5^5/5^x=5^18
2006 x ( 43 x 10 – 2 x 43 x 5) + 100
64 x 4 + 18 x 4 + 9 x 8
44 x 5 + 18 x 10 + 20 x 5
3 x 4 + 4 x 6 + 9 x 2 + 18
2 x 5 + 5 x 7 + 9 x 3
15 : 5 + 27 : 5 + 8 : 5
99 : 5 – 26 : 5 – 14 : 5
Giair hộ mình với nhé! Nêu lời giải chi tiết nhé !
2006 x [43 x 10 - 2 x 43 x 5] +100
=2006x0+100
=0+100
=100
64x4+18x4+9x8
=256+72+72
=400
44x5+18x10+20x5
=220+180+100
=500
3x4+4x6+9x2+18
=12+24+18+18
=72
2x5+5x7+9x3
=10+35+27
=72
15:5+27:5+8:5
=[15+27+8]:5
=10
99:5-26:5-14:5
=[99-26-14]:5
=11.8
Câu cuối sai đề nha mà nếu đề như vậy thì đó là toán lớp 6
Cảm ơn bạn I LOVE YOU rất nhiều mình đang vội ,cảm ơn bạn nhé!!!
Trả lời:
\(2006\times\left(43\times10-2\times43\times5\right)+100\)
\(=2006\times\left(43\times10-43\times10\right)+100\)
\(=2006\times0+100\)
\(=0+100\)
\(=100\)
\(44\times5+18\times10+20\times5\)
\(=44\times5+18\times2\times5+20\times5\)
\(=44\times5+36\times5+20\times5\)
\(=5\times\left(44+36+20\right)\)
\(=5\times100\)
\(=500\)
\(3\times4+4\times6+9\times2+18\)
\(=12+24+18+18\)
\(=12+24+36\)
\(=72\)
\(2\times5+5\times7+9\times3\)
\(=5\times\left(2+7\right)+9\times3\)
\(=5\times9+9\times3\)
\(=9\times\left(5+3\right)\)
\(=9\times8\)
\(=72\)
\(15\div5+27\div5+8\div5\)
\(=\left(15+27+8\right)\div5\)
\(=50\div5\)
\(=10\)
\(99\div5-26\div5-14\div5\)
\(=\left(99-26-14\right)\div5\)
\(=59\div5\)
\(=\frac{59}{5}\)
Đúng ghi Đ sai ghi S:
a,5 x 7/18 + 2/9 = 5 x 11/18=55/18
b,3/4 x (2/9+5/6) = 3/4 x 2/9 +3/4 x 5/6=1/6 + 5/8=19/24
5^x*5^x+1*5^x+2=1000..0:2^18 18 chữ số 0
Tìm số nguyên x , biết:
18) 5 / x + 5/ -5 = 5
19) (x - 20) + (x -19) + (x - 18) + ...... + 100 + 101 = 101
5^5/5^x=5^18
5^x*5^x+1*5^x+2<1000...09( có 18 chữ số 0)/2^18
tính bằng cách thuận tiện nhất a, \(\dfrac{5}{13}\)x\(\dfrac{4}{15}\)x13= b, (\(\dfrac{3}{7}\)+\(\dfrac{5}{2}\))x\(\dfrac{7}{5}\)= c, \(\dfrac{1}{5}\)x\(\dfrac{11}{18}\)+\(\dfrac{11}{18}\)x\(\dfrac{3}{5}\)=
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{5\times4\times13}{13\times5\times3}=\dfrac{4}{3}\\ b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\dfrac{3}{7}\times\dfrac{7}{5}+\dfrac{5}{2}\times\dfrac{7}{5}=\dfrac{3}{5}+\dfrac{7}{2}=\dfrac{6}{10}+\dfrac{35}{10}=\dfrac{41}{10}\\ c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
Tìm x,y biết: 5^x . 5^x+1 . 5^x+2 <( hoặc =) 10^18 : 2^18
tim x
5^x*5^(x+1)*5^(x+2) < hoặc = 100....0 (18 số 0 )/ 2^18
Ta có
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=>5^{3x+3}\le5^{18}=>3x+3\le18=>x\le5\)