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Hoàng Hà An
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Bài 1:

 A  = \(\dfrac{1}{1\times3}\) + \(\dfrac{1}{3\times5}\) + \(\dfrac{1}{5\times7}\) +...+ \(\dfrac{1}{2019\times2021}\)

A =   \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{2}{1\times3}\) + \(\dfrac{2}{3\times5}\) + \(\dfrac{2}{5\times7}\)+...+ \(\dfrac{2}{2019\times2021}\))

A = \(\dfrac{1}{2}\) \(\times\)\(\dfrac{1}{1}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{7}\)+...+ \(\dfrac{1}{2019}\) - \(\dfrac{1}{2021}\))

A = \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{1}{1}\) - \(\dfrac{1}{2021}\))

A = \(\dfrac{1010}{2021}\)

Nguyễn Trần Linh Chi
13 tháng 8 2023 lúc 20:55

bạn có sử dụng discord không

Bài 2:

B = \(\dfrac{4}{11\times16}\) + \(\dfrac{4}{16\times21}\)\(\dfrac{4}{21\times26}\)+...+ \(\dfrac{4}{61\times66}\)
B = \(\dfrac{4}{5}\) \(\times\) ( \(\dfrac{5}{11\times16}\)\(\dfrac{5}{16\times21}\) + \(\dfrac{5}{21\times26}\)+...+ \(\dfrac{5}{61\times66}\))

B = \(\dfrac{4}{5}\) \(\times\) ( \(\dfrac{1}{11}\) - \(\dfrac{1}{16}\) + \(\dfrac{1}{16}\) - \(\dfrac{1}{21}\) + \(\dfrac{1}{21}\) - \(\dfrac{1}{26}\)+...+ \(\dfrac{1}{61}\) - \(\dfrac{1}{66}\))

B = \(\dfrac{4}{5}\) \(\times\)\(\dfrac{1}{11}\) - \(\dfrac{1}{66}\))

B = \(\dfrac{4}{5}\) \(\times\)  \(\dfrac{5}{66}\)

B = \(\dfrac{2}{33}\)

Đỗ Nguyễn Quỳnh Anh
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Anh vũ
8 tháng 7 2019 lúc 18:16

E=\(\frac{1}{5}\).(\(\frac{1}{11}-\frac{1}{16}\)+\(\frac{1}{16}-\frac{1}{21}+\frac{1}{21}+\frac{1}{26}+....+\frac{1}{61}-\frac{1}{66}\))

E=\(\frac{1}{5}.\left(\frac{1}{11}-\frac{1}{66}\right)\)=\(\frac{1}{5}.\frac{5}{66}=\frac{1}{66}\)

\(E=\frac{1}{11x16}+\frac{1}{16x21}+\frac{1}{21x26}+...+\frac{1}{61x66}\)

\(E=\frac{1}{5}\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}+\frac{1}{26}+...+\frac{1}{61}-\frac{1}{66}\right)\)

\(E=\frac{1}{5}\left(\frac{1}{11}-\frac{1}{66}\right)\)

\(E=\frac{1}{5}.\frac{5}{66}\)

\(E=\frac{1}{66}\)

Nguyễn Hữu Thế
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Đỗ Lê Tú Linh
22 tháng 5 2015 lúc 10:30

\(C=\frac{1}{11\cdot16}+\frac{1}{16\cdot21}+...+\frac{1}{61\cdot66}=\frac{5}{5}\cdot\left(\frac{1}{11\cdot16}+\frac{1}{16\cdot21}+...+\frac{1}{61\cdot66}\right)\)

\(=\frac{1}{5}\cdot\left(\frac{5}{11\cdot16}+\frac{5}{16\cdot21}+...+\frac{5}{61\cdot66}\right)=\frac{1}{5}\cdot\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\right)\)

\(=\frac{1}{5}\cdot\left[\left(\frac{1}{11}-\frac{1}{66}\right)+\left(\frac{1}{16}-\frac{1}{16}\right)+...+\left(\frac{1}{61}-\frac{1}{61}\right)\right]\)

\(=\frac{1}{5}\cdot\left[\left(\frac{6}{66}-\frac{1}{66}\right)+0+...+0\right]=\frac{1}{5}\cdot\frac{5}{66}=\frac{1\cdot5}{5\cdot66}=\frac{1\cdot1}{1\cdot66}=\frac{1}{66}\)

Vậy \(C=\frac{1}{66}\)

Chúc bạn học tốt!^_^

Quang Nhật
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QuocDat
16 tháng 4 2017 lúc 21:01

\(\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}\)

\(=5^2\left(\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+\frac{1}{16.21}+\frac{1}{21.26}\right)\)

\(=25.\frac{1}{5}\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{21}-\frac{1}{26}\right)\)

\(=5\left(1-\frac{1}{26}\right)\)

\(=5.\frac{25}{26}\)

\(=\frac{125}{26}\)

Quang Nhật
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Nguyễn Phúc Nhi
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QuocDat
23 tháng 4 2017 lúc 10:15

\(S=\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}\)

\(5S=5^2\left(\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+\frac{1}{16.21}+\frac{1}{21.26}\right)\)

\(5S=5^2\left(1-\frac{1}{26}\right)\)

\(\Rightarrow S=5^2:5\left(1-\frac{1}{26}\right)\)

\(S=5\left(1-\frac{1}{26}\right)\)

\(S=5.\frac{25}{26}\)

\(S=\frac{125}{26}\)

TeamHauPro
10 tháng 9 2019 lúc 20:13

A = 3/11x16 + 3/16x21 + 3/21x26 +...+3/61x66

A : 3 . 5 = 5/11x16 + 5/16x21 + 5/21x26 +...+5/61x66

A : 3 . 5 = 1/11 - 1/16 + 1/16 - 1/21 + ......+ 1/61 - 1/66

A : 3 . 5 = 1/11 - 1/66

A : 3 . 5 = 5/66

A = 5/66 . 3 : 5

A = 5/22 : 5

A = 1/22

Chúc bạn hoc tốt vui

Nguyễn Thùy Linh
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Nguyễn Lê Phước Thịnh
26 tháng 7 2023 lúc 18:18

\(=11\left(\dfrac{5}{6\cdot11}+\dfrac{5}{11\cdot16}+\dfrac{5}{16\cdot21}+\dfrac{5}{21\cdot26}+\dfrac{5}{26\cdot31}\right)\)

=11(1/6-1/11+1/11-1/16+1/16-1/21+1/21-1/26+1/26-1/31)

=11*25/186=275/186

Nguyễn Thùy Linh
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Nguyễn Đức Trí
26 tháng 7 2023 lúc 16:47

\(\dfrac{55}{6x11}+\dfrac{55}{11x16}+\dfrac{55}{21x16}+\dfrac{55}{21x26}+\dfrac{55}{31x26}\)

\(=55\left(\dfrac{1}{6x11}+\dfrac{1}{11x16}+\dfrac{1}{21x16}+\dfrac{1}{21x26}+\dfrac{1}{31x26}\right)\)

\(=55\left(\dfrac{1}{5}x\left(\dfrac{1}{6}-\dfrac{1}{11}\right)+\dfrac{1}{5}x\left(\dfrac{1}{11}-\dfrac{1}{16}\right)+\dfrac{1}{5}x\left(\dfrac{1}{16}-\dfrac{1}{21}\right)+\dfrac{1}{5}x\left(\dfrac{1}{21}-\dfrac{1}{26}\right)+\dfrac{1}{5}x\left(\dfrac{1}{26}-\dfrac{1}{31}\right)\right)\)

\(=55x\dfrac{1}{5}x\left(\dfrac{1}{6}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{31}\right)\)

\(=11x\left(\dfrac{1}{6}-\dfrac{1}{31}\right)=11x\left(\dfrac{31-6}{186}\right)=11x\dfrac{25}{186}=\dfrac{275}{186}\)

Trần Đình Thiên
26 tháng 7 2023 lúc 16:42

C=\(\dfrac{55}{6\cdot11}\)+\(\dfrac{55}{11\cdot16}\)+\(\dfrac{55}{16\cdot21}\)+\(\dfrac{55}{21\cdot26}\)+\(\dfrac{55}{26\cdot31}\)

 =\(\dfrac{1}{6}\)-\(\dfrac{1}{11}\)+\(\dfrac{1}{11}\)-\(\dfrac{1}{16}\)+\(\dfrac{1}{16}\)-\(\dfrac{1}{21}\)+\(\dfrac{1}{21}\)-\(\dfrac{1}{26}\)+\(\dfrac{1}{26}\)-\(\dfrac{1}{31}\)

 =\(\dfrac{1}{6}\)-\(\dfrac{1}{31}\)=\(\dfrac{25}{186}\)

Phạm Quang Lộc
26 tháng 7 2023 lúc 17:13

\(C=\dfrac{55}{6\times11}+\dfrac{55}{11\times16}+\dfrac{55}{16\times21}+\dfrac{55}{21\times26}+\dfrac{55}{26\times31}\)

\(\dfrac{1}{11}C=\dfrac{5}{6\times11}+\dfrac{5}{11\times16}+\dfrac{5}{16\times21}+\dfrac{5}{21\times26}+\dfrac{5}{26\times31}\)

\(\dfrac{1}{11}C=\dfrac{1}{6}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{31}\)

\(\dfrac{1}{11}C=\dfrac{1}{6}-\dfrac{1}{31}=\dfrac{25}{186}\)

\(C=\dfrac{25}{186}:\dfrac{1}{11}=\dfrac{275}{186}\)