\(Xx\left(9-2\right)=63\)
\(Xx7=63\)
\(X=63:7=9\)

x(9-2)=63

x . 7= 63

x=63:7

x=9

X x (9 - 2) = 63

X x 7 = 63

x = 63 : 7

x = 9

X + 6 = 33

X = 33 − 6

X = 27

9 + x = 22

X = 22 − 9

X = 13

X − 41 = 41

X = 41 + 41

X = 82

X x 9 - X x 2 = 41 + 22

X x 9 - X x 2 = 63

X x ( 9 - 2 ) = 63

X x 7 = 63 

X = 63 : 7

X = 9

Vậy : X = 9

tớ nhanh nhất đó

x = 9 đó bạn

A.-9/2

b.-5/7

C.5/287

D.302/105

nêu cách tính nha bạn 

kho the

1) 41 - 2^{x + 1} = 9

-2^{x + 1} = 9 - 41

-2^{x + 1} = -32

2^{x + 1} = 32

2^{x + 1} = 2⁵

x + 1 = 5

x = 5 - 1

x = 4

\(41-2^x+1=9\)

\(41-2^x=9-1=8\)

\(2^x=41-8=33\)

\(x=\sqrt{33}\)

giải nữa.  bạn ơi

(\(x\) + \(\dfrac{3}{5}\))² + \(\dfrac{41}{25}\)  = 9%: 4,5%

(\(x\) + \(\dfrac{3}{5}\))² + \(\dfrac{41}{25}\) = 2

(\(x\) + \(\dfrac{3}{5}\))²          = 2 - \(\dfrac{41}{25}\)

(\(x\) + \(\dfrac{3}{5}\))² = \(\dfrac{9}{25}\)

\(\left[{}\begin{matrix}x+\dfrac{3}{5}=\dfrac{3}{5}\\x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\)

  \(\left[{}\begin{matrix}x=\dfrac{3}{5}-\dfrac{3}{5}\\x=-\dfrac{3}{5}-\dfrac{3}{5}\end{matrix}\right.\)

   \(\left[{}\begin{matrix}x=0\\x=-\dfrac{6}{5}\end{matrix}\right.\)

Vậy \(x\in\) {-1; \(\dfrac{1}{5}\)}

\(\dfrac{9}{10}\)

\(\dfrac{1}{24}\)

\(\dfrac{5}{2}\)

9/10

1/24

5/2

= 9/10

= 1/24

= 5/2