1) \(5-\left(1+\dfrac{1}{3}\right):\left(1-\dfrac{1}{3}\right)\)

\(=5-\dfrac{4}{3}:\dfrac{2}{3}\)

\(=5-\dfrac{4}{3}\cdot\dfrac{3}{2}\)

\(=5-\dfrac{4}{2}\)

\(=5-2\)

\(=3\)

b) \(\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)-\left(1-\dfrac{5}{4}\right)+2022-\dfrac{2}{3}\)

\(=1+\dfrac{2}{3}-\dfrac{5}{4}-1+\dfrac{5}{4}++2022-\dfrac{2}{3}\)

\(=\left(1-1\right)+\left(\dfrac{2}{3}-\dfrac{2}{3}\right)+\left(-\dfrac{5}{4}+\dfrac{5}{4}\right)+2022\)

\(=0+0+0+2022\)

\(=2022\)

2) \(0,7^2\cdot x=0,49^2\)

\(\Rightarrow x=\dfrac{0,49^2}{0,7^2}\)

\(\Rightarrow x=\left(\dfrac{0,49}{0,7}\right)^2\)

\(\Rightarrow x=\left(0,7\right)^2\)

\(\Rightarrow x=0,49\)

b) \(x:\left(-0,5\right)^3=\left(0,5\right)^2\)

\(\Rightarrow x=\left(0,5\right)^2\cdot\left(-0,5\right)^3\)

\(\Rightarrow x=\left(-0,5\right)^5\)

\(\Rightarrow x=-\dfrac{1}{32}\)

2:

a: =>x*0,49=0,49^2

=>x=0,49

b: =>x=(0,5)^2*(-1)*(0,5)^3=-(0,5)^5

a) \(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

 0,5 x + 0,6 ( x - 2 ) = 3

0,5 x + 0.6 x - 1,2 = 3

1,1 x = 4,2

x = \(\frac{42}{11}\)

Kết luận: 

b) \(\frac{1}{3}x-0,5x=0,75\)

\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(-\frac{1}{6}x=\frac{3}{4}\)

\(x=-\frac{9}{2}\)

Kết luận: 

c) \(\frac{3}{-2}x-0,5x=75\%\)

-1,5x - 0,5x = 0,75 

-2x = 0,75 

x = -0,375

Kết luận: 

d) \(-\frac{2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

-0,4 x + 0,25 = 0,75 - 0,75 x 

-0,4 x + 0,75 x = 0,75 - 0,25

0,35 x = 0,5 

x = \(\frac{10}{7}\)

Kết luận: 

\(a,\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

\(\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)

\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)

\(\frac{11}{10}x-\frac{6}{5}=3\)

\(\frac{11}{10}x=\frac{21}{5}\)

\(x=\frac{42}{11}\)

\(b,\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(\left(\frac{1}{3}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(\frac{-1}{6}x=\frac{3}{4}\)

\(x=\frac{-9}{2}\)

\(c,\frac{3}{-2}x-\frac{1}{2}x=75\%\)

\(\left(\frac{3}{-2}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(-2x=\frac{3}{4}\)

\(x=\frac{-3}{8}\)

\(\frac{-2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

\(\frac{-2}{5}x+\frac{3}{4}x=\frac{3}{4}-\frac{1}{4}\)

\(\left(\frac{-2}{5}+\frac{3}{4}\right)x=\frac{1}{2}\)

\(\frac{7}{20}x=\frac{1}{2}\)

\(x=\frac{10}{7}\)

a. |x-1/5|=|-5/2|-|1/4-2/3|

=> |x-1/5|=5/2-5/12

=> |x-1/5|=25/12

+) x-1/5=25/12

=> x=137/60

+) x-1/5=-25/12

=> x=-113/60

Vậy x \(\in\){-113/60 ; 137/60}

b. (x-0,5).(x²-1,96)=0

+) x-0,5=0

=> x=0,5

+) x²-1,96=0

=> x²=1,96

=> x²=(7/5)²=(-7/5)²

=> x \(\in\left\{-\frac{7}{5};\frac{7}{5}\right\}\)

Vậy \(x\in\left\{-\frac{7}{5};0,5;\frac{7}{5}\right\}\).

c. 5/6 : x = 20 : 3

=> 5/6 : x = 20/3

=> x = 5/6 : 20/3

=> x=1/8

Vậy x=1/8.

Minh Hiền làm đúng rồi tick cho bạn ý đi các bạn ơi ! ( mình ko tick được vì hết lượt rồi )

a/|x|-2,5=27,5

=>|x|=27,5+2,5=30

=>x=30 hoặc x=-30

b/\(\dfrac{3}{4}+\dfrac{2}{5}.x=\dfrac{29}{60}\)

=>\(\dfrac{2}{5}.x\)=\(\dfrac{29}{60}-\dfrac{3}{4}\)=\(\dfrac{-4}{15}\)

=>x=\(\dfrac{-4}{15}:\dfrac{2}{5}\)=\(\dfrac{-2}{3}\)

c/(x-1)\(^5\)=-32

=>x-1=-2 vì (-2)\(^5\)=-32

=>x=-2+1=-1

d/\(\dfrac{4}{5}.x+0,5=4.5\)

=>\(\dfrac{4}{5}.x+0,5=20\)

=>\(\dfrac{4}{5}.x=20-0,5=19,5\)

=>\(x=19,5:\dfrac{4}{5}\)=\(\dfrac{195}{8}\)

1/3 - 5/6 ( x + 1 ) = 0,5

               1/3 - 5/6 ( x + 1 ) = 1/2

                       5/6 ( x + 1 ) = 1/3 - 1/2

                       5/6 ( x + 1 ) = -1/6

                               x + 1    = -1/6 : 5/6

                               x +1     =  -1/5

                              x           =  -1/5 - 1

                             x            =   -6/5

\(\frac{1}{3}-\frac{5}{6}.\left(x+1\right)=0.5\)

\(\frac{5}{6}.\left(x+1\right)=\frac{1}{3}-0.5\)

\(\frac{5}{6}.\left(x+1\right)=\frac{-1}{6}\)

\(x+1=\frac{-1}{6}:\frac{5}{6}\)

\(x+1=\frac{-1}{5}\)

\(x=\frac{-1}{5}-1\)

\(x=\frac{-6}{5}\)

Vậy \(x=\frac{-6}{5}\)

CHÚC BẠN HỌC TỐT

\(a,\frac{-2}{3}\div\left(\frac{1}{2}-3x\right)=\frac{5}{3}\)

\(\frac{1}{2}-3x=\frac{-2}{3}\div\frac{5}{3}\)

\(\frac{1}{2}-3x=\frac{-2}{5}\)

\(3x=\frac{1}{2}-\frac{-2}{5}\)

\(3x=\frac{9}{10}\)

\(x=\frac{9}{10}\div3=\frac{3}{10}\)

\(b,\frac{1}{7}\left|x\right|-\frac{4}{5}=\frac{1}{5}\)

\(\frac{1}{7}\left|x\right|=\frac{1}{5}+\frac{4}{5}=1\)

\(\left|x\right|=1\div\frac{1}{7}=7\)

\(\Leftrightarrow x=\pm7\)

-2/3:(1/2-3x)=5/3

(1/2-3x)=5/3.-3/2

(1/2-3x)=-5/2

3x=-5/2+1/2

3x=-3/2

x=-3/2:3/1

x=-3/2.1/3

x=-1/2

`x+x:0,5+x:10=3,162`

`x+x xx2+x xx0,1=3,162`

`x xx(1+2+0,1)=3,162`

`x xx3,1=3,162`

`x=3,162:3,1`

`x=1,02`

_____________________________________

`2/5xx x+x xx1/5=2/7`

`x xx(2/5+1/5)=2/7`

`x xx3/5=2/7`

`x=2/7:3/5`

`x=10/21`