C=10101.(5/111111 + 5/222222 + 4/3.7.11.13.37 )
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C=10101.(5/111111 + 5/222222 + 4/3.7.11.13.37 ) = ?
\(C=10101.\left(\frac{5}{111111}+\frac{5}{222222}+\frac{4}{3.7.11.13.37}\right)\)
\(C=10101.\frac{23}{222222}\)
\(C=\frac{23}{22}.\)
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10101.(5/111111+5/222222-4/3.7.11.13.37)
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10101.(5/111111 + 5/222222 + 4/3.7.11.13.37)
10101.(\(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\))
111111=3.7.11.13.37
222222=2.3.7.11.13.37
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\(C=10101\left(\frac{5}{111111}+\frac{5}{222222}+\frac{4}{3.7.11.13.37}\right)\)
\(C=10101\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
B= 10101.\(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(B=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)
\(=10101\cdot\dfrac{1}{31746}=\dfrac{7}{22}\)
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\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(A=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)
\(A=10101.\left(\frac{7}{222222}\right)\)
\(A=\frac{70707}{222222}\)
\(A=\frac{7}{22}\)
Vậy A = \(\frac{7}{22}\)
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