Giai phuong trình: x^4 - 25x^2 + 60x - 36 = 0
Tính x: x4-25x2+60x-36=0
GIẢI:\(x^4-25x^2+60x-36=0\)
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Giải
\(x^4-25x^2+60x-36\)
\(x^4-25x^2+60x-36=0\)
\(\Leftrightarrow x^4+5x^3-6x^2-5x^3-25x^2+30x+6x^2+30x-36=0\)
\(\Leftrightarrow x^2\left(x^2+5x-6\right)-5x\left(x^2+5x-6\right)+6\left(x^2+5x-6\right)=0\)
\(\Leftrightarrow\left(x^2-5x+6\right)\left(x^2+5x-6\right)=0\)
\(\Leftrightarrow\left(x^2-2x-3x+6\right)\left(x^2-x+6x-6\right)=0\)
\(\Leftrightarrow\left[x\left(x-2\right)-3\left(x-2\right)\right]\left[x\left(x-1\right)+6\left(x-1\right)\right]=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-2\right)\left(x-1\right)\left(x+6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-3=0\\x-2=0\\x-1=0\\x+6=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=3\\x=2\\x=1\\x=-6\end{matrix}\right.\)
Giai phuong trinh
\(25\sqrt{25x+4}+4=x^2\)
giai phuong trinh:\(x^4-3x^3+4x^2-3x+1=0\)
\(65x^4+25x^3+12x^2-25x+6=0\)
\(x^5+2x^4+3x^3+3x^2+2x+1=0\)
Giai phuong trinh x^3 + x^2 - 36 = 0
Giai phuong trinh : x^3 + x^2 - 36 = 0
Cac ban giup mk di mk dang can ngay bay gio .
Giai phuong trinh
a/ \(\sqrt{4x^2+4x+1}\) - \(\sqrt{25x^2+10x+1}\) = 0
b/ \(\sqrt{x^4-16x^2+64}=\sqrt{25x^2+10x+1}\)
c/ \(\sqrt{x^2-25}-\sqrt{x-5}=0\)
d/ \(\sqrt{4x^2-9}-2\sqrt{2x+3}=0\)
e/ \(\sqrt{x-2}-3\sqrt{x^2-4}=0\)
a.
\(\sqrt{4x^2+4x+1}-\sqrt{25x^2+10x+1}=0\)
\(\Leftrightarrow\sqrt{\left(2x+1\right)^2}-\sqrt{\left(5x+1\right)^2}=0\)
\(\Leftrightarrow2x+1-\left(5x+1\right)=0\)
\(\Leftrightarrow-3x=0\Leftrightarrow x=0\)
b.
\(\sqrt{x^4-16x^2+64}=\sqrt{25x^2+10x+1}\)
\(\Leftrightarrow\sqrt{\left(x^2-8\right)^2}=\sqrt{\left(5x+1\right)^2}\)
\(\Leftrightarrow x^2-8=5x+1\)
\(\Leftrightarrow x^2-5x+\dfrac{25}{4}=\dfrac{61}{4}\)
\(\Leftrightarrow\left(x-\dfrac{5}{2}\right)^2=\dfrac{61}{4}\)
............................
tương tự ..
c: \(\Leftrightarrow\sqrt{x-5}\left(\sqrt{x+5}-1\right)=0\)
=>x-5=0 hoặc x+5=1
=>x=-4 hoặc x=5
d: \(\Leftrightarrow\sqrt{2x+3}\left(\sqrt{2x-3}-2\right)=0\)
=>2x+3=0 hoặc 2x-3=4
=>x=7/2 hoặc x=-3/2
e: \(\Leftrightarrow\sqrt{x-2}\left(1-3\sqrt{x+2}\right)=0\)
=>x-2=0 hoặc 3 căn x+2=1
=>x=2 hoặc x+2=1/9
=>x=-17/9 hoặc x=2
số nghiệm của phương trình x4 -10x3 +25x2 -36 = 0 là ?
https://h.vn/hoi-dap/question/238231.html?pos=815256