Tìm x biết (x * 8 + 7 * 8) + (x * 4 - 7 * 4) = (x * 3 + 3 * 3) + (x + 4 - 3 * 4)
Tìm x biết :
1/-5 +(-3+12-x)=7-(2-8)
2/8-(7-x+3)=-|-7+2|-(-9)
3/-(12-5+9-x)=3-|5-8+2|
4/-(-3-x+8)-(-3+5)=|5-8|
5/-|5-8|-(4-x+5)=4+|3-9|
mình đang cần gấp câu trả lời ,bạn nào giải được nhanh k luôn ,hứa đấy
1) -5+(-3+12-x)=7-(2-8)
=>-5+(9-x)=7-(-6)
=>-5+9-x=13
=>x=9-5-13=-9
2) 8-(7-x+3)=-|-7+2|-(-9)
=>8-(10-x)=-|-5|+9
=>8-10+x=-5+9
=>x=-5+9-8+10=6
3)-(12-5+9-x)=3-|5-8+2|
=>-(16-x)=3-|-1|
=>-16+x=3-1
=>x=3-1+16=18
4)-(-3-x+8)-(-3+5)=|5-8|
=>-(5-x)-2=|-3|
=>-5+x-2=3
=>x=3+5+2=10
5)-|5-8|-(4-x+5)=4+|3-9|
=>-|-3|-(9-x)=4+|-6|
=>-3-9+x=4+6
=>x=4+6+3+9=22
Bài 4: Tìm các số nguyên x biết
1) |x + 2| = 4
2) 3 – |2x + 1| = (-5)
3) 12 + |3 – x| = 9
4) |x + 9| = 12 + (-9) + 2
5) 2(4x – 8) – 7(3 + x) = |-4|(3 – 2)
6) 8(x – |-7|) – 6(x – 2) = |-8|.6 – 50
7) -7(5 – x) – 2(x – 10) = 15
8) 4(x – 1) – 3(x – 2) = -|-5|
1) |x + 2| = 4
\(\Leftrightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=-6\end{cases}}\)
2) 3 – |2x + 1| = (-5)
\(\Leftrightarrow\left|2x+1\right|=8\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}\)
3) 12 + |3 – x| = 9
\(\Leftrightarrow\left|3-x\right|=-3\)(vô lí)
=>\(x=\varnothing\)
1) I x+2 I=4
\(\Rightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-6\end{cases}}}\)
2) \(3-|2x+1|=-5\)
\(\Leftrightarrow|2x+1|=8\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-9\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}}\)
3) \(12+|3-x|=9\)
\(\Leftrightarrow|3-x|=-3\)(vô lí vì I 3-x I \(\ge\)0)
1; |\(x\) + 2| = 4
\(\left[{}\begin{matrix}x+2=-4\\x+2=4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-4-2\\x=4-2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-6\\x=2\end{matrix}\right.\)
Vậy \(x\) \(\in\) {- 6; 2}
tìm x thuộc Z biết:
1) 2(4x-8)-7(3+x)=[-4](3-2)
2) 12(x-4)+6(x-2)-16(x+3)=7[-4]
3) 4(x-5)-7(5-x)+10(5-x)=-3
4) -3[x+5]=15(-3)+7(-3)
5) 4[x-7]-3(-5)=-2[x-7]-10
1) <=> 8x-16-21-7x=-4
<=> x-37=-4
<=> x=33
2) <=> 12x-48+6x-12-16x-48=-28
<=> 2x-108=-28
<=> 2x = 80
<=> x = 40
3)<=> 4x-20-35+7x+50-10x=-3
<=> x-5=-3
<=> x=2
4) <=> -3x-15=-45-21
<=> 51=3x
<=> 17=x
5) 4x-28+15=-2x+14-10
<=> 6x-13=4
<=> 6x=17
<=> x = \(\frac{17}{6}\)
Chúc bạn học tốt
Bài toán 3 : Tìm x, biết.
a. 2(x – 5) – 3(x + 7) = 14 b. 5(x – 6) – 2(x + 3) = 12
c. 3(x – 4) – (8 – x) = 12 d. -7(3x – 5) + 2(7x – 14) = 28
e. 5(3 – 2x) + 5(x – 4) = 6 – 4x f. -5(2 – x) + 4(x – 3) = 10x – 15
g. 2(4x – 8) – 7(3 + x) = |-4|(3 – 2) h. 8(x – |-7|) – 6(x – 2) = |-8|.6 – 50
k. -7(5 – x) – 2(x – 10) = 15 l. 4(x – 1) – 3(x – 2) = -|-5|
m. -4(x + 1) + 89x – 3) = 24 n. 5(x – 30 – 2(x + 6) = 9
o. -3(x – 5) + 6(x + 2) = 9 p. 7(x – 9) – 5(6 – x) = – 6 + 11x
q. 10(x – 7) – 8(x + 5) = 6.(-5) + 24
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
d, \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\Leftrightarrow-7x=21\Leftrightarrow x=-3\)
e, \(5\left(3-2x\right)+5\left(x-4\right)=6-4x\)
\(\Leftrightarrow15-6x+5x-20=6-4x\Leftrightarrow-5-x=6-4x\)
\(\Leftrightarrow-11+3x=0\Leftrightarrow x=\frac{11}{3}\)
f, \(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
\(\Leftrightarrow-10+5x+4x-12=10x-15\Leftrightarrow-22+9x=10x-15\)
\(\Leftrightarrow-7-x=0\Leftrightarrow x=-7\)
tìm x
a) -1/8 = 3/x b) x/3 = 3/x c)3/4 . x = 1 và 1/2
d) x - 3/10 = 7/15 : 3/5 e) -4/7 - x = -8/3 . 3/7
f) 4/7 . x - 2/3 = 1/5 g) 2/3 + 1/3 : 3 x = 1/5
h) 2/9 - 7/8 x=1/3 j) (2 và 4/5 x - 50) : 2/3 = 51
\(a,\dfrac{-1}{8}=\dfrac{3}{x}\\ \dfrac{3}{-24}=\dfrac{3}{x}\\ x=-24\\ b,\dfrac{x}{3}=\dfrac{3}{x}\\ x.x=3.3\\ x^2=9\\ x=\pm3\\ c,\dfrac{3}{4}.x=1\dfrac{1}{2}\\ \dfrac{3}{4}.x=\dfrac{3}{2}\\ x=\dfrac{3}{2}:\dfrac{3}{4}\\ x=2\\ d,x-\dfrac{3}{10}=\dfrac{7}{15}:\dfrac{3}{5}\\ x-\dfrac{3}{10}=\dfrac{7}{9}\\ x=\dfrac{7}{9}+\dfrac{3}{10}\\ x=\dfrac{97}{90}\\ e,\dfrac{-4}{7}-x=\dfrac{-8}{3}.\dfrac{3}{7}\\ \dfrac{-4}{7}-x=\dfrac{-8}{7}\\ x=\dfrac{-4}{7}+\dfrac{8}{7}\\ x=\dfrac{4}{7}\\ \)
f: =>x*4/7=1/5+2/3=3/15+10/15=13/15
=>x=91/60
g: =>1/3:3x=1/5-2/3=-7/15
=>3x=-5/7
=>x=-5/21
h: =>7/8x=-1/9
=>x=-1/9:7/8=-1/9*8/7=-8/63
j: =>(2,8x-50)=34
=>2,8x=84
=>x=30
tìm X biết :
a.2/3 : 5/7 : x/9 = 2/7 : 3/5 :10/9
b.3/5 : 7/x : 3/4 = 12/105
c.x : 1/2 = 2/3 x 4/5 x 3/4 x 15/8
a, \(\frac{2}{3}:\frac{5}{7}:\frac{x}{9}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\Leftrightarrow\frac{2\times7\times9}{3\times5\times x}=\frac{2\times5\times9}{7\times3\times10}\Leftrightarrow\frac{42}{5\times x}=\frac{3}{7}\Leftrightarrow294=15\times x\Leftrightarrow x=19,6\)
Các phần sau tương tự.
Dùng phương pháp nhân chéo và kiểm tra trình độ tính toán, khả năng rút gọn.
Thay kết quả vào x để kiểm tra lại bài.
Tìm x biết
a, 3/3 - ( x - 7/3 ) = [ -3/4 - 9/8]
b, 3 - ( 8/3 - x + 5/4 ) = 1- [ 7/6 - 5/12 ]
a) \(\frac{3}{3}-\left(x-\frac{7}{3}\right)=-\frac{3}{4}-\frac{9}{8}\)
\(1-\left(x-\frac{7}{3}\right)=-\frac{15}{8}\)
\(x-\frac{7}{3}=1--\frac{15}{8}\)
\(x-\frac{7}{3}=\frac{23}{8}\)
\(x=\frac{23}{8}+\frac{7}{3}=\frac{125}{24}\)
b) \(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=1-\left(\frac{7}{6}-\frac{5}{12}\right)\)
\(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=\frac{1}{4}\)
\(\frac{8}{3}-x+\frac{5}{4}=1-\frac{1}{4}\)
\(-x=1-\frac{1}{4}-\frac{8}{3}-\frac{5}{4}\)
\(-x=-\frac{19}{6}\)
\(\Rightarrow x=\frac{19}{6}\)
a) \(\frac{3}{3}-\left(x-\frac{7}{3}\right)=\left(\frac{-3}{4}-\frac{9}{8}\right)\)
\(1-x+\frac{7}{3}=\frac{-15}{8}\)
\(1+\frac{7}{3}-x=\frac{-15}{8}\)
\(\frac{10}{3}-x=\frac{-15}{8}\)
\(x=\frac{10}{3}-\left(\frac{-15}{8}\right)\)
\(x=\frac{125}{24}\)
b) \(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=1-\left(\frac{7}{6}-\frac{5}{12}\right)\)
\(3-\frac{8}{3}+x-\frac{5}{4}=1-\frac{3}{4}\)
\(\left(3-\frac{8}{3}-\frac{5}{4}\right)+x=\frac{1}{4}\)
\(\frac{-11}{12}+x=\frac{1}{4}\)
\(x=\frac{1}{4}-\left(\frac{-11}{12}\right)\)
\(x=\frac{-7}{6}\)
Tìm x:
a)5/8/17:x+(-4/17):x+3/1/7:17/1/3=4/11
b)|x|-5/3/7|x|-3/4=2|x|+(-8/7)
Tìm x,biết :
a)4/7× x - 2/3=1/5
b)7/9-7/8× x =1/3
c)4/5+5/7: x=1
d)2/3×(1/4+3/4 : x)=5/6
a) 4/7 x X = 1/5 + 2/3
=> 4/7 x X = 3/15 + 10/15
=> 4/7 x X = 13/15
=> X = 13/15 : 4/7
=> X = 13/15 x 4/7 = 52/105
a ) 4 / 7 x X = 1 / 5 + 2 / 3
= > 4 / 7 x X = 3 / 1 5 + 1 0 / 1 5
= > 4 / 7 x X = 1 3 / 1 5
= > X = 1 3 / 1 5 : 4 / 7
= > X = 1 3 / 1 5 x 4 / 7
= 5 2 / 1 0 5
nhầm kết luận là x= 13/15 : 4/7 => x=13/15 x 7/4 => x= 91/60