giaỉ phương trình
a)(159-x)/141+(157-x)/143+(155-x)/145+(153-x)/147+(151-x)/149=-5
b)(x-5)/2010+(x-15)/2000+(x-25)/1990=x-2010/5 +(x-2000)?15 +(x-1999)/25
giúp mình với mình cần GẤP !!!!!
tính nhanh A = 165 - 163 + 161 - 159 + 157 - 155 + 153 - 151 + 149 - 147 + 145 - 143 + 141 - 139 + 137
x+143/157+x+146/154=x+149/151+x+152/148 Các bạn giúp mình với!!
\(\frac{x+143}{157}+\frac{x+146}{154}=\frac{x+149}{151}+\frac{x+152}{148}\)
\(\Leftrightarrow\frac{x+143}{157}+1+\frac{x+146}{154}+1=\frac{x+149}{151}+1+\frac{x+152}{148}+1\)
\(\Leftrightarrow\frac{x+300}{157}+\frac{x+300}{154}=\frac{x+300}{151}+\frac{x+300}{148}\)
\(\Leftrightarrow\left(x+300\right)\left(\frac{1}{157}+\frac{1}{154}-\frac{1}{151}-\frac{1}{148}\right)=0\)
có \(\frac{1}{157}+\frac{1}{154}+\frac{1}{151}+\frac{1}{148}\ne0\)
\(\Leftrightarrow x+300=0\)
\(\Leftrightarrow x=-300\)
mọi người ơi giúp mình câu giải phương trình này với:
\(\dfrac{x-5}{1990}+\dfrac{x-15}{1980}+\dfrac{x-25}{1970}+\dfrac{x-1990}{5}+\dfrac{x-1980}{15}+\dfrac{x-1970}{25}=0\)
\(\Leftrightarrow\left(\dfrac{x-5}{1990}-1\right)+\left(\dfrac{x-15}{1980}-1\right)+\left(\dfrac{x-25}{1970}-1\right)\\ +\left(\dfrac{x-1990}{5}-1\right)+\left(\dfrac{x-1980}{15}-1\right)+\left(\dfrac{x-1970}{25}-1\right)=0\\ \Leftrightarrow\dfrac{x-1995}{1990}+\dfrac{x-1995}{1980}+\dfrac{x-1995}{1970}+\dfrac{x-1995}{5}\\ +\dfrac{n-1995}{15}+\dfrac{n-1995}{25}=0\\ \Rightarrow\left(x-1995\right)\left(\dfrac{1}{1990}+\dfrac{1}{1980}+\dfrac{1}{1970}+\dfrac{1}{5}+\dfrac{1}{15}+\dfrac{1}{25}\right)=0\)
\(\Rightarrow x-1995=0\\ \Rightarrow x=1995\)
1.Tính tổng:
S1= 1+2+3+.....+999
S2= 10+12+14+.....+2010
S3= 21+23+25+.....+1001
S4= 24+25+26+.....+125+126
S5= 1+4+7+......+79
S6= 15+17+19+21+......+151+153+155
S6= 15+25+35+.......+115
2. Tìm x:
a) 5^2x=625
b) 9^x-1=9
c) 2^x : 2^5=1
2 . tìm x :
a ) 52x = 625
52x = 54
=> 2 . x = 4
x = 4 : 2
x = 2
b ) 9x-1 = 9
9x-1 = 91
=> x - 1 = 1
x = 1 + 1
x = 2
c ) 2x : 25 = 1
2x-5 = 1
=> x = 5 , vì 25-5 = 20 = 1
so sánh
2009 x 2011 và 2010 x 2010
2010 x 2007 và 2005 x 2009
2011 x 1998 và 1996 x 2000
2012 x 2000 và 1990 x 2010
2009 . 2001 < 2010 .2010 2010 .2007 > 2005. 2009 2011.1998 > 1996.2000 2012. 2000> 2010. 1990 dấu chấm là dấu nhân cho mik k đi ban mik cm
X - 25/75 + X - 15/85 + X -5/95 + X - 145/15 = 0
giải phương trình hộ mình vs
Ta có: \(\dfrac{x-25}{75}+\dfrac{x-15}{85}+\dfrac{x-5}{95}+\dfrac{x-145}{15}=0\)
\(\Leftrightarrow\dfrac{x-25}{75}-1+\dfrac{x-15}{85}-1+\dfrac{x-5}{95}-1+\dfrac{x-145}{15}+3=0\)
\(\Leftrightarrow\dfrac{x-100}{75}+\dfrac{x-100}{85}+\dfrac{x-100}{95}+\dfrac{x-100}{15}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{75}+\dfrac{1}{85}+\dfrac{1}{95}+\dfrac{1}{15}\right)=0\)
mà \(\dfrac{1}{75}+\dfrac{1}{85}+\dfrac{1}{95}+\dfrac{1}{15}>0\)
nên x-100=0
hay x=100
Vậy: S={100}
⇔ 4X - 3304/323 = 0
⇔ X=3304/323/4
⇔ X=826/323
ko tính kết quả, hãy so sánh
a) A= 67 x 71 và B=65 x 73
b) A= 25 x 58 và B=27 + 58 x 26
c)B= 2000 x 2000 và E= 2010 x 2010
ghi cách ra hộ mình với
Bµi 1 1 37064 – 64 x 82 42966 217 2 320 – 120.5 95,25 5,25 874 12 x 12,53 132 x 9 132 4 48 x 17 48 x 3 5 56 x 27 56 x 35 62 6 45 x 48 – 90 x 24 145 7 754 x 75 – 2262 x 25 4568 8 1050 15 – 350 5 1769 4320 9 – 8640 18 750 10 316 192 384 321 108 11 24 25 26 ….. 124 125 126 12 154 – 153 152 – 151 150 – 149 ….. 4 – 3 2 – 113 37 x 38 – 19 x 74 1000 14 0.48 x 500 – 2.4 x 40 x 2
giải phương trình sau:
a) \(\frac{15-x}{2000}+\frac{14-x}{2001}=\frac{13-x}{2002}+\frac{12-x}{2003}\)
b) \(\frac{x-5}{2010}+\frac{x-4}{2011}=\frac{x-2010}{5}+\frac{x-2011}{4}\)
c) \(\left(x^2+1\right)^2+3x\left(x^2+1\right)+2x^2=0\)
ai bít thì giúp mình với nhé
\(a,\frac{15-x}{2000}+\frac{14-x}{2001}=\frac{13-x}{2002}+\frac{12-x}{2003}\)
\(\Leftrightarrow\frac{15-x}{2000}+1+\frac{14-x}{2001}+1=\frac{13-x}{2002}+1+\frac{12-x}{2003}+1\)
\(\Leftrightarrow\frac{15-x+2000}{2000}+\frac{14-x+2001}{2001}=\frac{13-x+2002}{2002}+\frac{12-x+2003}{2003}\)
\(\Leftrightarrow\frac{2015-x}{2000}+\frac{2015-x}{2001}=\frac{2015}{2002}+\frac{2015-x}{2003}\)
\(\Leftrightarrow\left(2015-x\right)\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)=0\)
mà \(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}>0\)
\(\Leftrightarrow2015-x=0\)
\(\Leftrightarrow x=2015\)
KL : PT có nghiệm \(S=\left\{2015\right\}\)
a)\(\frac{15-x}{2000}+\frac{14-x}{2001}=\frac{13-x}{2002}+\frac{12-x}{2003}\)
\(\Leftrightarrow\frac{15-x}{2000}+1+\frac{14-x}{2001}+1=\frac{13-x}{2002}+1+\frac{12-x}{2003}+1\)
\(\Leftrightarrow\frac{15-x+2000}{2000}+\frac{14-x+2001}{2001}=\frac{13-x+2002}{2002}+\frac{12-x+2003}{2003}\)
\(\Leftrightarrow\frac{2015-x}{2000}+\frac{2015-x}{2001}-\frac{2015-x}{2002}-\frac{2015-x}{2003}=0\)
\(\Leftrightarrow\left(2015-x\right)\left(\frac{1}{2000}+\frac{1}{2001}+\frac{1}{2002}+\frac{1}{2003}\right)=0\)
Vì \(\left(\frac{1}{2000}+\frac{1}{2001}+\frac{1}{2002}+\frac{1}{2003}\right)\ne0\)
\(\Leftrightarrow2015-x=0\)
\(\Leftrightarrow x=2015\)
Vậy x=2015