tìm x: 64.x+225=700-75-36.x
tìm x: 64.x+225=700-75-36.x
64 x X + 225 + = 700 - 75 -36 x X
64×x+225=700-75-36×x
64×x+36×x=700-75-36
64×x+36×x=400
x×(64+36)=400
x×100=400
x=400:100
x=4
vậy x=4
1.Tìm y
a) y3 + 3y = 12 x 11
b) 64 x y + 225 = 700 - 75 - 36 x y
2.Tính
a)\(\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}\)
b) A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
bài 2
a] = 3 x \(\frac{4343}{7171}\)= \(\frac{17372}{7171}\)= \(\frac{172}{71}\)
b] = \(\frac{1}{33}\)x \(\frac{44}{7}\)= \(\frac{1}{3}\)x \(\frac{4}{7}\)=\(\frac{4}{21}\)
bài 1
a] y là 9
b] <=> 64y + 36y = 700 - 75 - 225
<=> 100y = 400
<=> y = 4
trên lớp cô sửa rồi nên mình giải luôn:
1) Tìm y
a) y3 + 3y = 12 x 11
y3 + 3y = 132
y x 10 + 3 + 3 x 10 + y = 132
( y x 10 + y ) + ( 3 x 10 + 3 ) = 132
11 x y + 33 = 132
11 x y = 132 - 33
11 x y = 99
y = 99 : 11
y = 9
b) 64 x y + 225 = 700 - 75 - 36 x y
64 x y + 225 = 625 - 36 x y
64 x y + 36 x y = 625 -225
64 x y + 36 x y = 400
( 64 + 36 ) x y = 400
100 x y = 400
y = 400 : 100
y = 4
2) Tính
a) \(\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}\)
\(=\frac{4343}{7171}\times4\)
\(=\frac{43}{71}\times4\)
\(=\frac{172}{71}\)
b) A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
Ta có:
\(\frac{3333}{2020}=\frac{3333:101}{2020:101}=\frac{33}{20}\)
\(\frac{333333}{303030}=\frac{333333:10101}{303030:10101}=\frac{33}{30}\)
\(\frac{33333333}{42424242}=\frac{33333333:1010101}{42424242:1010101}=\frac{33}{42}\)
A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
A = \(\frac{1}{33}\times33\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
A = 1 x \(\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
A = 1 x \(\left(\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}\right)\)
A = 1 x \(\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
A = 1 x \(\left(\frac{1}{3}-\frac{1}{7}\right)\)
A = 1 x \(\left(\frac{7}{21}-\frac{3}{21}\right)\)
A = 1 x \(\frac{4}{21}\)
A = \(\frac{4}{21}\)
a,
tìm x biết
x+36=98
x*8=56
b,
16+32
39+25
c, tính nhanh
36+69+31+64
12+78+25+75
ai nhanh mình tick
a ) x + 36 =98
x = 98 -36
x = 62
x * 8 = 56
x = 56 : 8
x = 7
b ) 16 + 32 = 48
39 + 25 = 64
c) tính nhanh :
36 + 69 + 31 + 64
= ( 36 + 64 ) + ( 69 + 31 )
= 100 + 100
= 200
12 + 78 + 25 + 75
= (12 + 78 ) + ( 25 + 75 )
= 90 + 100
= 190
a)62 va 7 b)48 va 64 c)200 vs 190
TK CHO MK NHA !
Bài 1:
a) (x-y+4)^2-(2x+3y-1)^2
b) x^6+y^6
c) x^16-1
d) x^36-64
e) 9x^2+90x+225-(x-7)^2
f) 49.(y-4)^2-9y^2-36y-36
Giúp mình với -.-
dễ vãi lol ra bn ngu vãi đái
a, \(\left(x-y+4\right)^2-\left(2x+3y-1\right)^2=\left(x-y+4+2x+3y-1\right)\left(x-y+4-2x-3y+1\right)\)
\(=\left(3x+2y+3\right)\left(-x-4y+5\right)\)
b, \(x^6+y^6=\left(x^2\right)^3+\left(y^2\right)^3=\left(x^2+y^2\right)\left(x^4-x^2y^2+y^4\right)\)
c, \(x^{16}-1=\left(x^2\right)^8-1=\left[\left(x^2\right)^4\right]^2-1=\left(x^8-1\right)\left(x^8+1\right)\)
Phân tích à :)
a) ( x - y + 4 )2 - ( 2x + 3y - 1 )2
= [ ( x - y + 4 ) - ( 2x + 3y - 1 ) ][ ( x - y + 4 ) + ( 2x + 3y - 1 ) ]
= ( x - y + 4 - 2x - 3y + 1 )( x - y + 4 + 2x + 3y - 1 )
= ( -x - 4y + 5 )( 3x + 2y + 3 )
b) x6 + y6 = ( x2 )3 + ( y2 )3 = ( x2 + y2 )( x4 - x2y2 + y4 )
c) x16 - 1 = ( x8 )2 - 12 = ( x8 - 1 )( x8 + 1 )
= ( x4 - 1 )( x4 + 1 )( x8 + 1 )
= ( x2 - 1 )( x2 + 1 )( x4 + 1 )( x8 + 1 )
= ( x - 1 )( x + 1 )( x2 + 1 )( x4 + 1 )( x8 + 1 )
d) x36 - 64 = ( x18 )2 - 82
= ( x18 - 8 )( x18 + 8 )
= ( x6 - 2 )( x12 + 2x + 4 )( x6 + 2 )( x12 - 2x + 4 )
e) 9x2 + 90x + 225 - ( x - 7 )2
= ( 3x + 15 )2 - ( x - 7 )2
= ( 3x + 15 - x + 7 )( 3x + 15 + x - 7 )
= ( 2x + 22 )( 2x - 8 )
= 2( x + 11 ).2( x - 4 )
= 4( x + 11 )( x - 4 )
f) 49( y - 4 )2 - 9y2 - 36y - 36
= 72( y - 4 )2 - ( 9y2 + 36y + 36 )
= ( 7y - 28 )2 - ( 3y + 6 )2
= ( 7y - 28 - 3y - 6 )( 7y - 28 + 3y + 6 )
= ( 4y - 34 )( 10y - 22 )
= 2( 2y - 17 ).2( 5y - 11 )
= 4( 2y - 17 )( 5y - 11 )
1/ Tính nhanh
a/ 364 + 225 + 436 b/ 125 x 14 x 25 x8 x4
c/ 36 x 49 x 64 x 49
a)364+225+436=(364+436)+225=800+225=1025
b)125x14x25x8x4=(125x8)x(25x4)x14=1000x100x14=100000x14=1400000
câu c bạn ra đề sai rồi để mk sửa lại rồi làm luôn.
sửa c) 36x49+64x49=(36+64)x49=100x49=4900
tk nha
\(364+225+436\)
\(=\left(364+436\right)+225\)
\(=800+225\)
\(=1025\)
a)(364+436)+225
=800+225
=1025
b)(125x8)x(25x4)x14
=1000x100x4
=400000
c)(49x64)x(36x49)
=3136+1764
=4900
Tính bằng cách hợp lý nhất
a, 2 x 26 x 5 b, 4 x 37 x 25 c, 25 x 5 x 4 x 27 x 2
d, 28 x 64 + 28 x 36 e, 769 x 85 - 769 x 75 f, 56 x 37 + 56 x 63
A, 2 x 26 x 5 =( 5 x 2) x 26
10 x 26
=260
b,4 x 37 x 25 =( 4 x 25) x 26
= 100 x 26
= 3700
c, 25 x 5 x 4 x 27 x 2 =( 25 x 4 ) x ( 2x 5) x 27
= 100 x 10 x 27
= 1000x 27
=27000
d,28 x 64 + 28 x 36 = 28 x ( 64 + 36 )
= 28 x 100
=2800
e, 769 x 85 - 769 x 75 = 769 x ( 85 - 75 )
=769 x 10
=7690
f, 56 x 37 + 56 x 63 = 56 x ( 37 + 63 )
= 56 x 100
=5600
a. = 26 x (2 x 5)
= 26 x 10 =260
b.=( 25x4) x37
=100 x37=3700
c.=(25x4) x(5x2) x27
=100 x10 x27
= 27000
d.=28 x( 64+36)
=28 x100
= 2800
e.=769 x( 85-75)
=769 x10 =7690
f. =56 x(37 +63)
=56 x100
= 5600
(2.x-8)-64=36 tìm x :<
Tìm x , biết :
a, ( 2x + 1 )^4 = 225
b, (3x - 1 )^2 = 64
a, \(\left(2x+1\right)^4=225\)
đề bài sai
bởi vì ko có số nào mà ^4 lên đc kết quả là 225
b, \(\left(3x-1\right)^2=64\)
Ta có : \(8^2=64\)
Vậy suy ra : 3x - 1 = 8
3x = 8 + 1
3x = 9
x = 9 : 3
x = 3
b) (3x - 1)2 = 64
(3x - 1)2 = 82
=> (3x - 1) = 8
=> x = 3