\(A=\left(2x-1\right)^2-\left(2x+3\right)\left(x-2\right)-2\left(x+2\right)\left(x+5\right)\)

\(=4x^2-4x+1-\left(2x^2-x-6\right)-2\left(x^2+7x+10\right)\)

\(=-17x-13\)

Thay x=-3 vào A,ta được 

\(A=\left(-17\right)\cdot\left(-3\right)-13\)

\(=38\)

Vậy A=38 tại x=-3

A = ( 2x - 1 )² - ( 2x + 3 )( x- 2) - 2( x + 2 )( x + 5 )

   = 4x² - 4x + 1 - 2x² - 4x + 3x - 6 - 2x - 4 + x + 5

   = 2x² - 6x - 4

Thay x = -3 vào biểu thức ta được:

    2 . ( -3 )² - 6 . ( -3 ) - 4

= 2 . 9 - 6 . ( -3 ) -4

= 18 + 18 - 4

= 32

Hk tốt

A= (2x-1)²-(2x+3)(x-2)-2(x+2)(x+5)

A= 4x²-4x+1-(2x²-x-6)-2(x²+7x+10)

A=4x²-4x+1-2x²+x+6-2x²-14x-20

A= -17x-13

Thay x= -3, ta có:

A= -17.3-13=-51-13=-64

chịu

A= ( 2x-1) - (2x+3)(x-2) - 2(x+2)(x+5)

  = (2x-1) - (2x^2 - 4x+3x-6) - (2x-4)(x+5)

  = (2x-1) - (2x^2-4x+3x-6) - (2x^2+10x-4x-20)

  = 2x-1-2x^2+4x-3x+6-2x^2-10x+4x+20

  = -3x-4x^2+25

  = -4x^2-3x+25

Với x=-3 ta có:

(-4).(-3)^2-3.(-3)+25

=-36+9+25

=-2

\(A=\left(2x-1\right)^2-\left(2x+3\right).\left(x-2\right)-2.\left(x+2\right).\left(x+5\right)\)

\(=\left(2x-1\right)^2-\left(2x+3\right).\left(x-2\right)-2.\left(x+2\right).\left(x+5\right)\)

\(=4x^2-4x+1-2x^2-3x+4x+6-2x^2-4x-10x-20\)

\(=4x^2-2x^2-2x^2-4x-3x+4x-4x-10x+1+6-20\)

\(=0-17x-13\)

\(=-17x-13\)

Ta thay \(x=-3\) vào

\(A=-17.\left(-3\right)-13=38\)

`Answer:`

`a)`

`A=5(x+1)^2-3(x-3)^2-4(x^2-4)`

`=>A=5(x^2+2x+1)-3(x^2-6x+9)-4x^2+16`

`=>A=5x^2+10x+5-3x^2+18x-27-4x^2+16`

`=>A=(5x^2-3x^2-4x^2)+(10x+18x)+(5-27+16)`

`=>A=-2x^2+28x-6`

`b)`

`B=5(x+1)^2-3(x-3)^2-4(x+2)(x-2)`

`=2x(3x+5)-3(3x+5)-2x(x^2-4x+4)-[(2x)^2-3^2]`

`=6x^2+10x-9x-15-2x^3+8x^2-8x-4x^2+9`

`=(6x^2-4x^2+8x^2)-2x^3+(10x-9x-8x)+(-15+9)`

Thay `x=-7` vào ta được:

`B=10(-7)^2-2(-7)^3-7(-7)-6`

`=>B=10.49-2(-343)+49-6`

`=>B=490+686+49-6`

`=>B=1219`

Lời giải:
$H=(x^3-3x^2+3x-1)-(x^3+8)+3(x^2-16)$

$=x^3-3x^2+3x-1-x^3-8+3x^2-48$

$=(x^3-x^3)+(-3x^2+3x^2)+3x+(-1-8-48)$

$=3x-57=3.\frac{-1}{2}-57=\frac{-117}{2}$

mn giúp e sớm đc ko ạ