= 5 x 7 + 5 x 4 + 5 x 8 + 5 x 1 

= 5 x ( 7 + 4 + 8 + 1 )

= 5 x 20 

= 100

5x(7+4+8+1)

=5x20

=100

5 x ( 7 + 8 + 5)

= 5 x 20

= 100

a)3/5x5/3x8/27=1x8/27=8/27

b)7/19x(1/3+2/3)=7/19x1=7/19

\(\frac{3}{5}x\frac{8}{27}x\frac{5}{3}=\frac{3}{3}x\frac{5}{5}x\frac{8}{27}=\frac{8}{27}\)

\(\frac{7}{19}x\frac{1}{3}+\frac{7}{19}x\frac{2}{3}=\frac{7}{19}x\left(\frac{1}{3}+\frac{2}{3}\right)=\frac{7}{19}\)

A)3/5x8/27x5/3

=8/27x(3/5x5/3)

=8/27x1

=8/27

B)7/19x1/3+7/19x2/3

=7/19x(1/3+2/3)

=7/19x1

=7/19

sai thì thông cảm cho cho mk nhé, có hứng thì kb luôn

\(\frac{9\cdot8\cdot33}{56\cdot54\cdot11}=\frac{9\cdot8\cdot3\cdot11}{8\cdot7\cdot9\cdot3\cdot2\cdot11}=\frac{1}{7\cdot2}=\frac{1}{14}\)

\(\frac{8\cdot15+16\cdot4-8\cdot21}{16\cdot5-8\cdot9}=\frac{8\cdot15+8\cdot2\cdot4-8\cdot21}{2\cdot8\cdot5-8\cdot9}=\frac{8\cdot15+8\cdot8-8\cdot21}{8\cdot10-8\cdot9}=\frac{8\left(15+8-21\right)}{8\left(10-9\right)}=\frac{8\cdot2}{8\cdot1}=\frac{2}{1}=2\)

b ) Đặt \(A=\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{101.103}\)

\(\Rightarrow A=\frac{5}{2}\left(\frac{5}{1}-\frac{5}{3}+\frac{5}{3}-\frac{5}{5}+....+\frac{5}{101}-\frac{5}{103}\right)\)

\(\Rightarrow A=\frac{5}{2}\left(5-\frac{5}{103}\right)\)

`x : 5/2 = 7/3`

`=> x= 7/3 xx 5/2`

`=>x= 35/6`

__

`23,7 xx 49 +23,7 xx 51`

`= 23,7 xx (49+51)`

`= 23,7 xx 100`

`=2370`

Lời giải:
a. 

$x=\frac{7}{3}\times \frac{5}{2}=\frac{35}{6}$

b.

$23,7\times 49+23,7\times 51=23,7\times (49+51)=23,7\times 100=2370$

x: 5/2=7/3`

`=> x = 7/3 xx 5/2`

`=> x=35/6`

Vậy `x = 35/6`

`23,7 xx 49 + 23,7 xx 51`

` =23,7 xx(49+51)`

`= 23,7 xx 100`

`=2370`

\(A=\frac{3-1}{1.3}+\frac{5-3}{3.5}+...+\frac{101-99}{99.101}\)

\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{101}=\frac{100}{101}\)