= 700 nha cái đồ giả mạo gái thành trai

=> 20 x ( 10 + 9 + 11 ) + 10 x ( 2 + 3 + 4 + 1 )

=> 20 x 30 + 10 x 10

=> 600 + 100

=> 700

20x10+20x9+20x11+10x2+10x3+10x4+10x1

=20x(10+9+11)+10x(2+3+4+1)

=20x30+10x10

=600+100

=700

`=7/10xx(3+5+2)`

`=7/10xx10=7`

\(\frac{4^{15}}{7^{30}}=\frac{\left(2^2\right)^{15}}{7^{30}}=\frac{2^{30}}{7^{30}}=\left(\frac{2}{7}\right)^{30}\)

\(\frac{8^{10}.3^{30}}{7^{30}.4^{15}}=\frac{\left(2^3\right)^{10}.3^{30}}{7^{30}.\left(2^2\right)^{15}}=\frac{2^{30}.3^{30}}{7^{30}.2^{30}}=\frac{3^{30}}{7^{30}}=\left(\frac{3}{7}\right)^{30}\)

Vì \(\frac{2}{7}<\frac{3}{7}\Rightarrow\left(\frac{2}{7}\right)^{30}<\left(\frac{3}{7}\right)^{30}\)

Vậy \(\frac{4^{15}}{7^{30}}<\frac{8^{10}.3^{30}}{7^{30}.4^{15}}\).

j: \(\dfrac{10x^3-19x^2-4x+4}{2x+1}\)

\(=\dfrac{10x^3+5x^2-24x^2-12x+8x+4}{2x+1}\)

\(=5x^2-12x+4\)

giup minh cau i,k voi a,minh cam on

30

3

19

280

10+10x2=10+20=30

3+2x0=3+0=3

7+12=19

7x(10+30)=7x40=280

10 + 10x2 = 30

3 + 2x0 = 3

7 + 12 = 19

7x (10+30) = 280

Ca này bó tay rồi, ghi rõ ra đc ko, khó hiểu quá

F(-1)=3*(-1)^4+(-1)^3+10*(-1)^2-7

=3-1+10-7

=5

=>x=-1 ko là nghiệm của 3x^4+x^3+10x^2-7