\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)

\(a,\dfrac{52}{32}=\dfrac{13}{8}\\ \dfrac{55}{65}=\dfrac{11}{13}\\ MSC:104\\ =>\dfrac{13}{8}=\dfrac{13.13}{8.13}=\dfrac{169}{104}\\ \dfrac{11}{13}=\dfrac{11.8}{13.8}=\dfrac{88}{104}\)

\(b,\dfrac{72}{64}=\dfrac{9}{8}\\ \dfrac{54}{81}=\dfrac{2}{3}\\ MSC:24\\ \dfrac{9}{8}=\dfrac{9.3}{8.3}=\dfrac{27}{24}\\ \dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\\ c,\dfrac{24}{36}=\dfrac{2}{3}\\ \dfrac{12}{30}=\dfrac{2}{5}\\ MSC:15\\ \dfrac{2}{3}=\dfrac{2.5}{3.5}=\dfrac{10}{15}\\ \dfrac{2}{5}=\dfrac{2.3}{3.5}=\dfrac{6}{15}\)

\(d,\dfrac{80}{40}=2\\ \dfrac{45}{63}=\dfrac{5}{7}\\ MSC:7\\ 2=\dfrac{14}{7}\\ e,\dfrac{150}{50}=3\\ \dfrac{100}{200}=\dfrac{1}{2}\\ MSC:2\\ 3=\dfrac{6}{2}\\ f,\dfrac{54}{81}=\dfrac{2}{3}\\ \dfrac{69}{93}=\dfrac{23}{21}\\ MSC:21\\ \dfrac{2}{3}=\dfrac{2.7}{3.7}=\dfrac{14}{21}\)

\(a.\dfrac{52}{32}\text{=}\dfrac{13}{8};\dfrac{55}{65}\text{=}\dfrac{11}{13}\)

\(\dfrac{13.13}{13.8}\text{=}\dfrac{169}{104};\dfrac{11.8}{13.8}\text{=}\dfrac{88}{104}\)

\(c.\dfrac{24}{36}\text{=}\dfrac{2}{3};\dfrac{12}{30}\text{=}\dfrac{2}{5}\)

\(\dfrac{2.5}{3.5}\text{=}\dfrac{10}{15};\dfrac{2.3}{5.3}\text{=}\dfrac{6}{15}\)

\(b.\dfrac{72}{64}\text{=}\dfrac{9.3}{8.3}\text{=}\dfrac{27}{24};\dfrac{54}{81}\text{=}\dfrac{2.8}{3.8}\text{=}\dfrac{16}{24}\)

\(d.\dfrac{80}{40}\text{=}\dfrac{2.63}{63}\text{=}\dfrac{126}{63};\dfrac{45}{63}\)

\(e.\dfrac{150}{50}\text{=}\dfrac{3.2}{2}\text{=}\dfrac{6}{2};\dfrac{100}{200}\text{=}\dfrac{1}{2}\)

\(f.\dfrac{54}{81}\text{=}\dfrac{2.31}{3.31}\text{=}\dfrac{62}{93};\dfrac{69}{93}\)

Cái này có tất cả 4 cặp số và dư 1 số 95

Khoảng cách giữa 2 số là 1 đơn vị

=> (99 + 91) + (98 + 92) + (97 + 93) +( 96 + 94) + 95

= 190 + 190 + 190 + 190 + 95 = 855

Hay có cách khác ngắn gọn hơn

(99 + 91).4 + 95 = 855 (1 đơn vị nhân ra cũng vậy nên không viết)

=(99+91)+(98+92)+(97+93)+(96+94)+95=190+190+190+190+95=190*4+95=760+95=855

( 99 + 91 ) + ( 98 + 92 ) + ( 97 + 93 ) + (96 + 94 ) + 95

=190 + 190 + 190 + 190 +95

= 190 x 4 + 95

= 855

\(\dfrac{51}{53}+\dfrac{55}{57}+\dfrac{61}{63}+\dfrac{69}{71}+\dfrac{79}{81}+\dfrac{91}{93}\) 

\(=\left(\dfrac{52}{53}-\dfrac{1}{53}\right)+\left(\dfrac{56}{57}-\dfrac{1}{57}\right)+\left(\dfrac{62}{63}-\dfrac{1}{63}\right)+\left(\dfrac{70}{71}-\dfrac{1}{71}\right)+\left(\dfrac{80}{81}-\dfrac{1}{81}\right)+\left(\dfrac{92}{93}-\dfrac{1}{93}\right)\)

\(=\left(1-\dfrac{1}{53}-\dfrac{1}{53}\right)+\left(1-\dfrac{1}{57}-\dfrac{1}{57}\right)+\left(1-\dfrac{1}{63}-\dfrac{1}{63}\right)+\left(1-\dfrac{1}{71}-\dfrac{1}{71}\right)+\left(1-\dfrac{1}{81}-\dfrac{1}{81}\right)+\left(1-\dfrac{1}{93}-\dfrac{1}{93}\right)\)

\(=\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)+\left(1-0\right)\) 

\(=1+1+1+1+1+1\) 

\(=6\)

a) 3 ^ 6 : 3 ^ 2 + 2 ^ 3 + 2 ^ 2 

 = 3^{6 - 2}  + 2^{3 + 2} 

  = 3⁴ + 2⁵  = 81 + 32 

  = 113 .

b) ( 2100 - 63 ) : 21

 = 2037 : 21

 = 97 .

c) 32 x 59 + 41 x 32

 = 32 x ( 59 + 41 )

 = 32 x 100

 = 3200 .

d) 99 - 97 + 95 - 93 + 91 - 89 + ... + 7 - 5 + 3 - 1 ( 50 so = 25 hieu )

= 2 + 2 + 2 + ... + 2 + 2 = 2 x 25 

= 50 .

a)   \(3^6:3^2+2^3.2^2=3^4+2^5=113\)

b)   \(\left(2100-63\right):21=2037:21=97\)

c)    \(32.59+41.32=32.\left(59+41\right)=32.100=3200\)

d)   \(99-97+95-93+........+9-7+5-3+1=2+2+...+2+1=25.2+1=50+1=51\)

giải giúp mik bài này nha

12x-33=3^2.3^3

a) 198 + 232 - 98 -  32 = (232 - 32) + (198 - 98) = 300.

b) 567 - 32 - 68 = 567 - (32 + 68) = 467.

c) 99 - 97 + 95 - 93 + 91 - 89+ ...+7 - 5 + 3 - 1

= (99 - 97) + (95 - 93) + (91 - 89) +... + (7 - 5) + (3 -1)

= 2 + 2 + 2 + . .. + 2 + 2 = 2.25 = 50.