+5050=5750\)

\(\Leftrightarrow100x=700\)

hay x=7

x=7

tham kharo : https://olm.vn/hoi-dap/detail/89184552036.html

(x+1)+(x+2)+...+(x+100)=5750

(x+x+...+x)+(1+2+3+...+100)=5750

100x+5050=5750

100x=5750-5050

100x=700

x=700/100

x=7

\(\Leftrightarrow100x+5050=5750\)

hay x=7

(x+1) + (x+2) + (x+3) +....+ (x+100) = 5750

x + 1 + x + 2 + x + 3 +...+ x + 100 = 5750

(x + x + x +...+ x) + (1 + 2 + 3 +...+ 100) = 5750

100x + 5050 = 5750

100x = 5750 - 5050

100x = 700

x = 700 : 100

x = 7

=>100x+5050=5750

=>100x=700

=>x=7

Ta có : (x+1) +(x+2) +......+(x+100)=5750

\(\Leftrightarrow\) 100.x +(1+2+...+100) =5750

\(\Leftrightarrow\) 100.x +5050       =5750

\(\Leftrightarrow\) 100x        =5750-5050

\(\Leftrightarrow\) 100.x =700

\(\Leftrightarrow\)x=700: 100

\(\Leftrightarrow\) x =7

 Vậy x=7

Có 100 nhóm nên có 100 số x

(x+x+...+x)+(1+2+3+4+...+100)=5750

x.100 + 5050=5750

x.100=5750-5050

x.100=700

x=700:100

x=7

( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 5750

( x x + x + x + ... + x ) + ( 1 + 2 + 3 + 4 + ... + 100 ) = 5750

100x + ( 100 + 1 ) x 100 : 2 = 5750

100x + 101 x 50 = 5750

100x + 5050 = 5750

100x = 5750 - 5050

100x = 700

x = 700 : 100

x = 7

( x +1 )+ ( x + 2 ) + ... +  ( x + 100 ) = 5750

( x + x + x + ...+ x ) + ( 1 + 2 + ... + 100 ) = 5750

x * 100 + 5050 = 5750

x * 100 = 700

x = 7

(x+1)+(x+2)+...+(x+100)=5750

=> (x+x+.....+x)+(1+2+3+......+100)=5750

=> 100x+(100+1).100:2=5750

=> 100x+10100:2=5750

=> 100x+5050=5750

=> 100x=5750-5050

=> 100x=700

=> x=7

Có ai muốn kết ban voi mik ko?

(x+1)+(x+2)+.............+(x+100)=5750

<=>x+1+x+2+............+x+100=5750

=>(x+x+...........+x)+(1+2+...........+100)=5750

=>100x+5050=5750

=>100x=700

=?x=700:7

=>x=7

(2x+1)+(2x+2)+...+(2x+2015)=0

Vì cứ 1 số hạng lại có 2x

 Số số hạng từ 1 đến 2015 là:

   (2015-1):1+1=2015(số)

 Tổng dãy số là:

   (2015+1)x2015:2=2031120

Do đó có 2015 2x

Ta có:

(2x+1)+(2x+2)+...+(2x+2015)=0

2015.2x+(1+2+...+2015)=0

4030x+2031120=0

4030x=-2031120

x=-2031120:4030

x=-504

Vậy x=-504

(x+1)+(x+2)+...+(x+100)=5750

x+1+x+2+...+x+100= 5750

100.x+ 5050= 5750

100.x= 5750-5050

100.x= 700

x= 700:100

x=7.

Vậy x=7